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Merged Apollo "hoax" discussion / Lick observatory laser saga

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That's a great point and an interesting one.....

That's true. Some of them will have been collected by Buzz Aldrin.



It does, unless you can prove that they were collected and returned to earth in some other way.

Can you explain the difference in the mass of the rocks returned by Apollo and the Russian Luna probes? Apollo returned 382Kg from six missions, while the Luna probes returned 0.32Kg from three missions. This difference in mass cannot be ignored. The mass of the rocks returned by Apollo is three orders of magnitude greater than was returned by the Russian probes.

If NASA had robots in 1969 that were capable of finding rocks, drilling core samples, removing the cores from the drill, packaging them in air-tight containers and returning them to earth, where are the engineers that designed and built these robots? Where are the robots now? Do you have any idea how complex these robots would have to be? Or the senses they would require to identify rocks? Also remember that on later Apollo missions the rocks weren't just randomly picked up, the astronauts were looking for particular types of rock that astronaut and scientist Harrison Schmitt had asked them to look for.

Changing tack, you haven't mentioned the lunar rovers used on Apollo 15, 16 and 17. It is obvious from the video footage that these were driven in 1/6th gravity and in a vacuum. According to your theory, were these faked in a studio or driven by humanoid robots?

That's a great point and an interesting one.....I'll see what I can learn Multivac.

Your point of course is ever so most excellent. If the rocks are lunar, a robot getting them is one possibility. But robots would presumably have trouble bringing back small quantities of rocks. The claim is we have hundreds of pounds, no?

So you'd have to show how a robot could do what robots might not be able to do, or so would go the party line now, OR show the rocks are terrestrial(found on earth) but lunar, OR show the rocks are terrestrial and lunarfied, doctored to appear lunar, or some combo of all 3; robot delivered, picked up off the earth, picked up off the earth and "fixed" to appear lunar.....

Least I think that is so, how it would have to shake out.

In various references one reads how over the top, at least per some, Armstrong was. Picking up on all this geology science and lingo and being kinda' good at it.

My theory is that Harrison/Jack Schmidt was a no good commie Apollo Mission Fraud PLANT from the get go. He tells Armstrong(and the others), what to say. then when they say stuff say to the REAL geologists like Shoemaker, they wind up sounding smart.

I'll check it out Multivac.
 
Actually, my wife came up with a simplified approach to the 'ol " didn't ya' know the 1966 Lunar Orbiter ll 2085 image taken in November of 1966 is the exact same image, as in "exact same" meaning identical with, the 1969 AS-37-5447HR image..... Check it out latin. She's a smart girl.....

Here is the easiest and my favorite way Laton to show that the November 1966 Lunar Orbiter II image 2085;

http://www.lpi.usra.edu/resources/lunarorbiter/images/preview/2085_med.jpg

is the very same image as the Apollo 11, AS-37-5447HR image alleged to have been taken July 20 1969 from the simulated Eagle before its pretended descent to the imaginary lunar surface.

http://next.nasa.gov/alsj/a11/AS11-37-5447HR.jpg.

I had my wife do this tonight as an experiment. she is a smart girl, handy with a camera, compass and ruler, but no more capable than any "Lost Bird Thread ": enthusiast,. As such, you all will be able to very easily get to the bottom of Apollo by way of the very same results more or less my Shanghai girl did tonight, and this was her very first try playing with the maps. I'll do even more accurate calculations for this stuff later, but this is too too too too good to pass up our taking a quick shot now.

Get out your favorite measuring device(ruler and compass, whatever). My wife did best ultimately with a stainless steel ruler of all things, so if you've got one handy, use that. But anything will do. Measure the distance between any two points that you care to on the AS-37-5447HR image you like, the image featuring the Command Module. The further apart the points are, the more accurate your measurements will be and the better overall result you'll get. The only requirement is the pair of landmarks that you choose to measure must be present on both images, the 1966 Lunar Orbiter II 2085 image and the 1969(NOT) AS11-37-5447HR image.

Now the AS -37-5447HR image is at slightly lower magnification than the Lunar Orbiter II image. Once you get your measurement between the two landmarks, and please do the measurement as downright precisely as you can, multiply that AS-37-5447HR image measurement by 1.1053. That is the number my wife calculated as a magnification factor for AS-37-5447HR image to slightly larger Lunar Orbiter II 2085 shot. Now that you have that (AS-37-5447HR measurement) X 1.1053 = number, go ahead and now measure DIRECTLY the distance between the same two landmarks in the Lunar Orbiter II 2085 image. What did ya' get? The SAME!!!!! SEE!!!!!! Pretty cool isn't it?

