If Aldrin and Armstrong were 3.8 meters apart, then Aldrin would have to be 227cm tall.
How come?
Even allowing around an extra 15cm for boots and helmet, he's only about 195cm tall (note that his leaning forward also shortens him). A quick back of the envelope calculation based on his taking up 58% of the frame from top to bottom and the FOV of the camera being 53.5° from top to bottom, put the two at a distance of only around 3.2 metres.
How come?
Using the shadow for measurements is rather a strange thing to do since shadow length relies on knowing, the angle of the sun, the slope of the terrain (and how it changes), and in this case determining the effects of the convex reflector. Quite simply it is impossible to determine what the length of the shadow should be or is (though it seems to stretch slightly beyond Armstrong's position) since none of these factors is actually known and trying to do so is simply guesswork. You have no way of knowing what the rise in the terrain is between the photographer and the subject, and your above waffle doesn't prove anything except that you're taking wild stabs in the dark to justify your claim about it.
The shadow length does not feature in Groves' calculation, so everything you've written above is, well, let's be polite and just say irrelevant!
That "hardly in a depression" is almost in the centre of a 10-15cm deep crater.
You calculated this just from looking at a photo! Cool!
It doesn't put him "above" Aldrin, other then explaining why parts of the top of the suit that normally wouldn't be visible are actually visible. It also shortens Aldrin vertically.
Have you actually ever seen Groves' analysis?!
Have you noticed that the ground the shadow lies on goes up immediately from Aldrin's position, then reaching the rim of the crater descends again before rising once more? Have you also noticed that the direction the shadow lies is not the direction to Armstrong? (Before you say that it is in the helmet, realise that the helmet is a convex reflector) Nothing the shadow does gives any conclusion as to Aldrin and Armstrong's respective heights. The only thing it tells us is that Aldrin is standing in a depression, something we already knew.
Again, have you actually ever seen Groves' analysis?
No, Groves' analysis claims the camera would be higher than Aldrin's chest height, and then he extrapolates that to mean it was higher the Armstrong's chest height if they are on level ground. The fact they aren't nullifies his conclusion so he tries to fudge that the ground is uneven so as to keep his wanted conclusions.
You haven't, have you!
Sorry I disagree. The change in the ground under Aldrin's shadow has zero to do with the lie of the ground between Aldrin and Armstrong since the shadow isn't on that section of ground.
Try drawing a straight line from Aldrin's right shoulder to the part of the shadow that corrssponds with Aldrin's hip, i.e. the extent to which Groves analyzed the shadow. Now extend that line 'down' to the bottom of the photo and beyond. I'd say it probably intersects the photographer's left shoulder. Have you ever heard of the principle of 'perspective'?!
Funnily enough that is sort of the point to the images, they look different depending on if you are looking up sun or down sun because in one you can see the shaded areas so it looks textured and darker while the other they are hidden from your view so it looks bright and untextured.
And, 'funnily enough' the famous Aldrin shot is looking essentially up-sun, but doesn't display the characteristics that your up-sun example shows, so far as the image of Aldrin is concerned! Will you be moving towards a plausible explanation for this any time soon?! (Contrast Aldrin's left inner knee and right shoulder before you erroneously suggest that great reflecting lump of cheese as the light source!)
It doesn't occur in all direction, it only occurs in the up-sun direction.
The ground is noticeably darker at the bottom of the photo, i.e. near the photographer, than the apparent 'pool of light' around Aldrin.
Look at the ground being reflected in Aldrin's visor. It is much brighter than the surface behind him and is evenly bright all the way to the horizon.
It is completely unnecessary, and would be a fundamental mistake, to try to assess drop-off by reference to an image reflected from a concave visor facing the opposite direction. Now if anything's stretching incredulity that is!
The drop off is only in the up-sun direction where the shadows of the rocks and craters make the surface look darker and as you look further away you are seeing more shadow and less sunlit area.
There are only rocks and craters in the up-sun
distance, and that accounts for the drop off? How do you reach that conclusion? The terrain looks pretty uniform on average to me. You posted photo earlier does not display any drop off whatsoever!
They demonstrate the zero-effect of the shadows being seen or not seen, the "drop-off" is merely that on a larger scale.
I'm sorry, I don't follow. Are you able to expand this explanation?
Wow, that makes very little sense at all. Firstly the crosshairs are NOT printed onto the photo, they are created when the image is taken by the means of a reseau grid that sits directly on top of the film. This means that the fiducials are a fixed part of each image that is taken, the largest one being in the exact centre of the image.
Whatever, the technicalities are irrelevant.
I have no idea what you are going on about the "position of the cross-hairs relative to the all-important image recorded,"
I'm saying that cropping and adding, even if there were some, is
completely irrelevant. Groves analysed the image with complete disregard to the perimeter of the photo. Any reference to the centre cross-hair is only in respect of assessing part of the image, and the relationship between any part of the image and the centre cross-hairs is fixed!
Aulis' claim is that since the large cross hair isn't in the centre of the photo that there is an issue with the image because the large crosshair is supposed to be in the very centre, and in theirs it isn't.
I don't recall this. Are you able to cite Dark Moon precisely?
This is because the image they use is cropped and the fiducial have been moved in respect to the borders of the image. The large cross hair has nothing to do with important information or anything else, it merely shows where the camera was pointed.
As I pointed out earlier, the image appearing in Dark Moon is hardly cropped at all. Do you have a copy of the Dark Moon image? Otherwise, I agree re. the significance of the cross-hairs, subject to my foregoing comment re. Groves' analysis.
The outer cover was white beta cloth, a material that is 90% reflective of sunlight. Do you suggest this is not a strong enough light source?
Accepting your 90% assertion, yes I am, especially given that we're only talking about Armstrong's shoulder, which is pretty small in area and can hardly be described as an effective reflecting surface (take a look at how 'well' Aldrin's left outer shoulder seems to be acting as a meaningful light source for comparison).
No, that was done by the light reflecting of the rather large reflector behind Armstrong. The lunar surface.
Do you mean the area close to the LM that's completely in shadow, or the lunar surface way beyond the LM shadow?!