Perhaps this answers some questions...
I have calculated how much kinetic energy represents the Transrapid MagLeV Train with a speed of 400 km/h, transporting 15 ton.
EK = 1/2(m*(v*v)) = 333.366.667.500 J
Whoa, what strangeness is this? 400 km/h = 111.111 m/s, so that answer should be 92.6 MJ, not 333.4 GJ if you're going to work in SI units.
And how much potential energy represents
EP = EK/s = 333.366.667.500 J / 3600 s = 92.601.852 Watts
First off, that's
kinetic energy of motion, not
potential energy, though some of it could be recovered. Second, simply dividing the (wrongly calculated) energy by 3,600 because that's how many seconds there are in an hour and the speed was reckoned in km/h does
not yield a power output in any meaningful way, as you seem to imply.
If the train decelerates to a halt from a speed of 400 km/h in a time
t seconds, then the power dissipated over that time
t is the initial kinetic energy of motion divided by that time
t. For example, if the time is 2 minutes = 120 sec, then the energy is dissipated at an
average rate of 92.6/120 MW = 772 kW
for a period of 120 sec only, not forever. Moreover, assuming a more-or-less constant deceleration rate, the energy dissipation rate is higher while the train is still moving at higher speeds.
Your physics and arithmetic are very odd indeed, as evidenced by the remainder of your post.
In any event, you still haven't answered the one very basic question that has repeatedly been put to you - a simple "yes" or "no" will suffice:
Does your machine produce more energy than it consumes?
'Luthon64