Sunstealer
Illuminator
- Joined
- Oct 22, 2007
- Messages
- 3,128
The biggest problem for thermite is this
WARNING FOR TRUTHERS - THIS CONTAINS SCIENCE, SPECIFICALLY CHEMISTRY AND MATHS.
Stoichiometric thermite requires 2 moles of Al per 1 mole of Fe2O3
2Al + Fe2O3 = Al2O3 + 2Fe
2 moles of Al weigh 54 g
1 mole of Fe2O3 weighs 160 g
density of Al=2.64 g/cc
density of Fe2O3=5.24 g/cc
54 grams of Al is equivalent to 20.5 cc of Al.
160g of Fe2O3 is equivalent to 30.5 cc of Fe2O3
Therefore, 51 cc of fully dense powder of 20.5 cc Al and 30.5 cc Fe2O3 weighs (54+160) g = 214 g.
A volume of 1000 cc would weigh (1000/51)*214 = 4.2 kg
For a powder packing density of 50%, the powder would weigh:
0.5*4.2 kg = 2.1 kg = 4.8 lb
So a litre weighs 4.8lb (2.1Kg).
The mass of the reactants is twice that of the liquid iron produced so 1 litre (2.1Kg) thermite will produce 1.05Kg of liquid iron with a volume of 0.15 Litres (150 cm−3) given liquid iron density of 6.98 g·cm−3.
Truthers - give a rough ball park figure for either the weight or volume of molten iron that you think was present
or
give a rough indication of how much molten iron from the thermite would be needed to cut columns/beams etc.
We can then do some further calculations.
WARNING FOR TRUTHERS - THIS CONTAINS SCIENCE, SPECIFICALLY CHEMISTRY AND MATHS.
Stoichiometric thermite requires 2 moles of Al per 1 mole of Fe2O3
2Al + Fe2O3 = Al2O3 + 2Fe
2 moles of Al weigh 54 g
1 mole of Fe2O3 weighs 160 g
density of Al=2.64 g/cc
density of Fe2O3=5.24 g/cc
54 grams of Al is equivalent to 20.5 cc of Al.
160g of Fe2O3 is equivalent to 30.5 cc of Fe2O3
Therefore, 51 cc of fully dense powder of 20.5 cc Al and 30.5 cc Fe2O3 weighs (54+160) g = 214 g.
A volume of 1000 cc would weigh (1000/51)*214 = 4.2 kg
For a powder packing density of 50%, the powder would weigh:
0.5*4.2 kg = 2.1 kg = 4.8 lb
So a litre weighs 4.8lb (2.1Kg).
The mass of the reactants is twice that of the liquid iron produced so 1 litre (2.1Kg) thermite will produce 1.05Kg of liquid iron with a volume of 0.15 Litres (150 cm−3) given liquid iron density of 6.98 g·cm−3.
Truthers - give a rough ball park figure for either the weight or volume of molten iron that you think was present
or
give a rough indication of how much molten iron from the thermite would be needed to cut columns/beams etc.
We can then do some further calculations.
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