I think you're onto something.
Yeah, there is no maybe about it. He never understood airspeed.
I think you're onto something.
This is too freaking cool! A minor interlude for Aero pleasure!
http://www.newscientist.com/blogs/n...on-air.html?DCMP=NLC-nletter&nsref=viraldance
For the TM disbelivers, this doesn't work because the earth and wind doesn't transform properly so they crash in your universe!
I think many of you will enjoy this especially if you've ever made a "jump"!
WindGrins
Flying Magazin drinks the Kool Aid:
http://www.flyingmag.com/pilots-places/pilots-adventures-more/technicalities-something-nothing
My first tandem jump was pretty high at 13,000 ft* but the free fall time was still a heck of a lot shorter than that dance.
* Out of "Mr. Douglas", the same DC-3 that was in "Drop Zone" with Snipes and Busey. I actually got nervous because it looked like my instructor was out like a light on the climb up to altitude, and there was no way I wanted to land in that plane, especially with the pilot that looked 18 years old.
@ spork,
While you're around, I just remembered something I read, and went back and checked.... the submission report says the prop is 17.5 feet. Is that correct? I have been using 16 feet all this time.
While you are looking at that report, LLyricist, take note of how the rolling resistance is calculated, then you may see the other reason I asked if it was .08
Okay, your comprehension of this is so far removed from reality as to be inexplicable.
I just got through saying that adding to the airspeed hurts the cart. And that the wind deviating from DDW adds to the airspeed. And you turn around and claimed I said the opposite. Which of course would be ridiculous. Then you PSed and made the almost correct interpretation of what I said and claimed it contradicted what I said.
Jeeez man.
Or maybe you don't understand what airspeed means?
I know what number he used in the hypothetical situation that explained how the cart works. It has a couple numbers that may be the same as the actual cart, but they are all used for illustration purposes nonetheless, and aren't necessarily representative of the actual cart.
The propeller diameter I asked about above was not in that part of the report, but at the beginning, and was in fact, referring to the actual cart.
Now I know some people have a hard time separating reality from hypothetical (or fantasy for that matter), but I am not one of them.
This must be the "busted cart", that humber is talking about.The Make magazine article by Charles Platt. Of course the publisher of that article did something very rare in the magazine world. He admitted that his author was wrong and published a very thorough article debunking their original claim.
Yes, you did.I did change it because it was not what I intended to say. I did not say you had said the opposite.
I know that, I said this before, and called it the AOA problem, and I have no way of quantifying it. But I can quantify the longitudinal component of the airspeed, which also, and more obviously affects the cart's performance.But, factoring in the wind angle as the cosine of , is not what is written in the submission,
This is just wrong in every imaginable way.and power of the wind is related to the cube of its velocity. KE =1/2mv^2, and mass over time is related to V, so the energy is related t0 V^3.
There is no doubt the the tailwind drives the rotor as a turbine, and the power generated by a turbine is related to the cube of the cosine of that angle away from the axis. The opposing turbine force will fall when the wind is not ddw, so opposite your contention.
No, I changed the way I expressed the same point.Yes, you did.
No you can't quantify that, and it still wouldn't deny that boats can gain from tacking, and so can the cart; and it is a fact that turbine force falls as the cube of the cosine away from the axis.I know that, I said this before, and called it the AOA problem, and I have no way of quantifying it. But I can quantify the longitudinal component of the airspeed, which also, and more obviously affects the cart's performance.
Just btw, with a 17.5 foot prop I get pretty much the same results as before with a Cd of .3 and a crr of .012.
No, it can'tNo you can't quantify that, and it still wouldn't deny that boats can gain from tacking, and so can the cart;
There is no turbine force.and it is a fact that turbine force falls as the cube of the cosine away from the axis.
You are claiming that the cart performs worse when not ddw, when the contrary is true.
It is not difficult to fit data into a system where all major parameters are linearly related. Speed, prop AV, acceleration etc, are all coupled together.
What you have failed to do, is show that other influences are not.
The opposing turbine force is one such example.
The opposing force from the propeller is accounted for.
Fnet = Thrust - (Prop Power Demand / Drivetrain Efficiency / Ground Speed) - Aerodynamic Drag Force - Rolling Resistance
And airfoil section can gain lift from incident wind, and so can the remainder of the cart. The apparent area exposed to the wind increases when not ddw.No, it can'tNo you can't quantify that, and it still wouldn't deny that boats can gain from tacking, and so can the cart;
The videos clearly show that the prop turns freely CCW, when not forced by the chain to turn the other way. That turbine force does not go away. The net force is the difference of that turbine force and the direct force driving the cart and wheels to turn it the other way. That is why it is so slow.and it is a fact that turbine force falls as the cube of the cosine away from the axis.
There is no turbine force.
It is exactly what you are doing.Wrong, as usual.You are claiming that the cart performs worse when not ddw, when the contrary is true.
There is no tailwind at the propeller, unless you are actually using that term as a pilot would. In which case, absolutely right, and it is that tailwind and the reduced power requirement because of it, that enables the cart to work.Where the power demand is simply the load at the prop shaft, and "powered" by the wheel. That says nothing about the effect of the tailwind on the propeller, which will reduce the demand.
Forces are frame invariant, as is rotational power.And you are mixing power and force from two different frames.
And the F is the same in all frames.The aerodrag force is related to the difference of the cart and wind speeds, Vhead, so producing an opposing force, F, related to Vhead^2, and power related to F*Vhead^3. But, the power consumed from the ground frame is F*(V_cart)
All irrelevant, Force is frame invariant.F_Drag = K*Vhead^2
Power_Drag = K*Vhead^3
Pcart = K*Vhead^2*Vcart.
Yep, it's just too bad that the drag the airfoil sections produce always leave them with a net force pointing to the rear. And I have done the polars for those airfoils, and I know this for a fact.And airfoil section can gain lift from incident wind, and so can the remainder of the cart.
You can assert this all you want, but until you can actually explain it, it remains fantasy.The apparent area exposed to the wind increases when not ddw.
The prop also spends 50% of its time in above the hub where the wind is measured, and that wind will certainly be faster then seen the other blade which will be below the hub. The cart can exploit both vertical and horizontal wind gradients and angle changes.
The videos clearly show that the prop turns freely CCW, when not forced by the chain to turn the other way. That turbine force does not go away. The net force is the difference of that turbine force and the direct force driving the cart and wheels to turn it the other way. That is why it is so slow.
When raced, the small turbine cart was quick of the mark, while the prop cart limped along, because that same turbine force was opposing the cart.
It is exactly what you are doing.