John Freestone
Graduate Poster
A little more patience, and you might get one puzzle right this year.Well jjcote, if it is as easy as this little canard, it won't be a problem.
Yes, yes, get on with it...
Ok here goes for the paddle question. I don't know what the 'paddle' is really about, but it seems some device for measuring two air velocities, from which we can calculate the difference.
First of all, it seems right up to '4 m/s', for someone 'standing in real wind', if that means someone standing on the ground. Yes. The top layer is going 10, the particular layer lower down that we're measuring the other velocity of, jj said was going slower, at 6. Difference = 4. Now, I don't get why you've put CW. You're obsessed with clocks. All I can imagine is that if I stood to the East of the 'paddle', the top layer would be going 4 m/s faster than the lower layer, and we can imagine that would spin a 'paddle device' clockwise as we look at it. Yes? I think jjcote's wind direction was from the south, but I can't be sure now. I'll say that was it anyway for this. As I've pointed out before to you, CW and CCW don't mean diddly unless you give enough information. If we stood to the West of the device, the southerly wind would still be faster at the top layer and slower in the lower layer, but now it would move the paddle CCW. It hasn't changed direction. You just looked at it from the other side. Ok so far. 4 CW looking from the east side.Stand in real wind while holding a paddle device, so that the axle is above the boundary layer, with the top and bottom blades driven by the wind and boundary respectively. This should yield a difference of '4m/s' (CW) and then again at windspeed. (10 - 6 = 4).
But now you say same again at windspeed. If you mean we are now travelling with the wind holding the device, you must surely realise that it can only measure the relative windspeed (by now, surely, can't you, by now, surely, please?). So it's top measuring device gets 0 m/s and its lower one gets
(the speed of the wind jj said it had relative to the ground) minus (whatever speed we are going at)
= 6 - 10
= -4
i.e. the bottom measurer is getting a backwards wind (it's going slower than us at our 10 m/s) of 4 m/s. The top one is stationary. So your bit in brackets should read (0 - - 4 = 4) not (10 - 6 = 4).
So when we are travelling with the wind at windspeed, we get: 4 CW looking from the east side. Gosh, that's the same as above. How amazing. A difference in two velocities is the same even when we measure it relative to a different 'ground-zero'. [ETA: I removed one particularly bitchy bit here, because you did get the same answer, and I was criticising the wrong thing, perhaps. The error seems just that you have a magical paddle device that can measure the windspeed relative to the ground when you're travelling at windspeed, rather than reading 0, and the boundary layer w.r.t. the ground (6) instead of w.r.t. the device (-4), but 10-6 does = 0--4 anyway).]
Now you get really bad:
Yes it is.The belt is not the same.
No. The top one is right, 0. The bottom one is wrong. Unfortunately, I'm finding it difficult to think of how to walk you through how to get it right without just employing the relative velocities trick normal people use all the time when doing this kind of thing. Here goes: JJ said that the boundary layer wind was going at 6 wrt the ground. Now, to any of us, it is obvious that that means that the equivalent layer must also be going at 6 w.r.t. the belt (or we just haven't got a correct setup and need a wider belt, or the air pressure has changed or something - this depends on such laws of physics - ok?). Therefore, if the belt is going backwards (i.e. negative) 10 and the boundary layer is going +6 with respect to it, then the boundary layer is going -10 +6 with respect to us.At windspeed, (taken from he cart) the paddle will turn ( 0 - 6) -6m/s (CW).
= 6 - 10 = -4
So, to correct you above, the paddle will turn (0 - - 4) = 4 CW looking from the east side. Ring any bells?
No. Going with the belt, your back is pushed into a wind. That is what you called a positive wind, so you are right to say the top one gets 10. The bottom one is right as well, 6. But where did you get CCW from? The top is still faster than the bottom, and from the rear, just as before. It should therefore be 4 CW looking from the east side. Hmmm.Going with the belt will be ( 10 - 6)6m/s (CCW)ETA:4m/s (CCW)
No. JJ said that the boundary layer he was using was going 6 m/s over the ground. In the equivalent scenario, it is also going over the belt at 6 m/s, although from our usual earthbound perspective we might call that the belt going past the wind at -6 m/s.This is tricky. If you stand on the belt, the air right next to the belt will be at 0 w.r.t you, so the slower flow of 6ms, can be said to move away from you at 4m/s.
See above calculation. 4 CW looking from the east side.The air over the top (from your back) is coming to the paddle at 10m/s, so the difference is6m/s (CCW.)ETA: 4m/s (CCW)
I think you've even confused the poor wind now.ETA:
If the lower paddle touches the belt, the paddle will stop, and so for a flow going at the speed of the belt. A flow of 6m/s will therefore be 4m/s slower, turning the paddle 4m/s (CCW)
I have no idea what you mean by that. Wind is the motion of an air mass relative to something else's motion. None of these motions are absolute. Blah blah blah blah...You have to agrees that at some point when moving up the belt, the flows will be equal and opposite, so the paddle will stop. This will not happen in the wind.
The answer, in case you missed it, was 4 m/s CW looking from the east side.
Last edited:
, must have been something I ate. He means clockwise and counterclockwise. Of course you do not measure rotational speed in m/s except in the humberverse of course. So I predict that since you did not know the meaning of is incorrect use of units then your proof, which was rather nice by the way, does not apply to him. humber does so many things wrong every time he post something it is amazing. And if you can't read his pointy little head and see what he was trying to say through his errors he won't accept your proof. And even if you did point out every error in his statement I doubt if he would still accept your proof.