Now to prove that both images are really the same and that the whole Apollo 11 Mission is phony, you'll need to take many measurements. Take them every single which way, north/south, east/west, all kinds of diagonals, go nuts. After you do so you'll find just as my wife did, clever Shanghai gal that she is, that this little "trick" always works. From any line of view, ANY LINE OF VIEW WHATSOEVER, EVERY SINGLE IMAGINABLY MEASURABLE LINE OF VIEW, THE NUMBERS ALWAYS WORK OUT LIKE THIS. ANY MEASUREMENT ONE TAKES ON THE AS-37-5447HR SHOT WILL YIELD THE SAME NUMBER IF MULTIPLIED BY 1.1053 AS STRAIGHT AWAY MEASURING THE DISTANCE ON THE LARGER, RELATIVELY MAGNIFIED LUNAR ORBITER II 2085 IMAGE.

Wow. What a discovery! And in other news, two photographs taken of Half-Dome from the same vantage point show the same match-up. As do any two photographs taken from the same location of the same object!

BTW, there's a simpler way to compare pictures. If you applied this, however, it would not provide the results you want. I already applied this other method to your last pair of "identical" images. You going to reply to me, ever, about that Patrick? Or just run away again?

It isn't even worth showing that this latest pair of images are far from identical. I can tell. Everyone else can tell. But you would respond no more than you responded the last time.



It is impossible for this to occur, utterly impossible, unless the two images are NOT TWO IMAGES, BUT RATHER ARE BOTH ITERATIONS/COPIES OF THE EXACT SAME IMAGE. Don't forget, as I pointed out with emphasis in previous posts, we are told that the Lunar Orbiter II and the Eagle are flying at different heights, along different tracks, using different cameras. One bird taking pics in 1966 and one simulated pretend bird taking pics in 1969.

So Laton, it would appear this baby is indeed about ready to be nailed up and shipped wouldn't ya' say. Turns out the 1966 Lunar Orbiter II 2085 image is identical with and in fact IS IS IS IS AS-37-5447HR itself, AS-37-5447HR allegedly taken on July 20 1969.

Unless time travel was/is possible, we have just proven this whole thang is 'bout as FAKE as they come.

This is actually getting easy now. Wish I had started to bully and "pick" on the photos earlier. It's an even more compelling angle than the vomit thing with Apollo 8. Come to think of it now, I really am beginning to enjoy this photo analysis stuff, and you guys thought I'd never come around….. Sure fooled you……

Are you really suggesting that the Apollo images that have been publicly available since the late 60's were based on LRO images which were not available until this year?

You may be under 16, but some of us actually saw pictures at the time -- published in Life magazine, for instance, or as a print you could get from NASA (I have two.)
 
Images images images.........

Why would you expect pictures of the same part of the lunar surface to be different? Is there a lot of construction on the moon? Is water remaking the surface of the land constantly?

Rather than argue that my picture of 86th street and 8th Avenue and yours are the same because, adjusting for our distance from it, the buildings haven't moved in relation to each other, perhaps you should take a look at shadows and glare which tell if the sun was in the same place for each picture.






Your theory fails to account for the hundreds of pounds of lunar rocks now residing on earth. The rocks exist, must have come from the moon, and must have been collected by hand. Your theory being inconsistent wih known fact, it must be false. You fail.

Imagine yourself to be at a Super Bowl. You Loss leader, are at the 50 yard line 15 rows up. Suspilot is in the press box with Al Michaels and the ghost of Howard Cosell. He's the equivalent of 50 rows higher than you and at the 30 yard line. Jack by the Hedge is in the nose bleed section, way up at the top of the stadium. The players look so tiny to him. Jack by the hedge is looking down from an end zone section. Laton is low down, one row up at the ten yard line. Nomuse is sitting half way up, say 60 rows at the forty yard line.

It is the last play of the game and Kenny Stabler throws a 90 yard pass to Cliff Branch for a touchdown. As Branch raises his arms victorious with the ball perched on the end of one, all you guys snap a shot of the beautiful moment at the exact same time.

You all go home and develop your film. Everyone has "the same shot". Kenny Stabler, beer in hand, is standing right on the one yard line at one end of the field and Branch, with arms up and the football in hand, is inside the end zone at the other side of the field. Let's say for the sake of making this as clear as possible, were one to have gone down on the field with a tape measurer at that very moment and had measured the distance cleat to cleat of Stabler and Branch, the measurement would have yielded a result of 105 yards.

The question now is, "is it possible to do the same thing with this collection of football shots as that which my wife handily did with the AS-37-5447HR shot and the Lunar Orbiter ll 2085 shot?".

Let's say you all blow your photos up to 8 feet by 10 feet so that you can work with them easily. You Loss Leader, measure the distance on your photo from Stabler's beer can to Branch's football. (The fact that it might not be possible in most stadiums to actually get a shot from the 50 of BOTH the touchdown catcher and passer from 15 rows up is a practical objection only. We can ignore that for the sake of this argument as it is not material to the argument's substance. Doing it this way simply makes the points(beer can and football) of interest clear/specific/easy to define and work with. One can of course amend the situation for sticklers simply by saying we imagine ourselves to be in a stadium where the spectator rows are pushed back away from the field to a distance from which the shot could in practice actually and easily be captured from the 50, 15 rows up. Onward..... ) Jack by the hedge does the same and measures the distance beer can to football.

