Richard Gage Blueprint for Truth Rebuttals on YouTube by Chris Mohr

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...
ergo:
The heavier one....
Then he spends five pages trying to rewrite the dictionary about what "heavier" means, never admits he was wrong, and, sulking, just ends up running away from the thread entirely since there are too many people he has to ignore.

Or he just tries to ask the person who asked the question why they have no idea which ball would hit first. What, they can't even answer their question?
 
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Are you folks setting up a set of derails/sidetracks for C7 to escape??? ;)
 
Chris,

Another example of your not knowing what you are talking about is when you compare a steel column to a wood stick. You note how the wood stick breaks and imply that steel columns would break in a similar manner, proving that you do not know the difference between the physical properties of wood and steel.
 
Chris,

Another example of your not knowing what you are talking about is when you compare a steel column to a wood stick. You note how the wood stick breaks and imply that steel columns would break in a similar manner, proving that you do not know the difference between the physical properties of wood and steel.
So you're attacking his credibility by addressing a single possibly incorrect analogy?

IF
Chris Mohr claims a wood stick might break in a comparable manner in some aspect to a metal column
AND
Wood and steel are different
THEN
???
THEREFORE
Chris Mohr does not know what he's talking about at all.

Sure would be nice if you had posted what you were talking about.
 
Chris,

Another example of your not knowing what you are talking about is when you compare a steel column to a wood stick. You note how the wood stick breaks and imply that steel columns would break in a similar manner, proving that you do not know the difference between the physical properties of wood and steel.
Once again, an attack not worthy of you. And certainly not worthy of a reply. I seem to remember you thanking me for not attacking you personally in past arguments in this forum.

You're welcome.
 
Chris,

Another example of your not knowing what you are talking about is when you compare a steel column to a wood stick. You note how the wood stick breaks and imply that steel columns would break in a similar manner, proving that you do not know the difference between the physical properties of wood and steel.


I don't know these particular examples but when both wood and steel columns buckle in compression, they share the same Euler's formula. Not similar, same. Both steel and wood's critical load, one formula, one reason.

It is you who don't know what you are talking about.
 
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So you're attacking his credibility by addressing a single possibly incorrect analogy?
Possibly? Aparently you don't know the difference between the physical qualities of steel and wood either.

IF
Chris Mohr claims a wood stick might break in a comparable manner in some aspect to a metal column
AND
Wood and steel are different
THEN
???
THEREFORE
Chris Mohr does not know what he's talking about at all.
His insistence that the entire upper portion was not falling at free fall acceleration is another example.

The north face descended at gravitational acceleration for about 100 feet.

The entire building above the buckled-column* region then moved downward in a single unit, as observed

The north face is part of the entire upper portion.

Therefore, the entire upper portion moved downward in a single unit at free fall acceleration.

To assert otherwise is saying that 2 + 2 is not equal to 4.

* Incorrect assumption. Buckling steel columns provide resistance and free fall acceleration means no resistance.

Sure would be nice if you had posted what you were talking about.
nistwtc7modelvideo14s16.jpg


These frames from the NIST computer simulation show that the columns are buckling and therefore providing resistance during the period of free fall acceleration. Please note that they are NOT breaking like sticks.
 
I don't know these particular examples but when both wood and steel columns buckle , they share the same Euler's formula. Not similar, same. Both steel and wood's critical load, one formula, one reason.
So you think steel breaks like wood?
 
As hilited above, that much was already contained in chrismohr's postm, and you quoted it. Got trouble reading? Or are you suggesting that you actually missed the exclusion aerodynamics (as opposed to air resistance) and the shape and rotation of the planbet?? You are not that subtle, pal ;)

I'm sorry for making sure I'm clear on something before I respond. It won't happen again.
 
Once again, an attack not worthy of you. And certainly not worthy of a reply. I seem to remember you thanking me for not attacking you personally in past arguments in this forum.

You're welcome.
When someone points out that your comparing steel columns to a stick demonstrates that you don't know what you are talking about, you call it an attack and use that as an excuse not to admit that you don't know the physical properties of steel and wood.

