Exactly so superficial (from A to Z) as expected.
And like if I would say the cow gives milk because it eat grass, and the car can drive because it is gasoline in the tank, and women blab la too much because they have a mouth.
...more mo cow gibberish...--
I was thinking that if I won a lot of money from the Lotto, I may move to Denmark, X, on that list.
Paul
![]()
![]()
![]()
Nah, Denmark is a free country. You are allowed to be bat crazy.Well, get rid of him and I'll think about it.
Paul
![]()
![]()
![]()
Do your own homework. However, you need to know the mass distribution. You can't assume that it is homogenous. First of all, the structure of such a building is more massive in the lower part (because it has to carry more weight), secondly, there will be local mass concentrations (water tanks, elevator machinery, etc).Which pattern of Acceleration Due to Gravity (ADG) shall we expect to measure inside a building like this one
Notice the values I am asking for is primary the values caused by the buildings own gravity, not the one due to the free air gradient.
Data
- Height 100 Meter
- Lenght 70 Meter
- Width 20 Meter
- Weiht (estimated) 40.000.000 KG
- 30 floors
This, and gradually changing trough the building (provided that by positive and negative, resp, you mean directed towards the centre). Except that the zero point would be in the gravity centre of the building, not in the geometrical centre. This is likely to be lower than you mention, probably as low as the 10th floor, but you need to study the structure in some detail to find out. I would expect that drawings should be obtainable from the building authorities. Also, you may find it difficult to extract the effect of the large shopping centre at the base, so you should include that in your calculations.1
Would the ADG caused by the building itself be:
-
- Positive at the top for (for example + 0.100 Micro Gal)
- Zero, or almost zero at the Centre (14 th or 15 th and 16 th floor)
- Negative at the ground floor (for example minus 0.100 Micro Gal)
I have done it, the second ADG measurement (in fact the third) at DOMOS VISTA have been finished. Now you have a change to defend the prevailing theory, - before I crash it.Do your own homework
CorrectYou can't assume that it is homogenous. First of all, the structure of such a building is more massive in the lower part (because it has to carry more weight), secondly, there will be local mass concentrations (water tanks, elevator machinery, etc).
This is not the question either.If you had shown yourself to be a serious researcher, genuinely interested in finding facts, some people here might have been inclined the help you out, but since you have repeatedly insulted everone here, both verbally and intellectually, the best you can hope for is this:
This, and gradually changing trough the building (provided that by positive and negative, resp, you mean directed towards the centre). Except that the zero point would be in the gravity centre of the building, not in the geometrical centre. This is likely to be lower than you mention, probably as low as the 10th floor, but you need to study the structure in some detail to find out. I would expect that drawings should be obtainable from the building authorities. Also, you may find it difficult to extract the effect of the large shopping centre at the base, so you should include that in your calculations.
You know, if science was easy, every cow could do it.
Hans
Never mind, here it is:
http://www.science27.com/english/Measurement/Domus.pdf
I assume that is #2.
Hans
I believe more measurements must be executed. (the container measurement experiment).*Yawn* Bjarne, if you think you have made a breakthrough, you should publish in an international scientific journal, not here. We don't issue Nobel prizes, here.
Don't worry, you can calculate it you self, the free air gradient is 0.3084ms2 per meterHowever, if you have not taken the factors I mention into account, don't expect them to take you seriously.
If you must used force to get a car uphill it MUST come down when the force suddenly (halfway up) disappear.
Nope.
Drive a car halfway up a hill. Park the car, but keep the engine running. Engage the emergency/parking break. Place the car in neutral gear. Turn off the car. Notice the car does not roll down the hill.
Place a coin flat on the ground. Push the coin halfway up a hill. Notice the coin does not come down the hill.
Drive a car to the bottom of a hill. Park the car in neutral with the parking break on. Get several people to push the car halfway up the hill. Notice that it doesn't go down the hill.
Please explain what is, or is not, happening in this photo (http://farm2.static.flickr.com/1226/981197857_3b1be44587.jpg)
![]()
Don't worry, you can calculate it you self, the free air gradient is 0.3084ms2 per meter
You can easy see there is a + 0.0150 MicroGal at each floor, (much more than any disturbing can account for)
Thank you, nice data. A little tricky to extract from the .pdf, but no matter.
So if you subtract the free air gradient, you get a nice (if somewhat bumpy) slope from the top of the building to the bottom, with gravity being higher at the top. Since we don't know the zero reference (the gravity at that spot if the building had NOT been there) we cannot deduce the center of gravity, however, your measurements are EXACTLY as predicted by established gravity theory:
At the top of the building, you are exposed to the gravity of Earth + the gravity of the building (but - the gradient from altitude).
At the bottom of the building, you are exposed to the gravity of Earth - the gravity of the building.
Between those two points, there is a continuous gradient which crosses zero in the building's center of gravity.
Nice work, Bjarne. You have just disproved your own thesis, but a true scientist accepts that and moves on.
Thank you for playing.
Here is the differential gravity measured by Bjarne's team, when corrected for elevation. As you can see there are a few bumps, but they can be due to local mass concentrations. We don't know exactly what is in that building.
-0.277
-0.467
-0.642
-0.562
-0.470
-0.395
-0.315
-0.225
-0.151
-0.079
0.004
0.073
0.151
0.221
0.294
0.359
0.425
0.498
0.563
0.634
0.705
0.766
0.825
0.896
0.968
1.050
1.118
1.190
1.278
1.345
I will leave it as an exercise to the masochists to calculate the mass of the building from this.
Hans
You have not followed a strict protocol where you have corrected for known confounding factors, so to make long story short, your measurements are worthless and they do not show anything of interest.To make a long history short, - measurements proves that ADG is NOT gradually decreasing towards the center, not from the top to the center and also not from the bottom to the center.
You have not followed a strict protocol where you have corrected for known confounding factors, so to make long story short, your measurements are worthless and they do not show anything of interest.
You have a problem, your understanding DO NOT FIT TO REALETY.
Do you want to ignore that?
Correct. And your measurements do also not matter when you refuse to follow a sensible protocol.My opinion doesn’t matter
Our understanding fits reality. Your problem is that you have wasted time and money on producing worthless measurements. If you had made the effort to produce a sensible protocol (and you were offered help here), you might have made measurements that could have been of interest, but now it is just a case of garbage in - garbage out.You have a problem, your understanding DO NOT FIT TO REALETY.
Do you want to ignore that?