From one angle the building appears to lean ever so slightly but it is by a degree or two so is to be expected. You cannot argue with this because it is there for all to see. The building falls straight down.
Let's try and express what mrkinnies is saying mathematically. His argument, all along, is that the building falls straight down with no rotation, and this is only possible for a CD. Mathematically, we can define an angle A, such that:
A
cd = 0
A
nc > 0
where A
cd is the angle of rotation expected for a CD, and A
nc is the angle of rotation expected for a natural collapse. His evidence for this claim is... well, I'm sure he thinks he has some. Now, he also points out that the building rotates through 1-2º, and that this is to be expected. We can therefore deduce the further relationship:
A
obs = (1.5 ± 0.5)º
where A
obs is the observed angle of rotation. He draws from this the conclusion that the building fell in a CD rather than a natural collapse. We can therefore deduce that:
A
obs = A
cd
and that:
A
obs =/= A
nc
Therefore, we reach the conclusion that:
1.5 ± 0.5 = 0
and
1.5 ± 0.5 <= 0.
Clearly, mrkinnies' argument is absurd.
Let's be charitable, and say that the rotation has to be greater than some threshold for a natural collapse. Clearly, mrkinnies feels that this threshold must be at least 2º. What, I wonder, is his source for this belief?
Dave