MaartenVergu
Illuminator
- Joined
- Nov 19, 2010
- Messages
- 3,146
Hello,
I'm Maarten from Belgium (so excuse me for my English) and I have a theory on relativity. Do not understand me wrong: I accept the SRT and the GRT. This theory is about gravity. I do not change a thing on the idea of the geometry of spacetime (GRT). But I want to explain something about 'the expanding universe' as a relativistic effect given different clocks...
I will explain this and I will explain why space not only 'contracts' with timedilation, but can also 'stretch' (space-stretch)
First, a question.
Different clocks and G
One year for the travelling twin will be five years on Earth for the twin who was left behind. (fictional example, twinparadox)
Imaging you are a travelling twin who has a brother on Earth. And you want to go near the speed of light.
You also like to look back to the object Earth with a large telescope.
At what speed does the Earth turn around its axis and at what speed does Earth turn around the sun with my twin brother on it, given my clock?
Remember:
One day = one turn around its axis
One year = 365 rotations around Earth’s axis, 12 wobbles with a moon, and one circular motion around the sun.
Given the fact that one day for me is one year for my twin brother, given my speed.
So would that object Earth will fall slower, given my clock. Or not?
The first thing you can notice here:
There is a 'problem of motion’. Does Earth accelerate? Do the laws of gravity change, given different clocks?
What’s going on?
This object (Earth) will move too, like it always does. But the question is
‘how fast?’ Relative to who’s clock?
One year is equal to one move around the sun
One day is equal to one turn around Earth’s axis.
But time differs for both observers.
And when time differs for both observers: how does this effect our perception/measurements of fallen objects? Remember: there is not a body in space that is not falling towards something else.
In what way will all the heavenly bodies fall ‘differently’ towards each other given different clocks for different observers?
G must be constant for all observers, even when clocks differ
G (the gravitational constant) must be the same for all observers.
All the bodies in space - must fall towards each other, obeying the laws of physics (i.c. gravity) for every frame of reference.
The measured velocities in the gravitational fields must somehow be related to the clocks of the observers, to hold G constant.
Will all objects fall like they do as if it was one day on Earth for you?
Nature has a solution for that:
Relativistic measurements of motion, time and space in the gravitational field
Lisa and Bart
Lisa stands next to Bart on Earth.
Bart takes his rocket to space.
Lisa begins to move around more and more.
She turns around with the Earth,
When Bart leaves the solarsystem
He sees Lisa going in spirals around the sun
Once Bart is out of the Milkey Way
Lisa is doing more moves in the Mikey Way,
Because the sun is moving in the galaxy
And far far away, Bart sees Lisa with the whole galaxy redshifting…
Lisa goes progressively through more spatial dimensions, seen from different time-points of view, because of the difference in gravity.
So: that’s a relativistic observation from Bart’s referencepoint of view in the gravitational field.
The observer will see more motion of the same object, while he is progressively leaving the gravitational fiellds. His clock will differ more and more, so he will see, relative to his reference frame, more motion of the same object.
And the other way around.
And far far away, he will see the heaveness of far milkeyways and clusters, and they fall towards the whole universe.
So Hubble's law (spacestretch in stead of lengthcontraction) is a relativistic effect, given an observer with a relative different clock.
So no Big Bangtheory is needed.
Maybe this theory is for the crackpotindex,
maybe not.
I want to discuss it here.
friendly regards,
Maarten Vergucht
Antwerp
I'm Maarten from Belgium (so excuse me for my English) and I have a theory on relativity. Do not understand me wrong: I accept the SRT and the GRT. This theory is about gravity. I do not change a thing on the idea of the geometry of spacetime (GRT). But I want to explain something about 'the expanding universe' as a relativistic effect given different clocks...
I will explain this and I will explain why space not only 'contracts' with timedilation, but can also 'stretch' (space-stretch)
First, a question.
Different clocks and G
One year for the travelling twin will be five years on Earth for the twin who was left behind. (fictional example, twinparadox)
Imaging you are a travelling twin who has a brother on Earth. And you want to go near the speed of light.
You also like to look back to the object Earth with a large telescope.
At what speed does the Earth turn around its axis and at what speed does Earth turn around the sun with my twin brother on it, given my clock?
Remember:
One day = one turn around its axis
One year = 365 rotations around Earth’s axis, 12 wobbles with a moon, and one circular motion around the sun.
Given the fact that one day for me is one year for my twin brother, given my speed.
So would that object Earth will fall slower, given my clock. Or not?
The first thing you can notice here:
There is a 'problem of motion’. Does Earth accelerate? Do the laws of gravity change, given different clocks?
What’s going on?
This object (Earth) will move too, like it always does. But the question is
‘how fast?’ Relative to who’s clock?
One year is equal to one move around the sun
One day is equal to one turn around Earth’s axis.
But time differs for both observers.
And when time differs for both observers: how does this effect our perception/measurements of fallen objects? Remember: there is not a body in space that is not falling towards something else.
In what way will all the heavenly bodies fall ‘differently’ towards each other given different clocks for different observers?
G must be constant for all observers, even when clocks differ
G (the gravitational constant) must be the same for all observers.
All the bodies in space - must fall towards each other, obeying the laws of physics (i.c. gravity) for every frame of reference.
The measured velocities in the gravitational fields must somehow be related to the clocks of the observers, to hold G constant.
Will all objects fall like they do as if it was one day on Earth for you?
Nature has a solution for that:
Relativistic measurements of motion, time and space in the gravitational field
Lisa and Bart
Lisa stands next to Bart on Earth.
Bart takes his rocket to space.
Lisa begins to move around more and more.
She turns around with the Earth,
When Bart leaves the solarsystem
He sees Lisa going in spirals around the sun
Once Bart is out of the Milkey Way
Lisa is doing more moves in the Mikey Way,
Because the sun is moving in the galaxy
And far far away, Bart sees Lisa with the whole galaxy redshifting…
Lisa goes progressively through more spatial dimensions, seen from different time-points of view, because of the difference in gravity.
So: that’s a relativistic observation from Bart’s referencepoint of view in the gravitational field.
The observer will see more motion of the same object, while he is progressively leaving the gravitational fiellds. His clock will differ more and more, so he will see, relative to his reference frame, more motion of the same object.
And the other way around.
And far far away, he will see the heaveness of far milkeyways and clusters, and they fall towards the whole universe.
So Hubble's law (spacestretch in stead of lengthcontraction) is a relativistic effect, given an observer with a relative different clock.
So no Big Bangtheory is needed.
Maybe this theory is for the crackpotindex,
maybe not.
I want to discuss it here.
friendly regards,
Maarten Vergucht
Antwerp
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