... a balloon below the speed of the wind will approach the speed of the wind asymptotically and will always be below wind speed ....
That's not correct ... as has been explained in this thread more than once.
-- Roger
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... a balloon below the speed of the wind will approach the speed of the wind asymptotically and will always be below wind speed ....
Humber, until the collision, there isn't anything at the centre of mass, just like there isn't anything at the centre of mass of a hollow ball.Well, the mass-less observer you are trying to make the center of mass.
I'm happy you're amused, yet it's embarrassing to see you decry simple physics as "junior school errors". There is nothing new about this. That you mock it as new thinking exposes your lack of understanding.It is very funny to see adults defend junior school errors as a new dawn of scientific thinking.
You are still barking up the wrong tree. If you think I have overlooked a miscalculation, show us where, please.There was no argument about the momentum because m*v is not quadratic, so it can be added as you would like. However, no so KE, because it's quadratic, and and (-v)^ = V^2
I still don't care either way. I have enough entertainment watching you fail to account for the conserved kinetic energy in a closed system. If you want Spork to play your game, I imagine you'll have to persuade him yourself.Spork is back. Would you like to see him prove his acceleration claim mathematically, like a proper aeronautical engineer rather than silly pet tricks?
Humber,
Does this mean we get to see the "Top Secret" car in action now that you have the data?
nope
The observer, if he has a scrap of common sense, is standing as far as practicable from the point of impact and is certainly outside the closed system we're considering.
nope
Can we see that "Top Secret" cart now that you have the data Humber?
Humber,
It does look like Spork is willing to answer some questions for you!
WindGrins![]()
OK by me, Windgrins, but if they are so helpful and knowledgeable, why do they present their remarks to I Ratant in mocking riddles? It does sound like they want him to fail.
I have one for them. This cart goes up the TM belt, no prop, motors or tricks.
[qimg]http://www.internationalskeptics.com/forums/attachment.php?attachmentid=21828&stc=1&d=1302838596[/qimg]
Rhett and Jamie have told you that you are dead wrong. OK?
Your colours are showing, Windgrins.
Rhett and Jamie have told you that you are dead wrong. OK?
No. Not OK. You did not understand what you read.
Look, you're not going to take it from anyone here, so I have a suggestion: Get a second opinion.
If you happen to know, say, a high school physics teacher, why don't you direct them here or print out the relevant portion of the thread for them to read?
Humber,
Way back in post #2620, completely unsolicited by me, you promised a "Top Secret" cart that "This cart goes up the TM belt, no prop, motors or tricks."
No. Not OK. You did not understand what you read.
Look, you're not going to take it from anyone here, so I have a suggestion: Get a second opinion.
If you happen to know, say, a high school physics teacher, why don't you direct them here or print out the relevant portion of the thread for them to read?
No. He hasn't. Clearly you do not understand. Maybe you should read it again.A professor of physics has told you that you, are wrong.
Had what wrong? Do you mean you think I said you never passed a science exam? Maybe you could add that to your shopping list of accusations to substantiate. I said you should show your notions to a physics teacher, because they're garbage science. If you ever knew this material, you have forgotten it.Not about something vague, but simple a case of collisions. I passed my exams with flying colors thanks.
Now, you had that 100% wrong.
Handwaving like this merely signals your inability to address the substance of the issue. It makes you look silly.Trying to save face, by resort to momentum, tarting up two numbers, talking of centre of mass and closed systems will not rectify that.
You got that rightI don't need you to tell me I don't understand
Remember you're going to point out exactly where that happened, right?... or seek the advice of a teacher, because it was not me that was corrected by the Professor, but you.
You should show them your own magic cart. If you ever finish it.We can see what the reaction would have been has Mythbusters shown the cart to be a sham.
No. He hasn't. Clearly you do not understand. Maybe you should read it again.
Better still, since you keep repeating the accusation, maybe you should point out precisely where the professor of physics told me I was wrong. (Oh boy, will my face be red when you do that. I'll be all like "nooooo" and you'll be all like "looooser" and it'll be amazing.)
So can you actually do that?
Yet Windgrins was the most assiduously "uncoloured" of posters when he arrived here. You seem to have that effect on people. The phrase "try the patience of a saint" appears appropriate.
In all seriousness, I encourage you to get an opinion on your KE vs momentum notions from a physicist you trust. You are not willing to be corrected on this forum, and you are mistaken.
In one-dimension this is true; but in 2 or more dimensions it's not always true. Consider the case of two cars passing on the highway - one northbound and the other southbound. They pass with several car widths between them. Let's say each is going 60 mph. At the moment they're adjacent to one another, their relative speed is 120 mph. But their closing speed is 0 mph at that moment.
During their approach or departure, their relative speed and closing speed become more closely aligned the further away from this point at which they're adjacent.
DISCLAIMER: I don't read much of what humber posts, so it's possible your answer to him was right on the money in the given context. I just felt the brief need to converse with someone that can... communicate.
humber, I hope you do realize that the same theories that say that a balloon below the speed of the wind will approach the speed of the wind asymptotically and will always be below wind speed also say that a balloon released at a speed above wind speed will approach the speed of the wind from above asymptotically and will always be at a speed above wind speed. Or do physical laws work differently in the humbererse?
Really? I must have missed that. Can you post a link or give me an idea on about what page I might find that explanation?That's not correct ... as has been explained in this thread more than once.
-- Roger
Humber,
Way back in post #2620, completely unsolicited by me, you promised a "Top Secret" cart that "This cart goes up the TM belt, no prop, motors or tricks."