But even your initial purely pressure-based explanation is better than the model often shown by schoolteachers of air going faster over one surface than the other = lift.
Actually, air moving faster over one surface than the other is exactly what I said. That speed difference is what causes the pressure change.
I just went into a little more detail on
why the air flowing over the wing changes speed.
Air pressure can be separated into two sources: static pressure and dynamic pressure.
Static pressure is the pressure the air would have if it were not moving at all. This is the one driving lift.
Dynamic pressure is linked to the kinetic energy of the fluid. The main difference is that instead of trying to find the kinetic energy using mass (hard to do with the atmosphere) is uses density. This does not matter as much in lift (except, as you will see shortly, in reducing the static pressure), since the air is flowing over the wing rather than
The rest of this results from
Bernoulli's principle (the following formula is for incompressible flow only, but it can be adapted to compressible flow):
[latex]P_{0} + \rho g h = P_{dynamic} + P_{static} + \rho g h = \frac{1}{2} \rho V^2 + P_{static} + \rho g h = constant[/latex]
where
P0 = total pressure
Pdynamic = dynamic pressure
Pstatic = static pressure
g = gravity
h = height (altitude)
V = velocity
and rho = density
Now this of course seems backwards at first glance. Greater velocity means more pressure, since it's got that V
2 term sitting right in there.
This is why the Bugatti Veyron only needs 280 horsepower to reach 150 mph, but needs over 1,000 horsepower to reach 250 mph. 60% more speed requires three and a half times as much power. All to overcome the drag caused by pushing through the dynamic pressure.
The trick here is that the above equation is
constant.
At a constant altitude, we can ignore the height term, and we get:
[latex]constant = P_{static} + \frac{1}{2} \rho V^2[/latex]
As I said, it is principally the static pressure generating the lift, so let's re-arrange this equation to show the static pressure. I'm going to assign "C" to represent the constant.
[latex]P_{static} = C - \frac{1}{2} \rho V^2[/latex]
So, increased speed means reduced static pressure.
The difference in static pressure between the upper and lower surfaces of the wing is what generates lift.
This pressure difference is caused by the air moving faster over the top of the wing than over the bottom (think about it: if the air went the same speed over both surfaces, the static pressure would be the same on each surface, and there would be no lift).
So, what your teachers told you was perfectly acceptable. They just omitted the details behind it. To be fair, most schoolchildren don't have the background (in physics or math) yet to be able to follow the explanation I gave.
~ X (currently thinking of incorporating this post into the discussion)
Also be aware that total pressure is sometimes referred to as stagnation pressure (the pressure a moving stream of fluid would have if it were brought to a stop with no loss of energy). This is how Pitot tubes (those long thin rods you see projecting from the front of aircraft, usually with "remove before flight" tags hanging off them) determine airspeed, altitude, and more.