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Merged LHC has its first high energy collisions! 7 TeV

It's the energy, which is a combination of the particle mass and speed.

Heavier particles means more energy, and faster particles mean more energy. As I understand it (and I'm open to correction by those with more expertise), that's basically the energy of an individual particle in the beam; a combination of it's velocity and mass.
 
It's the energy, which is a combination of the particle mass and speed.

Heavier particles means more energy, and faster particles mean more energy. As I understand it (and I'm open to correction by those with more expertise), that's basically the energy of an individual particle in the beam; a combination of it's velocity and mass.

Thanks. The link below helps me a little more. I really need to read it several more times though. I keep getting hung up on "volt" vs. "electron volt".

http://www.popularmechanics.com/science/research/4340070.html

I guess I don't have a good feel for the terminology, like I do for electronics. I'm curious why there is no such thing as "proton volt". :confused:
 
Can anyone explain in simple terms what is meant by a beam of protons at 3Tev? I think it means just the speed or equivalent energy, but I am not sure. How does one measure such a thing? Does it mean you need 3TeV insulation in the beam tube? This is something I thought I sort of understood, but I'm not so sure now.

One electron-volt is the electrical potential energy liberated when a single electron experiences a potential change of one volt. It's a measurement of energy, and has a value of about 1.6 x 10^-19 joules. One joule is the amount of energy required to raise a kilogram of water by one degree centigrade, so a kettle containing one litre of water needs about 80 joules to bring it to the boil from room temperature. Therefore, it would take the energy from rather less than 200 million of the particles in the LHC to make a good-sized mug of tea for you and three friends.

What it means is that the particles are travelling extremely fast. Because of relativity, it's not particularly helpful to say how fast, because when speeds get close to the speed of light you can put in a lot more energy without changing the speed very much. It's a lot more informative to quote the particle energy, because that's how much is available to convert into mass. Part of the aim here is to create very massive particles by crashing together two particles travelling in opposite directions, so the more energy per particle colliding, the bigger the particles made by the collision.

Dave
 
Can anyone explain in simple terms what is meant by a beam of protons at 3Tev? I think it means just the speed or equivalent energy, but I am not sure.

As others have already said, pretty much. When dealing with the energies involved, the speed is pretty much irrelevant since it's so close to the speed of light that you can't really tell the difference. This also means that when you add more energy, the speed hardly changes at all. So for all intents and purposes, the particles going at 3.5TeV are travelling at the same speed as they were at 1TeV, and the same speed as they will at 7TeV (and maybe beyond, but it'll take some upgrades to get past there).

The electronvolt thing is really just jargon. It's a measure of energy derived, as already noted, as the amount of energy an electron gains when it travels over a potential of one volt. It came about because the energies involved are actually very small relative to the units we usually use (1TeV is still only around 100 nano-Joules), and because particles are usually accelerated using a voltage, so the unit kind of falls out naturally. The reason it's electrons rather than protons is really a matter of tradition more than anything else.

How does one measure such a thing?

An interesting question. The answer is - with great difficulty. One of the big problems with particle accelerators is that there is no direct way to actually measure the energy. Particle detectors can do so, but only destructively which isn't much use if you're trying to keep beams circulating. Instead, there are a variety of indirect methods that can be used.

The easiest is to simply look at your magnets. A particle with a particular energy and charge will bend with a particular radius in a given magnetic field. If you know how strong your dipole magnets are, and you know how big the ring you're using is, you can work out the energy. The problem with this approach is that any error in measuring the strength of the magnets or the length of the ring will be carried into the error on the energy. A particular problem is that you can't actually measure the magnetic field in the first place. That would require sticking probes inside the magnet, which is something of a problem if you want to keep it under vacuum and fire particles around inside it. Instead, you have to rely on calibration of the power supplies done previously, which adds another layer of errors to things. There are other similar methods, but most of them suffer from similar problems.

