Bjarne Wrote:The buildings own ADG at the top of the Building is in fact so weak it is difficult to distinguish from Gravitational noise , - (not more than 15 ugal) .
How do you know? Your measurements show differently. Let me make this very simple for you:
Hans Wrote;
YOUR measurement at the lowest floor: 981547,684mGal
YOUR measurement at the top floor: 981521,273mGal
Difference:26,411mGal
Elevation difference between the two floors (according to the drawing YOU published: 87.5m
FAG = -0.3086 x 87.5 = 27.0025mGal
Difference between measured gravity and FAG: 0,592mGal
That is the contribution of the building, on the highest measuring station.
Do you have any questions to my calculation?
Hans
The values you have mention are all correct.
Mother Cow (and me) is now extremely happy that you now FINALLY begun to used the objective elevations.
Mother Cow really hope that you too (finally) soon will discover that; if you insist that the FAG to be 0.3086mGal (308,4 ugal) it in FACT would mean a cow on the top of the building would be dragged
slower towards the Earth as it would
without the presence of the building.
I hope you will agree with mother (and me) cow that (according to your own calculations) the FAG-difference-value in fact is 0,592mGal
larger as the pull due to both the Earth’s + the Buildings ADG difference.
Or shortly; The buildings
seems to have exactly 0,592mGal
negative ADG relative ADG at the upper floor...
Do you understand this?
This mean the higher the building is the larger is the risk for the Cow (on the roof of the building) to take off like was it a helicopter?
The Cow logic is therefore idiotic clear, - the FAG CANNOT be 308,4 ugal, it MUST be
much less.
And this statement is NOT strange since we do not have heavy underground in this part of the world.
Therefore have I and Mother Cow in more than ½ year (without success) tried to explain you, that you
MUST adjust / estimate the FAG until you hit an logical
overall acceptable cow-logic pattern.
My friend it is "legal" to adjust the FAG few percent....
And should you seriously try to do this, you certainly would come to the same acknowledgment = >>> that the prevailing thesis MUST fall, simply because you CANNOT “re-establish” such possible overall pattern as the prevailing thesis predict.
BUT what you can “re-establish” by estimating the FAG is
ONLY >> THIS >>>>
And as you can see this is based on a estimated FAG = 301 ugal
Download the Excel file and try to show us a possible ADG pattern based on a reasonable adjustment of the FAG >>
http://www.science27.com/english/Graph/DV4.xlsx
But PLEASE do not come up with something nuts as for example; + or minus 500ugal at the top of the building and minus 50ugal af ground floor.
PLEASE show us a
possible +
logical overall pattern based on the
objective data you now FINALLY have begun to accept..
For a ball of 6.5m diameter, and a density of 1.55, the surface gravity will be 2.7mGal.
What do you mean, - “density 1.55”?
I assume you mean density 1550 Kg/m
3 right
And you believe that should give you a surface ADG = 2700ugal ?
OK then let’s calculate it
Volume of a ball = 4/3 * Pi * r
34/3 * 3,14 * 3,25 = 143,73 m
3Weight = 143,73 m
3 * 1550 Kg = 222766 Kg.
ADG = 6,67*10-
11 * 222766 Kg /3,25
2 =
140 ugal
[Minus missing mass due to cavities (Measurement station 4 and access tunnel) estimated to minus 10 ugal = 130 ugal ....
]
Not
2700 ugal, - Hans.
Hans again you clearly demonstrate that you have no idea what you are blap la nlap nlap about. You is a factor 20 off .. (again).............