Your shot is the closer shot Loss Leader and so will appear "magnified" relative to Jack by the hedge's photo. I'll just make up a number here for the sake of argument. On your photo Loss Leader, you measure 3 feet beer can to football as representative of that 105 yards separating Kenny and Cliff. Jack by the hedge measures 1 foot on his 8 foot X 10 foot blow up. You guys are working together and you check the work of one another and agree on your results so far. As such, you determine your magnification factor "Jack by the hedge photo to Loss leader photo" is 3 with respect to the ground level of the playing field.

As there are 22 players on the field, not just Kenny and Cliff, you guys start to see if this thing might not work in every case. You start to measure the distance between players, between hash marks, the distance goal post base to cheerleader boot. In each and every case Jack by the hedge precisely measures a distance. He then multiples that distance by 3 and finally passes you the result. You Loss Leader, then make the measurement yourself on your own photo and QUITE OBVIOUSLY find that the "trick" employable in the AS-37-5447HR/Lunar Orbiter ll 2085 case does not hold up here. One cannot just multiply Jack by the Hedge's measurement by 3 to get your own measurement for the distance between the same two landmarks. The two photos are DIFFERENT photos Loss Leader, SPATIALLY DIFFERENT and so MUST yield different results in that regard. Similarly, Laton, nomuse, Suspilot will most definitely NOT be able to work anything out with you either Loss Leader. Think through this and even try it! The point is an obvious one, especially once one works with it practically.

The reason the situation is different with AS-37-5447HR/Lunar Orbiter ll 2085 has to do with the fact that those two photos were take with EXACTLY THE SAME TWO EYES FROM EXACTLY THE SAME SPOT, THEY ARE THE SAME PHOTO.

So just as you could take YOUR OWN FOOTBALL PHOTO Loss Leader, two versions of it, an 8 inches x 10 inches version and an 8 foot X 10 foot version and in every case find that multiplying an 8 inches X 10 inches photo measurement with a "magnification factor" would consistently yield the distance actively/"actually" measurable with a long ruler across the 8 foot X 10 foot version, so too can one do the same with AS-37-5447HR and Lunar Orbiter ll 2085, because in these cases one is dealing not with 2 different pictures but with the VERY SAME PICTURE, one only blown up and rotated a bit with respect to the other.

THE ONLY WAY THIS "TRICK" WORKS, THE ONLY WAY A MEASUREMENT TIMES A MAGNIFICATION FACTOR GIVES AN ACCURATE DISTANCE BETWEEN COMMON POINTS ON ANOTHER IMAGE IS IF THOSE TWO IMAGES ARE NOT IN FACT TWO DISTINCT IMAGES, BUT RATHER, THE VERY SAME IMMAGE, PERHAPS MAGNIFIED, PERHAPS ROTATED, PERHAPS PHOTOSHOPPED TO CHANGE COLORS OR TEXTURES OR SHADOWS, BUT THE IMAGES MUST BE, THE IMAGES CAN ONLY BE, THE VERY SAME, BY THE "SAME" I MEAN TAKEN FROM THE EXACT EXACT EXACT SAME VANTAGE POINT ........

As such, with this criteria being fulfilled in spades by the AS-37-5447HR and Lunar Orbiter ll 2085 pair, one may announce to the world, with utter unmitigated metaphysical certainty that AS-37-5447HR WAS NOT A PHOTOGRAPH TAKEN IN JULY OF 1969, BUT RATHER WAS TAKEN IN NOVEMBER OF 1966. AND AT LONG LAST, THE LAST BIT OF WIGGLE ROOM HAS BEEN ELIMINATED FROM THIS EVER SO BOGUS STORY. APOLLO 11 IS NOW SEEN NAKED IN ALL OF ITS FRAUDULENT GLORY AND I HAVE A PICTURE MY FRIENDS, NOT NOT NOT NOT!!!!!! TWO PICTURES, ONE PICTURE, ONE EVER SO SINGLE AND EVER SO BEAUTIFUL PICTURE TO PROVE IT......
 
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First discrepancy (not counting the solar angle, which is really, really obvious); assuming that the LRO camera was perfectly perpendicular to the surface, AS11-37-5447 appears to have been shot an an angle slightly down-sun; from my eye a good 15 degrees off perpendicular.

I did not work forensically (nor do I have that training). This is a simple blink comparison, taking as starting point Patrick's (obviously incorrect) assumption that the two images at the links he provided are, bar scaling and rotation, identical.

Incidentally, 1.1053? Is this new math? I had to use an approximately 50% reduction to get a decent match.
 
No, Patrick.

