Dr. MAS said:
Dr. MAS: I will correct on your thesis. Type your thesis (exactly in the thesis form) and send it to me. I will the expeneditures of your postage.
Erm. Okay... how about I write a short sumary here and you correct me?
Dr. MAS: your discussion is based on "there is no molecules in above 18c. I said, you prove this statement on papers and send it to me endorse with two ph.d doctors in the filed of chemistry. I will pay the postal charges.
Okay, let's see. I guess the sumary can answer both your questions. But after I post this you better 1) show me where I'm wrong; 2) demonstrate an alternative that still explains all observations in chemistry relating to Avogadro's (now obsolete according to you) number.
Let's start with 1 litre of 1 molar Na
2SO
4 solution, which has (by definition) 6.022 x 10
23 sulphate ions and 12.044 x 10
23 sodium ions. This will be the mother tincture.
For convenience I'll prepare one full litter of 18C remedy. At every step 10ml of the previous step is taken and succussed with 990ml of solvent.
First dilution: You now have: 6.022 x 10
21 sulphate ions and 12.044 x 10
21 sodium ions.
Second dilution: You now have: 6.022 x 10
19 sulphate ions and 12.044 x 10
19 sodium ions.
Third dilution: You now have: 6.022 x 10
17 sulphate ions and 12.044 x 10
17 sodium ions.
Fourth dilution: You now have: 6.022 x 10
15 sulphate ions and 12.044 x 10
15 sodium ions.
Fifth dilution: You now have: 6.022 x 10
13 sulphate ions and 12.044 x 10
13 sodium ions.
Sixth dilution: You now have: 6.022 x 10
11 sulphate ions and 12.044 x 10
11 sodium ions.
Seventh dilution: You now have: 6.022 x 10
9 sulphate ions and 12.044 x 10
9 sodium ions.
Eighth dilution:. You now have: 6.022 x 10
7 sulphate ions and 12.044 x 10
7 sodium ions.
Ninth dilution: You now have: 6.022 x 10
5 sulphate ions and 12.044 x 10
5 sodium ions.
Tenth dilution: You now have: 6.022 x 10
3 sulphate ions and 12.044 x 10
3 sodium ions.
Eleventh dilution: You now have: ~60 sulphate ions and ~120 sodium ions.
Twelfth dilution: You now have: ~60% chance of having 1 sulphate ion, plus ~1 sodium ions.
Tirteenth dilution: You now have: ~6.022 x 10
-1% chance of having 1 sulphate ion and ~12.044 x 10
-1% of having 1 sodium ion.
Fourteenth dilution: You now have: ~6.022 x 10
-3% chance of having 1 sulphate ion and ~12.044 x 10
-3% of having 1 sodium ion.
Fifteenth dilution: You now have: ~6.022 x 10
-5% chance of having 1 sulphate ion and ~12.044 x 10
-5% of having 1 sodium ion.
Sixteenth dilution: You now have: ~6.022 x 10
-7% chance of having 1 sulphate ion and ~12.044 x 10
-7% of having 1 sodium ion.
Seventeenth dilution: You now have: ~6.022 x 10
-9% chance of having 1 sulphate ion and ~12.044 x 10
-9% of having 1 sodium ion.
Eighteenth dilution: You now have: ~6.022 x 10
-11% chance of having 1 sulphate ion and ~12.044 x 10
-11% of having 1 sodium ion.
*All probabilities are approximate. I'll try to get more precise.
So there you go. 18C. You have a remote chance of having even 1 ion of the original mother tincture.
BTW: geni, Rolfe, BSM, Zep, could you check my math? I was in kind of a hurry.