TruthersLie
This space for rent.
- Joined
- Jun 20, 2009
- Messages
- 3,715
So the fires in the towers were not started by the planes?
And the columns were cut by ninja squirrels with light sabres?
and sharks with lasers and MOTHRA!!! with lightsabers!!!!
So the fires in the towers were not started by the planes?
And the columns were cut by ninja squirrels with light sabres?
and sharks with lasers and MOTHRA!!! with lightsabers!!!!
Come on, that is silly, Mothra cannot hold more than 6 light-sabres, and would not need them anyway.
and sharks with lasers and MOTHRA!!! with lightsabers!!!!
Well, you obviously managed to confuse yourself, and be off by 1g.
Look at post #272, then repeat your assertion that there is no negative slope in the velocity curve. Then I'll be able to call you a liar.
Dave
DISINFO SHILL!!!!!
It was too Mothra... and not your ninja squirrles with lightsabers... they were there to STOP Mothra!!!!
Thermite on a stick!He means they tied up several hundred thousands of these to the building
http://ticketsmoneypassport.krustyfries.com/blog/sparklers.jpg
Thermite on a stick!![]()
This is about as straightforward and clear cut as can be.In the table on page 7 of (what I presume to be the 7th revision of) his paper, the roof fall distances in feet at 1.500, 1.667, and 1.834 seconds are listed as:
1.500 25.52
1.667 32.56
1.834 38.72
The following equations are facts of arithmetic:
32.56 - 25.52 = 7.04
38.72 - 32.56 = 6.16
In other words, Tony's raw unsmoothed data show the roof travelling 7.04 feet between 1.5 and 1.67 seconds, but only 6.16 feet between 1.67 and 1.83 seconds. It is a fact of arithmetic that 7.04 > 6.16.
That means the velocity actually drops: the velocity during the 1.67-1.83 interval really is less than it was during the preceding 1.5-1.67 interval.
This is about as straightforward and clear cut as can be.
Response, Tony? It's right there in the table on page 7 of your paper.
Dave Rogers
Look at post #272, then repeat your assertion that there is no negative slope in the velocity curve. Then I'll be able to call you a liar.
Dave
...<snip>
You still never answered my question on whether you have a job other than replying to posts on this forum.
This is about as straightforward and clear cut as can be.
Response, Tony? It's right there in the table on page 7 of your paper.
Thanks.That appears to be true.
I'll take a look at it.
You are either confused or obfuscating, but either way you are wrong.
The point I made above with the rate of velocity change is correct. F = ma and the deceleration of the impacting object from full gravitational acceleration is the correct value to multiply by its mass to provide the force involved.
It seems there is confusion because I am speaking of deceleration occuring relative to full gravitational acceleration. The static load is being decelerated by 1g to begin with relative to a full gravitational acceleration state.
Thanks.
I think in this case it is you, Tony, who is confused or obfuscating.
Upthread you stated
Why you have chosen to represent acceleration differently from everyone else is beyond me, but the blame for any confusion falls squarely on your shoulders.
(emphasis mine)I know some will say that the measurement resolution is not sufficient to discern whether or not a jolt took place, but that is a feigned argument for two reasons: One is that the trend is obviously increasing and two the size of the jolt required is much higher than what could be masked by one data point.
What I said about deceleration and amplification here is correct