jj said:
Yeah, I can. How long is the impulse response?
Good one, jj! Testing to see if we're awake?
jj said:
Yeah, I can. How long is the impulse response?
Sundog said:
It's very satisfying, though, how this thread turned around 180 degrees to bite the biter back. I wish I could vote again on it.
BillHoyt said:
Good one, jj! Testing to see if we're awake?![]()
jj said:
Actually, I'm digesting the 1- gaussian general idea.
Oh, the statement isn't quite that...
And that singularity e^ (1/ zero) suggests that the transform doesn't fall off very fast...
Stimpson J. Cat said:JJ,
I have constructed a new type of notch, which essentially takes the form f(w) = 1 - exp[-(1/x)^2], where x = 0 is the location of the notch. This seems to give a nice smooth notch, which can destroy any singular peak without being much wider than the peak. The question is, can you think of any potential problems using such a notch could present?
Thanks,
Dr. Stupid
BillHoyt said:
Randi's rules of engagement here are ...
This forum isn't to do kids' homework assignments or to keep people busy asking about Ron Fisher or the Central Limit Theorem or anything similar.
..tachump ..
After that, I suggested (based on some specious statistical things he said) that he burn his degrees and spank his professors.
He then started a bonfire, painted hoggrease on his naked body and started chanting "scan! scan! scan!" I refuse to engage in such arguments from authority. I am, simply, a bouncer at a local strip club.
That is all. I have made no such claims. That is all.
And, that is all.
I see you are using a slightly different definition of "even" than I am. I have always understood the term even to mean that f(t) = f(-t), for all t, which implies that it is symmetric about t = 0.
Ahh. Ok. For FIR filters, the number of taps of length (talking in discrete-time here) turns out to be relevant to a number of things. An even-tap filter has a half-sample delay, which can be annoying or very useful, dependingBecause of the limit conditions at Pi and 0, one or the other may be much more useful in a given application.
Are you sure you don't have the terms "symmetric" and "even" mixed up? For example, a function for which f(t-a) = f(a-t) would be symmetric about t = a, but would not be even.
Even number of taps is what I mean. Symmetry means symmetry around the center point of the filter.
I have recently had to rewrite all the filtering software we use here in our lab, because the software we were using is not only buggy, but poorly documented, so that we don't know exactly what it is doing. All of our filters are frequency domain, zero phase-shift, zero time-delay, Butterworth filters. There are two issues which have somewhat puzzled me.
Well, butterworth filters have phase shift. I'm assuming since you're talking about sampled data you're taking the magnitude response of the butterworth and using it at zero phase as a filter in a convolve via transform scheme?
Works, but you have a LOT of padding to do.
1) Zero padding: Since the signals being filtered are not periodic, some wrap-around effects will be present. This problem is usually resolved by padding the end of the filtered signal with zeroes. For time domain filtering with an FIR filter, this is simple. The amount of padding needed is just 1/2 the total length of the FIR filter.
The length you need is N+M-1. Not half, length - 1 of the FIR added to the signal. Some signal will be before zero time, then, too. That's just how it is.
Any idea how to estimate the appropriate padding length for a frequency domain filter, other than the brute-force method of inverse Fourier transforming the frequency response function, and seeing how long it takes it to go to (effectively) zero?
There is no simple answer. You need to figure out how long the impulse response that YOU CARE ABOUT is.
Better to custom-design an FIR of the right type.
Yeah, I can. How long is the impulse response?
It may be way way long...
Again, try using a custom-designed FIR. You have MATLAB handy?
Ok, first time I misread this as 1 - gaussian... That would be a band-reject filter consisting of an impulse and a guassian. In some senses an optimum solution.
But it's not, it's got the 'x' in the denominator of the thing.
It has a singularity at zero, at least in its derivitive, yes?
And, well,
at x= +-inf (assume you're using bilinear warping here?)
1 - e ( - (1/inf))= 1-1 = 0
at zero
1 - e (- inf) = 1 - 0 = 1.
Remind me how this is a band STOP, ok?
BillHoyt said:Gang,
You (sunny & tachump & some others) seem to think you can mimic this approach to play some sort of game here. You seem to think the skeptics here can pepper believers with questions and that, therefore, the beleivers can pepper the skeptics back and expect answers. That ain't how it works, kiddies.