Let me lay out your two errors here as clearly as I can.

First, two photographs of the same object from the same place will look similar. It would be very surprising if they didn't.

Second, in the real world difference in lighting, differences in lens distortion, and even small difference of photographer's location will show up if the pair of photographs is compared with something more rigorous than a casual eye. You have not done this. Your method is a failure. With an even slightly more rigorous method, your "matched" pair of photographs fails; they clearly show a difference in angle of the sun and location of the photographer.
 
The photos were NOT taken from the same vantage, that is the whole point....

Wow. What a discovery! And in other news, two photographs taken of Half-Dome from the same vantage point show the same match-up. As do any two photographs taken from the same location of the same object!

BTW, there's a simpler way to compare pictures. If you applied this, however, it would not provide the results you want. I already applied this other method to your last pair of "identical" images. You going to reply to me, ever, about that Patrick? Or just run away again?

It isn't even worth showing that this latest pair of images are far from identical. I can tell. Everyone else can tell. But you would respond no more than you responded the last time.





Are you really suggesting that the Apollo images that have been publicly available since the late 60's were based on LRO images which were not available until this year?

You may be under 16, but some of us actually saw pictures at the time -- published in Life magazine, for instance, or as a print you could get from NASA (I have two.)

The photos were SAID TO HAVE NOT BEEN taken from the same vantage, that is the whole point....

You nomuse, are now arguing like me, for a different reason of course, that the photos were taken from the same vantage point. So we are in perfect agreement there. Of COURSE THESE IMAGES WERE IN REALITY TAKEN FROM THE SAME VANTAGE POINT. It shall be an easy thing then too capture you now into the fraud side's gravitational field, for it is rather easy to show the official story says the shots were NOT taken from the same spot, and Apollo's truth or fraudulence now as is apparent to all including you nomuse hangs in the balance, upon this one simple question/issue.

If NASA/Apollo says the vantages are different, WE ALL THEN WOULD AGREE THAT THEY, THE WRITERS OF THE APOLLO STORY, WRITE FICTION, AND AS SUCH ARE LYING. FOR WE ALL NOW AGREE THE VANTAGE IS COMMON, ONE AND THE SAME FOR THE TWO SHOTS AS-37-5447HR AND LUNAR ORBITER ll 2085.

Lunar Orbiter ll was at an altitude of 51.37 kilometers, latitude 0.80 degrees north and longitude 23.71 degrees east when Lunar Orbiter ll 2085 was snapped in November of 1966. The Eagle best estimate trajectory from Mission Report 5-lll shows the imaginary bird tracking at 1.037 north and image AS-37-5447HR shows the simulated Eagle was roughly at the height of the command module, could not have been under it to get the shot of the CM over the moon. So the Eagle is 60 miles up give or take, in the vicinity of 100 kilometers above the lunar surface. Check the Mission Report table 5-lll for your self nomuse.
 
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Since he claims the Apollo missions were flown robotically, in his fantasy, the LM and CSM really were there in 1969. So if the picture was taken robotically too...

It could still be a real photo in Patrick's World Without Evidence.



That's easy, the Robot mission can land un aided, and deploy sophisticated Military hardware butthey forgot to include a camera. Doh!
 
Actually...

Patrick, why did you quote Laton's article demolishing your claim of "military-style gridding" and then not talk about the coordinate system at all? The alleged military origin of the coordinate system for LAM-2 was an important premise in your argument that that map had been doctored by the military as an attempt to mislead people both inside and outside NASA. And so important was that claim that you ranted on it at length yesterday, even taking others to task for not obeying that focus.

Since you have ignored both his and my rebuttal, I assume you have no answer. Therefore your claim that LAM-2 is a military fabrication is refuted. And the subsequent claim that the doctoring was done intentionally therefore fails by subversion of support.

Moving on, then...

...my wife

Isn't this the same wife you told us in a different thread was fed up with your Apollo hoax theories? You told us that as a prelude to winding up your Apollo-related activities here, back when you felt the discussion was going very badly for you. You said your wife didn't approve of your "obsession" over Apollo, and demanded you stop.

Now for some reason she's helping you. Given your propensity to invent people to help your claims along -- people who magically seem to exhibit whatever contradictory property you specifically require from moment to moment -- why should we believe that anything you're about to say is coming from anyone other than you?

Let's be clear: Unless your wife is willing to come here and speak for herself, anything you say (or don't say) about what she has done to help you is simply hearsay and carries essentially no weight beyond your own claims.

came up with a simplified approach...

What did she do to prove her approach was correct? Further -- and most important -- what did she do to prove her approach actually worked at detecting whether images were the same or different?

Do you understand that such a validation is required before you can use it on "live" data?

She's a smart girl...

She may be a smart girl, but she certainly doesn't have any clue about scientific or forensic methodology. There are lots of smart people who nevertheless lack the specialized knowledge to work in specific fields. Aptitude is not the same thing as knowledge.

