If you're still using the sample standard deviation (with a denominator of n - 1), then this is a counterexample. Your attempted proof uses the population standard deviation (with a denominator of n), though, so I thought you changed your mind about that.Originally posted by T'ai Chi
Well, that can be disproved by finding one counter-example where range/SD < 2.
data = {2,4}
The range = 2, and the SD = sqrt(2), so
the range/SD = sqrt(2) < 2.