Little 10 Toes
Master Poster
Thank you for the correction there Reality Check. In referring to an Earth year, I was to you on Earth.
No this is not how to understand SR.From my basic understanding, in order to answer the beard length question, you need to tell us how fast the Earth is moving.
The rocket is really moving 100,000 km/s east relative to planet X.You have told us that Planet X is moving 100,000 km/s.
You have mentioned that a rocket ship is moving in the opposite direction of Planet X at 100,000 km/s.
A simple diagram is R <----- # ---> E -----> X where R is the rocket ship, E is the Earth, X is Planet X, # is the point in space when Planet X was directly overhead the Earth and launched the rocket ship, and the greater than / less than signs are used as arrows to show direction of movement.
RC's clock.You need to specify whose clock is measuring the year.
This is irrelevant.At the end of one year according to my clock my beard reaches the floor.
But Paul will report that his beard reached the floor after more than a year by my clock.
But from what I have seen the situation is:
I am on a planet and consider to be the reference observer.
Paul is on a planet X travelling at a speed of v (100,000 km/s) from my planet.
Bjarne is on a spaceship with travelling at a speed of 2v (200,000 km/s) relative to me in the opposite direction to Paul.
As noted before: I will measure Paul and Bjarne's clocks to tick slower because they both have relative velocities to me.
But it loks like Bjarne has sated that he is actually at rest realtive to me. This makes it even simpler: No time dilation for him.
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Bjarne is on a spaceship with travelling at a speed of 2v (200,000 km/s) relative to me in the opposite direction to Paul.
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http://www.science27.com/forum/abc77.jpg
We expect according to SR; time dilation to be the same in all directions.
Hence Paul should expect the same when he launch a spacecraft from planet X.
BUT a person in a different reference could never agree about how the captains beard length must grow.
Hence the idea is shot down.
The idea that there are no absolute reference frame is death, There MUST be.
Witch mean if we (the Earth) moves 100,000 km/s west seen from a absolute reference frame , and we launch a rocket with same speed in the opposite motion direction time is NOT ticking slower, because from a absolute reference frame the true speed would be ZERO.
ONLY by launching the rocked opposite will cause the clock to tick slower.
SR ONLY make sense in an absolute reference frame.
The truth is; only the speed of EM-waves (any particle without mass) is the same in all direction in all reference frames.
But the speed of a mass particle cannot be the same, and can only be correct understood in an absolute reference frame.
This is the where the chain went of for A. Einstein, - and the rest of the world.
FACE IT , it is so simple.
The explanation of this is; that speed of EM waves (so called particles without mass) do not moves through space, but are properties by space itself.
... the captains (my) beard is both reaching the floor and only 25% reaching the floor at the same time.
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No this is not true.Bjarne
We expect according to SR; time dilation to be the same in all directions.
Hans
It is. This is experimentally verified.
Make you self clear please.Bjarne
BUT a person in a different reference could never agree about how the captains beard length must grow.
Hans
The reference frame is always the original frame of the object. The rocket accelerates frem some place. The time frame of that place is the reference for the rocket.
Bjarne
Witch mean if we (the Earth) moves 100,000 km/s west seen from a absolute reference frame , and we launch a rocket with same speed in the opposite motion direction time is NOT ticking slower, because from a absolute reference frame the true speed would be ZERO.
ONLY by launching the rocked opposite will cause the clock to tick slower.
Hans
That would be the case if there was an absolute time frame, yes. However, we can show experimentally that this is not the case.
And:... why SR (in the thought-experiment above) not apply for his reality (reference frame) but only for RC’s and the captains reality.
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This is what the thought-experiment above clearly demonstrates.
?... and therefore the captains (my) beard is both reaching the floor and only 25% reaching the floor at the same time.
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If no one can't answer the question above, no one understand SRSR is really hard to understand. In fact, I would guess there is less than one person in a thousand who fully and completely understands SR
You still don't seem to understand the relative part of relativity.No this is not true... ignorant ranty nonsense snipped
Refer to my previous post.
http://www.internationalskeptics.com/forums/showpost.php?p=7203142&postcount=3888
Well, Bjarne??? Is that what you meant?
RC means what RC wrote: ticking slower.
The clocks always tick slower in special realtivity. No one ever sees a click ticking faster.
Time dilation
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The Lorentz factor is a positive number (regardless of what an especially ignorant person thinks) that is always greater than 1.
I know that you are incapable of understanding simple math but here it is, Bjarne:
v is the relative speed between the observers. It has units of (length/time).
c is the speed of light. It has units of (length/time).
If you square v then you get v2 then you get a positive number with units of (length/time)2.
If you square c then you get c2 then you get a positive number with units of (length/time)2.
If you divide that v squared by c squared then you get a number with no units of measurement which is less than 1 because v is always less than c.
If you subtract that number from 1 then you get a positive number < 1 with no units of measurement.
If you take the square root of that number from 1 then you get a positive number < 1 with no units of measurement.
If you divide 1 by that number then you get a positive number >= 1 with no units of measurement.
That is part of the problem.I belive I know all this
Really?Wait I will get to the point
No response to the new dark energy data Bjarne?
I believe I know all this
Special Relativity predicts that the on-board atomic clocks on the satellites should fall behind clocks on the ground by about 7 microseconds per day
Can such amateurs like us calculate that?
1 day 86400 s
Let say speed = 3000 m/s
y = 1/√(1 - v²/c²) = 1,0000000000503
t' = 86400/√(1 - v²/c²) = 86400,0000086
I guess everybody agree
Wait I will get to the point
Yes you did. Right in this:I did not got the Q
Basically becaus you don't understand even only relative motion.Of course these observation cannot be the same, and therefore the captains (my) beard is both reaching the floor and only 25% reaching the floor at the same time.
This is the result you get when using the dilation formula which Reality Check provided above.
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