How would the constants of proportionality you suggest change the argument for deformation? Would it? Linear relations still hold over the first few degrees, so points a, b and r must still move according to a set, fixed relation for rigidity to be maintained. They do not move together as multiple drop curves show from at least 2 views.
I have not suggested any "constants of proportionality". The Membership Agreement does not allow me to state my opinion of your use of linear approximations for sine and cosine functions. The relationships between the vertical coordinates of points a, b, and r are approximately linear
for small angles of tilt, but you have miscalculated somewhere.
I don't know where you made your mistake(s). You haven't given me a reason to care.
WDC, in your calculation what is the upward angle the viewing line makes with the horizontal? The upward angle of viewing is very important and I don't see it mentioned anywhere in your post. An incorrect upward viewing angle would change the whole result.
I calculated the actual drops and differences (as did
Myriad, despite his use of the word "apparent"). Those numbers are independent of the observer.
WDC, I am looking at your rotational tranformation and I see nothing about the viewer looking up at a 12 degree angle. Where do you include this info in your calculation?
Do you assume the viewer is looking horizontally? I hope not.
I assumed nothing about the viewer or angle of view.
If
your graph was supposed to be observer-dependent, then you mislabelled the vertical axis. A difference in meters is an objective measure. There are no relativistic velocities here, so lengths and differences between lengths are the same for all observers.
If we use your slope, we get pretty absurd angle readings. You predict about a 15 degree slope by frame 260?
You appear to be speaking about my "slope" as though it were a single number. If that is true, then you don't know what you're talking about.
My calculations used sine and cosine functions, not small-angle linear approximations. I showed my work, so you have no excuse for thinking the curves I calculated were linear. Those curves will probably appear linear to a careless or untrained eye, but their non-linearity can (just barely) be seen at the resolution of my graph. If you can't see the non-linearity, then I suggest you use my calculations to create an equivalent graph with greater resolution, print it out, and hold a straight-edge against the curve on your printed paper. Holding a straight-edge against the monitor screen isn't good enough.
Please plug your slope into the linked plots and try to predict the antenna tilt with it.
Why? You haven't given me a reason to care.
I wouldn't have done this calculation at all if
Myriad hadn't posted a typo in his last number. I was curious about that number, so I did the calculation independently. That took about ten minutes. Having done that, I figured I might as well post a correction/confirmation for
Myriad's calculation.
It took about twenty minutes to create the graph in my previous post and to copy it to my web site for display here. That's about twenty minutes more effort than your responses deserved.
I will note, however, that if you have been using
your calculation of a-b to infer the tilt, then you've been underestimating the tilt by an order of magnitude.
Some of us have worked on this for over 7 months.
Hey, dude (BasqueArch), do your own research. I'm not your mother.
I leave you to your own "research".