I won the million rupee
In the following keep in mind I will soon go into mumbai, so I need to convert some cash to rupee at the airport or ... Get some rupee in advance

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Somebody correct me if i am wrong, my speciality was Quantum physic, not Chemie.
There is 55 mole of water per liter (if I recall correctly). If we assume a saturated solution this go into complex operation, but as I understand the mother tincture principle, this is rather a diluted solution.
If you have n compound named M1...Mn in a solvant S, Each of those compound having a concentration [M1]...[Mn]. EAch will roughly due to the assumption of diluted solution rather inferior to 55. But for the sake of the argument let us all assume that any solute concentration is 10 mole.liter-1 (which is wrong this would already be beyond saturation but I do not want to go into chemical activity and perfect gas equations).
Let us notice the {Mx,j} the number of molecules for solute Mx AFTER Dilution number j. {Mx,0} is the initial number of molecule, so {Mx,0}=[Mx]*6.02.10^23. So for the sake of the argument this would be {Mx,0}=6.02.10^24.
Now since we are working in dilution and concetration we can consider every compound independant.
After Dilution 1, FROM THE DEFINITION of dilution itself, no matter how much you succuss , if you really dilute you will have {Mx,j+1}=0.01*{Mx,j}.
So, {Mx,1}=0.01{Mx,0}=6.02.10^24*0,01=6.02.10^22
{Mx,2}=0.01{Mx,1}=0.01*0.01*{Mx,0}=6.02.10^20
{Mx,3}=0.01{Mx,2}=0.01*0.01*0.01*6.02.10^24=6.02.10^18
{Mx,n+1}=0.01{Mx,n}=(0,01)^n*6.02.10^24
Still following me Mr Scheick ?
So now we have a number of molecule x in solvent for n=20 (20C) equal to :
{Mx,20}==(0,01)^20*6.02.10^24=10^-40*6.02*10^24=6,02*10^-16.
10^-16 is an extremly small number of molecules. This is impossible. Molecule cannot be fractionned they are integer (?) entity. So After 12C you have nothing more in your dilution.
Even if you consider saturated solution, you won't be able to go much more than 55 moles of componant in your 55 moles of water (else you can't call that a solution anymore) and any those step for saturated solution only apply for the first 1C, or 2C dilution. Afterward you have diluted solution, see above.
I will now stand on a leg and
I will assume you PROPERLY do your dilution and properly clean up your apparatus between dilution, unlike a certain team of bad scientist I won't citate
If you say that any physical activity of the solute is present in your solution after a dilution of 12C this can ONLY means that you have a PARANORMAL effect of a coumpound which is NOT PRESENT (normal effect as forseen by science : is no physical activity related to the solute since it does not exist anymore beyond 12C). Homeopathy just say that : at 30C there is still an effect (example : basophile still react). Thus homeopathy is paranormal.
Do I get my million rupee please ?
PS: I assume it has already been talked about before in the 90+ page those cumulated homeopathic thread but that would be nice to see mr sheick answer to the above.