And I echo the concerns of the others: Why did this "smart girl" cherry-pick the available evidence in exactly the same way as you did?

she is [...] no more capable than any "Lost Bird Thread ": enthusiast,.

Given that many of us "enthusiasts" have professional training and experience in these methods, I would say that yours is a true statement. If she is therefore likely less capable than us, why is her (non-)expertise something we should pay attention to?

...and this was her very first try playing with the maps.

The argument, "So obviously wrong a novice could detect it," is popular among conspiracy theorists. Sadly it fails on his face as a creatively begged question. Your wife is new to the science and unfamiliar with the data, and working from homegrown methods. What makes her opinion worth any attention?

I'll do even more accurate calculations for this stuff later...

You haven't yet produce any sort of discussion regarding the accuracy in your method. It is the absence of that discussion that reveals just how amateur your approach is.

As I said, you need to show us an error analysis. You need to show us to what precision you are able to measure your control network. You need to show us to what precision the camera captures features in each case. You need to show us how much error would be expected from your different lines of sight (this is not trivial).

Since you have explicitly committed to address the accuracy in your model and method, I note that any subsequent attempt to excuse yourself from the necessity of the error analysis will be intentionally disingenuous on its face.

Measure the distance...

You said your wife used a staineless steel ruler to measure. Yet the images you are using are digital. Please elaborate on your measurement method and what error analysis and validation steps you took.

...between any two points that you care to

Please show us exactly which points you used and how you proved in each case that the "points" you were using could be located to suitable precision in each photo.

Now the AS -37-5447HR image is at slightly lower magnification than the Lunar Orbiter II image.

Is that the only difference that would need to be considered between two digital copies of an image that are purportedly the same image? Since neither you nor your wife have any training in photogrammetry, how do you know you're not missing something important?

[1.1053] is the number my wife calculated as a magnification factor...

Why is that number missing its error -- you know, the "plus-or-minus" values that represent the confidence to which you know that to be the number you're looking for? Are four decimal places appropriate to the discretization of your data? Why or why not?

How was this number computed? That magic number is one of the key premises to your method, but you just pluck it out of your [anatomy]. How many times did your teachers tell you to show your work?

Now that you have that (AS-37-5447HR measurement) X 1.1053 = number, go ahead and now measure DIRECTLY the distance between the same two landmarks in the Lunar Orbiter II 2085 image. What did ya' get? The SAME!!!!! SEE!!!!!! Pretty cool isn't it?

Congratulations on having proven the distributive property of multiplication. If my suspicion is correct about how your wife computed the "conversion factor," then this outcome is practically assured regardless of the data.

It is impossible for this to occur, utterly impossible, unless the two images are NOT TWO IMAGES, BUT RATHER ARE BOTH ITERATIONS/COPIES OF THE EXACT SAME IMAGE.

This is the second of the two key premises in your claim, and you don't prove it. You simply assume it's true.

The error analysis I asked you to perform earlier would have told you (and us) just how possible or impossible it would be for features photographed from slightly different circumstances to exceed the tolerance in your model, data, and measurements. You hand-waved vaguely about fields of view, but never drew a quantitative conclusion. You never presented a lens model. By your allusion to those concepts I gather you realize they are essential to your claim. Therefore you agree that you are most decidedly on the hook to complete those computations to the point where they are quantitatively useful.

This is actually getting easy now. Wish I had started to bully and "pick" on the photos earlier.

Me too, because it's predictably shaping up to be one more topic on which it's painfully obvious you have absolutely no clue, training, or aptitude.

You are the second worst armchair photo analyst I have seen in my ten years of listening to amateurs prattle on about Apollo photos. The absolute worst was a guy named Piper. He held a magnifying glass up to his monitor to "enhance" the picture. You're only slightly less inept.

Once again your entire line of reasoning boils down to suppositions. You write gobs of distractionary text around them, but at their core they're just your uninformed, naive beliefs. You try to measure reality against them, and when it fails to conform, you blame reality. Tsk tsk!

You've clumsily and crudely reinvented what we call a control network. There are vast papers written about the real ones -- including one that you yourself unwittingly cited (but obviously never actually read). The properly validated methods for using control networks in photogrammetry are out there, should you care to see how the pros do what you and your wife have attempted. And you'll find that you're looking for results in all the wrong places.

Unfamiliarity with existing techniques is one of the ways we identify pseudoscientists. They don't know what others have done in the field, just that those others are somehow wrong.

So you think you've used a control network to verify that the geometry presented in two photos of the same subject is exactly identical. You provide no error analysis. You're so naive that you don't realize that the error analysis is the argument. This is the case with almost all quantitative science. The investigator bears a very prominent burden to identify, quantify, and control for all the factors that affect his measurements and conclusions.