It was not an attack but rather a statement of fact. When someone is so wrong, as you are on this point, it is fitting to note the fact that you don't know what you are talking about.
 
C7 hold it!!!!!!
You denied that freefall can happen to an object that is not falling straight down, and you continue to harp on MY ignorance. First and foremost, rewind a bit and man up to your mistake and agree to stop all these incessant attacks against me, OK?
 
Chris,

Another example of your not knowing what you are talking about is when you compare a steel column to a wood stick. You note how the wood stick breaks and imply that steel columns would break in a similar manner, proving that you do not know the difference between the physical properties of wood and steel.

Chris, seriously. Before you are digging the next hole, you should first acknowledge you realized you reached rock bottom on the previous one.

In other words, don't dodge this:

Hogwash -- yet again.

Correct (so far...but) WRONG. what other force??? When you have dug yourself into a hole the best advice is stop digging.
totally wrong. Yet again. however you have advanced one step - you have identified the system. note also that we are discussing accelerations NOT rate of descent. And IIRC ChrisMohr did not get velocity and acceleration confused.

Now please read this example from my earlier post - It allows you to consider the principles free of the WTC complications and emotive pre-commitments.


So the ball, the hand holding it and the arm it is attached to are "inside the system". You can throw the ball. (You can press on the outer walls) Both presuming that the state of your underwear and your nervous system will allow those actions. More to the point of this WTC discussion this example is an accurate analog of the explantion ChrisMohr gave in Video #18 when he corrected Chandler's error. Chandler is wrong on basic premises in most of his claims.

And your claim, C7, "everything within the system is falling at free fall acceleration and cannot cause any other part of the system to alter its rate of decent" is clearly wrong. ChrisMohr's explantions are correct (in the first order and suited to the intended lay person audience - and those disclaimers don't change the basic facts.)

Ozeco is right, and you are in fact totally wrong on just about everything, Chris.
You'd totally flunk physics 101. You'd not make it through high school without a big fat F on your grade report if you can't learn this bit of simple relativistic mechanics:




Consider a cube that's rotating as it is suspended in air (imagine you can shields it from gravity for the moment): You observe two point P and Q on it on opposite sides. Presently, P is on the side of the cube that noves down, while Q is on the other side moving up.
A second later, P has reached its lowest point and Q its highest. Another second later, P moves up, Q moves down, etc.

What's the velocity of P relative to the direction of gravitry (vertical)? Well at first it had a positive value (positive velocity being defined as moving down), then dropped to zero, then, as it moved up, it had negative velocity.

During that half-turn, what was the acceleration? Since velocity decreased, acceleration was negative. During the next half-turn, acceleration is positive: Velocity reaches zero again coming from a negative value, and then increases to a positive value as P starts moving down again from its top position.

The opposite happens to Q: As velocity for P is positive, velocity of Q is negative, and vice versa. As acceleration of P is negative, acceleration of Q is positive, and vice versa.




Now switch on gravity and let the cube fall at freefall - with no outside forces acting on it.

Questions:
  • What acceleration does he cube experience relative to the center of planet earth? (Answer: g)
  • Is the cube's downward acceleration constant? (Answer: Yes)
  • What acceleration does point P experience relative to the center of planet earth? (Answer: g + a, with a oscillating between a negative and a positive value)
  • Is point P's acceleration constant? (Answer: no)

Now lets move away from that ideal cube, and look at a building. As it falls down, you observe a point X on its north wall near the roof, and measure its downward acceleration.
Question:
  • If you observe that point X accelerates at a constant rate of approx. g for a short while, does that imply that the entire building falls at g? (Answer: No. There could be some rotation of the building, and other movements within the system)
  • If you observe that point X moves at a variable acceleration, does that mean the building is also falling at a variable acceleration? (Answer: No. There could be some rotation of the building, and other movements within the system)




Chris7, do you understand any of that?
Serious question. If you don't understand why you totally flunked on the cannonballs and the rotating objects, then you prove to the world that you are totally unqualified to debate the dynamics of collapse and stay out of this debate!
 
