Are All Conspiracy Theories False?

Personally, I kind of like thinking about it in terms of fully loaded B-52's. That makes it clear in a real hurry just how stupid the explosives hypothesis really is.

ETA:
Huntsman said:
That would convert to roughly 26 tons of C-4, by the way ( a pound of C-4 is about equal to 1.4 lbs. of TNT).
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No, actually much more. Watch the units. I'm using kilograms of TNT, not pounds.

The final answer is, per tower, 160,000 kilograms of TNT, or about 110,000 kilograms -- 110 tons -- of C-4.
 
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R.Mackey said:
The final answer is, per tower, 160,000 kilograms of TNT, or about 110,000 kilograms -- 110 tons -- of C-4.
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But wait - that's just the amount of C4 per tower to equal the gravitational energy in each tower. The CTers' claim is that the gravitational energy was way too small to cause the observed destruction, so we need to multiply that by what, 10?

So according to TruthSeeker1234, each tower was loaded with more than two million pounds of C-4 (or equivalent).
 
R.Mackey said:
Personally, I kind of like thinking about it in terms of fully loaded B-52's. That makes it clear in a real hurry just how stupid the explosives hypothesis really is.

ETA:

No, actually much more. Watch the units. I'm using kilograms of TNT, not pounds.

The final answer is, per tower, 160,000 kilograms of TNT, or about 110,000 kilograms -- 110 tons -- of C-4.
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Doh!

Thank you. Guess I need to withdraw my application for the NASA Mars program, huh? ;)

Good catch, though.

And for our CTers, it's a catch that was made possible because I provided enough information in my post (the ReF value of C-4) that Mackey could repeat the calculation, and recognize the error.
 
R.Mackey said:
The final answer is, per tower, 160,000 kilograms of TNT, or about 110,000 kilograms -- 110 tons -- of C-4.
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Do you have any idea what the volume of C-4 would be?

The Ford F-150 Superduty can carry a payload of 3,000 lbs. So, you'd need 74 of them per tower to bring in the C-4 by weight. But I'd like to know how much cargo volume you'd need.
 
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CurtC said:
But wait - that's just the amount of C4 per tower to equal the gravitational energy in each tower. The CTers' claim is that the gravitational energy was way too small to cause the observed destruction, so we need to multiply that by what, 10?

So according to TruthSeeker1234, each tower was loaded with more than two million pounds of C-4 (or equivalent).
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Well, that's only 50,000 trips with 40 lbs of Hushaboomtmper trip. So, 20 people make 2,500 trips each. That's feasible. And then they did WTC 7, "conventionally."
 
Loss Leader said:
Do you have any idea what the volume of C-4 would be?

The Ford F-150 Superduty can carry a payload of 3,000 lbs. So, you'd need 74 of them per tower to bring in the C-4 be weight. But I'd like to know how much cargo volume you'd need.
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1.63g/cm3 is what I find. source

That's milspec. In my experience, it's between modelling clay and playdoh (closer to modelling clay).
 
Huntsman said:
1.63g/cm3 is what I find. source

That's milspec. In my experience, it's between modelling clay and playdoh (closer to modelling clay).
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I get 98,159,510 cubic centimeters. That's 98 cubic meters. So that's a circlular area 8 meters in diameter and 2 meters high.

Is that right?
 
Loss Leader said:
I get 98,159,510 cubic centimeters. That's 98 cubic meters. So that's a circlular area 8 meters in diameter and 2 meters high.

Is that right?
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Let's see. 110,000 kg is 110,000,000 grams (1000g/kg)

Divide that by 1.63 that gives 67,500,000 cm3, or 67.5 m3, or a cube of about 4 meters per side. Somehow, that doesn't seem right...but that's still a lot of C-4.

And, of course, that doesn't include packaging, det cord (or wire or shock tube), detonators, attachment devices, standoffs, etc, etc, etc.
 
But y'all are figuring the amount of C4 necessary to equal the gravitational energy of the towers. No CTers claim just that - you need to multiply by 10. That cube should be 8.7 m on a side.
 
You blokes with all your fancy facts and figures. Don't you realise Truthshtup123 and Goggy aren't going to deal with stuff like that?

They want things they can understand. Like football fields and hog weights.
So how many Hogs does it weigh and how many football fields would it blow up?
 
my car gets 40 rods to the hogs head...oh wait....

anyway, the volume of c4 to equal gravitational energy is 281 hogsheads, 571 barrels, 1900 bushels, 7605 pecks...

did i miss any obsolete volume measures?
 
jhunter1163 said:
142.857 stone per ton x 110 tons = 15,714.27 stone of C4. (1 stone = 14 pounds for the stone-impaired)

I have an uneasy feeling that someone's going to run with that phrase, stone-impaired... :blush:
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Oh come on! We all know all the stones were completely pulverized!
 
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