But even if the error analysis works out in your favor, it's not proof that two photos derive from an identical exposure. Why do you think that geometric coherence alone establishes a common origin? At most it would identify an identical projection, which can arise in other ways.

An argument for common origin must address all the ways in which two photos can be identical or different, not just the ones you favor or know how to work with. As has been laboriously presented, there is plenty of data in each photograph to estimate the respective phase angles, and they clearly differ by a very large margin.

Second, the LO-II photo retains expected artifacts of its handling. It exhibits artifacts of trackwise assembly: specifically, discontinuity at the seams in geometry and optical density -- expected stitching errors. It exhibits raster-related errors in some of the strips. Leaving aside that you do not account for them in your analysis (and they are factors), you do not explain how these artifacts are missing from the Apollo photo you say was derived from it.

Further, you offer a specific claim: that the Apollo photo derives from the Lunar Orbiter "negative," and that the CSM was composited in. That's testable, and in your case it fails the test.

First, I asked you where the negatives from the Lunar Orbiter spacecraft are stored. That was a trick question, since the negatives never left the spacecraft. They were exposed, developed, and scanned onboard, and the electronic versions transmitted to Earth. The negatives were destroyed when the spacecraft de-orbited and impacted the lunar surface in 1967. So your theory needs to explain how your hypothetical military authorities got the exposed negative that never left the vicinity of the Moon. Another unparsimonious appendage to grow out of your theory.

Second, I asked you about the Apollo "negatives." You obviously didn't know that color photography from Apollo was on reversal film, which does not involve negatives. The Ektachrome E-3 emulsion on the Estar polyester base is a wholly different process. The only way to get from a black-and-white negative image to a color transparency is via an intermediate exposure -- no contact printing or anything. And that still doesn't provide color information, only luminance.

Now when you make a copy of a copy of a photo by means of optical exposure, you lose contrast and detail. That is, the difference in luminance in adjacent shades is lost, and therefore image detail that relies on those subtle differences is lost. However, the Apollo photo actually exhibits a larger spectrum of luminance and greater detail than the LO-II photo. This is the opposite of the effect we should see if the Apollo photo were made from the LO-II photo.

And, while subtle, there is coherent chromatic information in the Apollo photo. That is, color. The Apollo photo is a color photo and contains color information that isn't (and cannot be) present in the alleged source image.

So in summary all the factors but one conclusively prove a separate origin for the photographs. The one factor that appears to disagree is argued to disagree only by virtue of a homegrown, uncontrolled, unvalidated method. Any questions?

As for the alleged composition of the CSM into the Apollo photo, you've provided zero evidence that this is how the CSM got into the photograph, instead of simply having been photographed normally. Do you understand what evidence of composition ordinarily entails?
 
Oh, and "1.053?' Four significant figures, really? As a total eyeball estimate, the scale change due to perspective over the width of the Apollo photograph is at least 5%. So if Patrick had actually measured small distances along both "sun" and "antisun" borders of the picture he would not specify his scaling figure to four digits. The method will not allow specifying to closer than 2.

Which means either Patrick didn't bother to apply his method outside of a small or restricted sample set, or he fudged the results.

Using only the pixel width of the larger provided image (before scaling) as a basis, he is claiming accuracy to within twice the pixel limit (about 2.2 pixels per stated significant figure, in fact). With the necessary scaling of one image to line them up, this works down to very close to the pixel limit. And if he is using anything resembling Adobe PhotoShop, that means he is well inside the aliasing error.

That may not be a math noob error, but it is very much a physics noob error. You don't introduce spurious precision beyond what your methods are capable of.
 
If you are off by that much we are looking at different pictures.

First discrepancy (not counting the solar angle, which is really, really obvious); assuming that the LRO camera was perfectly perpendicular to the surface, AS11-37-5447 appears to have been shot an an angle slightly down-sun; from my eye a good 15 degrees off perpendicular.

I did not work forensically (nor do I have that training). This is a simple blink comparison, taking as starting point Patrick's (obviously incorrect) assumption that the two images at the links he provided are, bar scaling and rotation, identical.

Incidentally, 1.1053? Is this new math? I had to use an approximately 50% reduction to get a decent match.

If you are off by that much we are looking at different pictures.
 
Imagine yourself to be at a Super Bowl. You Loss leader, are at the 50 yard line 15 rows up. Suspilot is in the press box with Al Michaels and the ghost of Howard Cosell. He's the equivalent of 50 rows higher than you and at the 30 yard line. Jack by the Hedge is in the nose bleed section, way up at the top of the stadium. The players look so tiny to him. Jack by the hedge is looking down from an end zone section. Laton is low down, one row up at the ten yard line. Nomuse is sitting half way up, say 60 rows at the forty yard line.

It is the last play of the game and Kenny Stabler throws a 90 yard pass to Cliff Branch for a touchdown. As Branch raises his arms victorious with the ball perched on the end of one, all you guys snap a shot of the beautiful moment at the exact same time.