Another method, that I've worked on, is resonant spin depolarisation. The principle is that the spin of particles tends to polarise all in the same direction when they spend a long time spinning round in accelerators. By measuring the parameters involved with the polarisation, and then other parameters involving finding a resonance to depolarise the beam again, you can get a very accurate measure of the beam energy. However, this is something that takes time to do, and so isn't something that can work as realtime measurement.

The LHC energy is most likely taken simply from the dipole magnets. Just remember that when they say the energy is 3.5TeV, there could easily be as much as a 1% error on that.

Does it mean you need 3TeV insulation in the beam tube?

No. The idea is that you don't want the beam to actually hit the beam pipe. Remember, the 3.5TeV refers to individual particles, but there are an awful lot of particles involved - eventually there will be 156 bunches each containing around 1010 protons. That's somewhere around 10MJ stored in each beam. With the amount of energy involved at the LHC, if the beam were dumped into the beam pipe, there would be no way of stopping it burning straight through, and drilling a reasonably sized hole in the wall outside.

There needs to be enough cooling that the particles and radiation that does escape won't heat anything up too much. However, in order to actually get rid of the beam, there is a series of fast kicker magnets and diffusers that spread the beam out and direct it to an absorber specifically designed to cope with it.


Incidentally, I just noticed that their schedule had preparation for 3.5TeV down for the 29th March, so looks like things are going pretty much to plan at the moment.
 
Many years ago I took a private tour of Fermilab with one of the head scientists. I remember it very vividly, the tunnel, the huge detector etc., but understood virtually nothing at the time about how it worked. Not a whole lot more now, but I recall that they were converting to superconducting magnets.
As I remember, they used very large RF amplifiers, using huge amplifier tubes which could be disassembled for repair, spaced every 100 feet or so around the beam tunnel to accelerate the particles. I have a memory also of a room with gigantic diodes, perhaps 20 feet tall. I assumed that these were the source of the GEV's. I guess that is just plain incorrect. It could be they were used to strip out the protons from hydrogen?

I was under the impression that the supercon magnets were just used to steer the beam. I now read that
Inside the Large Hadron Collider (LHC), massive, powerful magnets chilled to a few degrees above absolute zero — colder than outer space — will zip beams of superenergetic protons and lead nuclei in a loop at speeds within a hairsbreadth of the speed of light, then collide them head-on.
http://www.popularmechanics.com/science/extreme_machines/4216588.html

Is this just wrong? It is difficult to imagine how one can modulate supercon magnets at these speeds. I think I have taken a lot of mistaken notions for granted as true, and perhaps gotten some wrong information as well along the way. Anyway thanks for all the comments.
 
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As others have already said, pretty much. When dealing with the energies involved, the speed is pretty much irrelevant since it's so close to the speed of light that you can't really tell the difference. ....
Wow! Thanks a lot.
 
One joule is the amount of energy required to raise a kilogram of water by one degree centigrade, so a kettle containing one litre of water needs about 80 joules to bring it to the boil from room temperature.
Dave

There are some things one never forgets. It takes 4200 (ish) joules to raise 1kg of water by 1C

You wouldn't happen to be thinking of k calories would you?
 
I was under the impression that the supercon magnets were just used to steer the beam. I now read that
http://www.popularmechanics.com/science/extreme_machines/4216588.html

Is this just wrong? It is difficult to imagine how one can modulate supercon magnets at these speeds. I think I have taken a lot of mistaken notions for granted as true, and perhaps gotten some wrong information as well along the way. Anyway thanks for all the comments.

You're right, Pop. Mech. is being imprecise. LHC steers the beam with the magnetic dipoles, and accelerates it in a set of RF cavities.
 
We know they collided because the broke up on impact and the wreckage was detected by the usual means.

Edit. I gave this thread some tags. There are several threads on similar subjects.
 
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There are some things one never forgets. It takes 4200 (ish) joules to raise 1kg of water by 1C

You wouldn't happen to be thinking of k calories would you?

Yeah, you're right. Crossed wire in brain; sorry. So that's 700 billion particles to make a pot of tea.

Dave
 
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