Please consider the case of an aeroplane's propeller, moving forward into a headwind of several hundred knots. Now consider whether that prop pushes the aircraft forward or backwards, and then explain to us why the comments above are not stupid.
The drag of the headwind on the plane is an opposing force.
Planes have an engine to overcome that opposing force.
They do not rely on the opposing headwind to drive the prop.
There are only so many ways to try and work around a fundamentally flawed idea, JBTH.
The Ames expert of Spork's
choosing has largely said what I have said about the wind changes being capable of driving the cart, and it not being simply a matter of ddw. The gradient too. The instruments too. etc.
He says the real reason is "obvious" but then he seems to have a lot of other explanations. The current test says it's not the "obvious" because that does not work. It's a sail cart. So what? OK. There is nothing to see. That's it. Except that it is the basis of a plan to launch more crap. Otherwise, it would be just a crank's folly.
Another expert of Spork's choosing, Dr Camp said this of the TM:
Dr. Paul J. Camp Physics Department Spelman College: I'm happy to be quoted by name on this issue by anyone who wishes to do so. The treadmill/non-treadmill issue is entirely one of reference frames and physical law is not dependent on reference frame choice. . . I believe it is not just a different reference frame but in fact a different experiment but that doesn't matter. Personally, I would just
bag it.
How much more do you need?
ETA:
NALSA simply take the average of the wind readings. That is just wrong. It is technically wrong.
The cart is symmetrical. If it's traveling North, the tailwind is from the South. It will gain by tacking, if the tailwind comes from 20 degrees South West, or 20 degrees South East. So; +20 degrees and -20 degrees around the ddw path. That averages to zero. It makes no sense to equate that with ddw, which is zero. So what number do you put on it? RMS.
Let's say it is not symmetrical; +20 -15. The difference is 35. That overestimates the value, but it's not 20 and its not 15
RMS = Sqrt ( a^2 + b^2)/n where n is 2 in this case so Sqrt (20^2 + 15^2) /2 = Sqrt (625/2) = 17.67. It's the equivalent of a constant deviation of 17.67.
When that is applied to the remainder of the chart the average deviation will probably double, maybe more. But that chart has been filtered and averaged so it's not possible to say. But it will be more.