It means there are 6 equally likely total possible outcomes, and just one possible target (successful) outcome.
Does a die exist where there are 6 equally likely possible outcomes?
And the argument is circular. The premise includes the assumption that God exists. If you don't know that, then you can't possible determine the probabilities of a life-supporting universe with a god or without a god.
It is possible to come up with a probability for the existence of something without knowing that it exists. And if you DID know that it exists, it would be impossible to come up with any probability other than 1.
You can argue that there isn't enough information to come up with a valid probability that isn't speculative, but that's just a rejection of the premise. It is not an example of Begging the Question.
It is not the same as Drake's equation at all. Assigning a value for any factor assumes the existence of that factor.
Does an argument based on Drake's equation assume the existence of aliens?
It is meaningful, for example, to say that as the probability of finding planets in a certain orbit goes up, so does the probability of finding ET intelligent life.
Not if no aliens exist. According to your reasoning, if no aliens exist, it doesn't matter how many planets you add, there will still be no aliens. By your reasoning, Drake's equation assumes the existence of aliens.
-Bri