You all go home and develop your film. Everyone has "the same shot". Kenny Stabler, beer in hand, is standing right on the one yard line at one end of the field and Branch, with arms up and the football in hand, is inside the end zone at the other side of the field. Let's say for the sake of making this as clear as possible, were one to have gone down on the field with a tape measurer at that very moment and had measured the distance cleat to cleat of Stabler and Branch, the measurement would have yielded a result of 105 yards.

The question now is, "is it possible to do the same thing with this collection of football shots as that which my wife handily did with the AS-37-5447HR shot and the Lunar Orbiter ll 2085 shot?".

Your problem is that you are thinking too small. When we talk 60-100yards, perspective comes into play very quickly. Instead try mountains at 10 and 20 km or further. I have photos of the mountian near me (presently hiding under rain clouds) that I use to show that distant mountains appear to hardly change in a photo even with some significant lateral movement (in the case of the photos over 3 km lateral movement) Given that, how different would that same mountain appear in an image if the movement was only slightly laterally as you got further away from it?
 
[most of a completely naive description of pidgen photogrammetry snipped]

THE ONLY WAY THIS "TRICK" WORKS, THE ONLY WAY A MEASUREMENT TIMES A MAGNIFICATION FACTOR GIVES AN ACCURATE DISTANCE BETWEEN COMMON POINTS ON ANOTHER IMAGE IS IF THOSE TWO IMAGES ARE NOT IN FACT TWO DISTINCT IMAGES, BUT RATHER, THE VERY SAME IMMAGE...

No, Patrick. That is not the only way that "trick" works. If you understood the first thing about projective geometry, O "Maths" teacher, then you'd immediately see why. And if you were half the drama critic you claim to be, then you'd probably understand a well-known technique of scenic design and construction that capitalizes on that property of projection.

Your geometric argument is entirely unquantitative and therefore useless. Until you assign actual quantities to the expected error, you have zero case. How does someone who claims to work in a scientific field not understand this?

I'll explain it to you in small words. Before you can claim that geometric identity in the image plane necessarily means an identical line of sight, you have to show how much difference in line of sight will result in a difference in your control network that rises above your threshhold for precise measurement. You haven't even begun the necessary quantitative validation of your method.

PERHAPS MAGNIFIED, PERHAPS ROTATED, PERHAPS PHOTOSHOPPED...

Photoshop? In 1967? Really? How can you claim to be a 54-year-old man and tell us that NASA was using Adobe Photoshop to doctor Apollo images?

TO CHANGE COLORS OR TEXTURES OR SHADOWS...

Bzzt!

Now you're admitting that there are material differences between the LO-II photo and the Apollo photo, whereas before you said they were identical, even right down to the lighting. Changing horses yet again.

So now we have to ask: if NASA when to all the trouble to make the photographs seem different, why didn't they just slightly distort one of the photos to wreck your control network? It's a simple adjustment on the animation stand, you know.
 
Here ya' go nomuse, I shall make it ever so easy for you.....

No, Patrick.

Let me lay out your two errors here as clearly as I can.

First, two photographs of the same object from the same place will look similar. It would be very surprising if they didn't.

Second, in the real world difference in lighting, differences in lens distortion, and even small difference of photographer's location will show up if the pair of photographs is compared with something more rigorous than a casual eye. You have not done this. Your method is a failure. With an even slightly more rigorous method, your "matched" pair of photographs fails; they clearly show a difference in angle of the sun and location of the photographer.

Here ya' go nomuse, I shall make it ever so easy for you....

Here again is the image of our old friend, the Apollo 11 LAM-2 flown Map of Michael Collins taken from a Lunar Orbiter image made long before Armstrong's Saturn V ever pretended to leave the smell of the earth.

http://next.nasa.gov/alsj/a11/LAM2_CMP-flown.jpg

Here now is the blown up image of the command module taken from AS-37-5447HR.

http://next.nasa.gov/alsj/a11/ALS-2_vertical_w-ellipse.jpg

Like the Apollo 11 Flown LAM-2 Map, this image along with many others can be found at the Apollo 11 Image Library website;

http://next.nasa.gov/alsj/a11/images11.html#Maps

The site was last updated November of 2011, so everything is quite current.

Back to business......

Here now we have the LAM 2 map presumably made from a 1966 Lunar Orbiter photo and an image(blown up) allegedly taken by the Eagle over Tranquility Base before the imaginary bird descended on 07/20/1969

Note in both cases how the landing ellipse runs straight across left to right, lunar east to west on the LAM-2 map as depicted. However, the LAM-2 image is rotated roughly 8 degrees counterclockwise with respect to the image allegedly taken by the Eagle. I'll have much to say about the rotation issue in later posts. Suffice it to say for now, this is another example where they have been caught red handed trying to scam us. Obviously both images cannot have the surfboard shaped ellipse in the exact same orientation in the case of both LAM-2 and the alleged Eagle shot, and at the same time have the images in different orientations under the ellipses. THE LANDING ELLIPSES DO NOT COVER THE SAME TERRITORY IN THESE 2 CASES LAM-2 AND ALLEGED EAGLE SHOT WITH ELLIPSE PHOTOSHOPPED IN. ONCE AGAIN, FRAUD IS FOUND, AND HERE IN THIS PARTICULAR CASE, WITH A BIT OF PICTURE PROOF POSITIVE.