Tachump made claims about degrees. He offered to scan in his degrees and challenged me to do the same. I told him he was deep in the midst of the fallacy of argument from authority. After that, I suggested (based on some specious statistical things he said) that he burn his degrees and spank his professors. He then started a bonfire, painted hoggrease on his naked body and started chanting "scan! scan! scan!" I refuse to engage in such arguments from authority. I am, simply, a bouncer at a local strip club.
T'ai Chi said:It is your right to refuse to answer the questions. I have no problem with that.![]()
Sundog said:This defense falls flat on its face because your questions had nothing to do with the paranormal.[/quote
What are you smoking, sunny? There was nothing in the rules of engagement that restrict "claims" to "claims about the paranormal".
This is also not what I said. I said JREF had certain ground rules for engagement. This is from a previous post of mine on the subject:Therefore your assertion is that skeptics here, just because they are the skeptics, can pepper what you call "believers" with questions whether the questions address their beliefs or not.
But the forum has certain rules of engagement; the very rules Claus and others play by and the very rules you continue to whine about.
Randi has made these rules clear on several occasions:
o If someone says they believe something and have no evidence to back it up, let it go unchallenged.
o If someone says they believe something and have evidence for it, call on them to marshall that evidence
o If they say they refuse to answer, let it go.
These are excellent rules of engagement. But, Clancie, it is you, not Claus, who won't play by these rules of engagement. We hear this constant whine of yours because you recognize the believer's trap built into these rules:
o You must either admit you have no evidence, or
o You must state your refusal to answer
That is pretty clear. Somebody makes a claim about something. Anything. They can be called upon to marshall evidence for it.
I have made no such claims. Woodini is simply asking questions. Sorry, sunny, but my time is too valuable to let people randomly ask questions and demand answers of me. How does this differ from Woodini's case? He claimed authority. He offered scanned in documents to back it up. (Laughable really.) He then challenged me to scan in my degrees. I claim no degrees. I am simply a bouncer at a local strip club.
It is about time woodini (and you) deal with a simple fact of skepticism: authority doesn't matter. If a janitor wrote here, and was able to back up her claims with proper citations and excellent logic, she would be welcomed here. She would be showered with praise. Probably offers of marriage as well. We skeptics are weird folk. We're driven more by the quest for truth than for scrutiny of degrees.
I am, simply, a bouncer at a local strip club.
BillHoyt said:
This is also not what I said. I said JREF had certain ground rules for engagement. This is from a previous post of mine on the subject:
That is pretty clear. Somebody makes a claim about something. Anything. They can be called upon to marshall evidence for it.
I have made no such claims. Woodini is simply asking questions. Sorry, sunny, but my time is too valuable to let people randomly ask questions and demand answers of me. How does this differ from Woodini's case? He claimed authority. He offered scanned in documents to back it up. (Laughable really.) He then challenged me to scan in my degrees. I claim no degrees. I am simply a bouncer at a local strip club.
It is about time woodini (and you) deal with a simple fact of skepticism: authority doesn't matter. If a janitor wrote here, and was able to back up her claims with proper citations and excellent logic, she would be welcomed here. She would be showered with praise. Probably offers of marriage as well. We skeptics are weird folk. We're driven more by the quest for truth than for scrutiny of degrees.
I am, simply, a bouncer at a local strip club.
Sundog said:
Do you honestly think I'll let you get away with that?
You have just proved my point for me.
The "rule" you quote says:
"If someone says they believe something and have evidence for it, call on them to marshall that evidence"
Read that again, Bill. Believe. That absolutely does not translate into a general claim!
You are entitled to question beliefs. NOT any incidental claim a woo woo might make, just because they're on that side of the fence.
Incidentally, I happen to agree with you completely about the degree issue.
BillHoyt said:
Holy cow, sunny. Is your only reference book a dictionary? That's pathetic; another argument about wording and definitions...
BillHoyt said:
Holy cow, sunny. Is your only reference book a dictionary? That's pathetic; another argument about wording and definitions...
Stimpson J. Cat said:jj,
My mistake. I wrote all of that from memory. It is not 1 - exp[-(1/x)^2], but exp[-(1/x)^2]. I was misremembering the "1 -" part because what I had originally tried was 1 - Gaussian.
As for the singularity, that is actually kind of interesting. This particular function is infinitely differentiable, and at zero, all of its derivatives are zero. The thing is, it is not analytic. Its complex derivatives are undefined at zero.
...
Dr. Stupid
[edited: The normalization factor I refered to was for something else. The above function is zero for x = 0, and 1 for x = +-infinity.]
BillHoyt said:
Ah, goody. Then you ...