Chris,

Not too bad. You got 2/4.

We'll give C7 a chance to try his hand, if he wants, and tomorrow I'll post the "whys".


Tom

PS. Nope, not a teacher. I'm a working mechanical engineer (bioengineering). But I have taught engineering dynamics for freshmen/sophmore college engineering students. That was a lot of fun.

And I've helped raise a passel of kids thru their "science fair" days.

PPS. You guessed right on the bullet spinning. For aerodynamic stabilization. Same as with a football. No spin, you can't throw it far or accurate. It'll start to tumble.

"Rifling" is helical grooves in the barrel that dig into the sides of the soft, lead bullet, that cause the bullet to spin. Makes it much, much, much more stable in flight (like a gyroscope or a frisbee) & therefore much more accurate.

A spinning bullet (whether shot or dropped) will maintain it's original orientation. A non-spinning one will orient itself (weather-cock) to the apparent wind to minimize drag forces.

Care to adjust any of your answers?

;-)
 
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C7 hold it!!!!!!
You denied that freefall can happen to an object that is not falling straight down, and you continue to harp on MY ignorance. First and foremost, rewind a bit and man up to your mistake and agree to stop all these incessant attacks against me, OK?
These are not attacks. They are statements of fact. I noted that you do not know the definition of free fall.

A cannonball fired out of a cannon may fall to earth at gravitational acceleration but it has another force acting upon it so it does not fit the definition of free fall.

Furthermore, a cannonball being fired out of a cannon has no relevence to the free fall acceleration of the entire upper portion of WTC 7.
 
Minor correction: forces not acting upon "the" building (i.e. as a whole) but upon the part of the building that femr2 (or Chandler, or NIST) observed and measured.
Right. I was knowingly inaccurate to keep the wording simple, but sometimes these are sources of confusion. Sorry.




Well again not quite true. If fired from a high enough altitude and at sufficient speed the cannon ball would go into a stable orbit. It would be in freefall but it would never get any nearer the ground.
Er, well, add "flat earth" to the list of assumptions, or we'll also have to cope with the fact that ballistic trajectories are ellipse arcs instead of parabolas :D




Both are dropping at free fall acceleration but the one shot out of a cannon does not fit the definition of free fall because it has another force acting on it.

[...]

Free fall does not "imply" an acceleration value of 9.8 m/s²
It is the scientific definition.
Dude, your physics and logic are even worse than I thought. You've already been advised to stop digging. It's a wise advice, believe me.
 
When someone points out that your comparing steel columns to a stick demonstrates that you don't know what you are talking about, you call it an attack and use that as an excuse not to admit that you don't know the physical properties of steel and wood.

It was not an attack but rather a statement of fact. When someone is so wrong, as you are on this point, it is fitting to note the fact that you don't know what you are talking about.

Chris, when being smug and self loving, you should first try to be right.

Just a tip from Uncle Noah.
 
...A cannonball fired out of a cannon may fall to earth at gravitational acceleration but it has another force acting upon it so it does not fit the definition of free fall...
More hogwash. In fact it is even more stupid. It is repeated hogwash after I have several times told you the correct situation. There is no other force.

THERE IS NO OTHER FORCE

Here try this - it may give you a ladder to get out of the ever deepening hole you are digging in:

Answer this. What do you think is "another force"? Even the exercise of trying to explain it should show you there is no other force.

...Furthermore, a cannonball being fired out of a cannon has no relevence to the free fall acceleration of the entire upper portion of WTC 7.
The rest of us are not bound by the limitations of your understanding....as several recent posts have clearly shown.

Your understanding of free fall as revealed by your recent posts is limited to single dimension with some recognition of "system".

The cannonball example takes the "free fall" issue into a two dimensional single system scenario. If you cannot understand 2D single system there is little hope of understanding 3D and (at least) dual systems which is the minimum level of complexity needed to comprehend WTC7 collapse.
 
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