Shrinker
Graduate Poster
- Joined
- Oct 25, 2004
- Messages
- 1,600
First, using trogonometry, let's calculate the length of the LM shadow; call it 'X':
X = 6000mm / Tan 15 degrees = 22,392mm
Now, using triangulation, let's calculate ...[a load of unnecessary garbage]
Length of LM shadow with sun at 15 degrees above horizon=6000mm*tan(90-15) = 22,392mm
Length of LM shadow with sun at 15.35 degrees above horizon=6000mm*tan(90-15.35) = 21,857mm
Difference = 535mm
Not 36mm!!
And that's not even a maximum! What happens if the ground has a slight decline away from the sun of say 5 degrees? Yes, that's right, the difference gets even bigger - 1,174mm!
Not 36mm, Southwind. Not 36mm at all.
After 18 pages of vague ramblings you've finally pinned your claims on something verifiable, and surprise, surprise, you've utterly embarrassed yourself. Twice.
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No... Just no. There is no single light source on the planet, then or now, that could light up that much area.