Compare the two images and take some measurements on each, one landmark to the next. See if there is any way that you can convince yourself that these shots covering roughly 170 square miles were taken from separate vantage points. The LAM-2 shot which was taken by a Lunar Orbiter well before Neil's bogus space ship was ever launched can now readily be seen as an image identical with respect to vantage as the alleged Eagle shot purported to have been snapped 07/20/1969. Since there was no way for the Eagle to travel back in time to get to the same vantage as the Orbiter in 1966, and since in 1969 the Eagle was said to have been tracking north(0.2 degrees, roughly 3.8 miles) of where the Orbiter had flown when the Orbiter shot was taken, and since the Eagle was per NASA documents allegedly flying roughly twice as high as the Orbiter flew when the Eagle allegedly snapped its shot, and since there is no way the Eagle would have snapped its shot accidentally from the exact same lunar longitude vantage as that of the Orbiter (23.85 degrees per the details as provided at the Lunar Orbiter Gallery website), one may conclude with utter confidence that the two photos are indeed the same photo.

Go ahead and try it nomuse with these two images. The LAM-2 shot (1966) and the Apollo 11 Mission bogus live shot(1969 NOT NOT NOT NOT). Since as I just did above and any other curious researcher may easily do as well, eliminate the possibility of the Eagle and Orbiter having achieved the same vantage(altitude, latitude, longitude, camera angle), one may conclude with a sad sigh that once again Apollo 11 has been proven fraudulent and this proof has a lovely picture or two(NOT), single picture I mean, to prove it.......
 
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The photos were SAID TO HAVE NOT BEEN taken from the same vantage, that is the whole point...

But you haven't shown the numbers to prove that the difference in purported vantage point must necessarily result in a measurable change in your control network.

If NASA/Apollo says the vantages are different, WE ALL THEN WOULD AGREE THAT THEY, THE WRIERS OF THE APOLLO STORY, WRITE FICTION...

No. Everyone but you agrees that your method lacks validity.

Lunar Orbiter ll was at an altitude of 51.37 kilometers, latitude 0.80 degrees north and longitude 23.71 degrees east when Lunar Orbiter ll 2085 was snapped in November of 1966. The Eagle best estimate trajectory from Mission Report 5-lll shows the imaginary bird tracking at 1.037 north and image AS-37-5447HR shows the simulated Eagle was roughly at the height of the command module, could not have been under it to get the shot of the CM over the moon. So the Eagle is 60 miles up give or take. In the vicinity of 100 kilometers above the lunar surface. Check the Mission Report table 5-lll for your self nomuse.

Yes, those are some of the starting values for your computation. They are not the computation itself.

Please stop claiming victory and start working the problem.
 
Your problem is that you are thinking too small. When we talk 60-100yards, perspective comes into play very quickly. Instead try mountains at 10 and 20 km or further. I have photos of the mountian near me (presently hiding under rain clouds) that I use to show that distant mountains appear to hardly change in a photo even with some significant lateral movement (in the case of the photos over 3 km lateral movement) Given that, how different would that same mountain appear in an image if the movement was only slightly laterally as you got further away from it?


And this technique is easily observed in magic tricks in which large objects are made to disappear.

http://www.youtube.com/watch?v=r5Ga5fYxVo0

Without proper close reference points, the inexpert viewer cannot tell that his position and even his angle has shifted just be viewing things far away.
 
The photos were SAID TO HAVE NOT BEEN taken from the same vantage, that is the whole point....

Citation, please. They are both of the Moon. They are both from orbit. What documentation do you have that leads you to believe that they are being represented as being of different objects or from significantly different places?

Or is this the renowned Patrick 180?


You nomuse, are now arguing like me, for a different reason of course, that the photos were taken from the same vantage point.

Don't enlist me as writing in support of your delusions. The best you could say is that your fractured, near-impenetrable writing style, and your complete inability to maintain a coherent argument, might end up with you claiming something in one of your posts that is similar to the rebuttal made by someone else of a different one of your posts.

So we are in perfect agreement there. Of COURSE THESE IMAGES WERE IN REALITY TAKEN FROM THE SAME VANTAGE POINT. It shall be an easy thing then too capture you now into the fraud side's gravitational field, for it is rather easy to show the official story says the shots were NOT taken from the same spot, and Apollo's truth or fraudulence now as is apparent to all including you nomuse hangs in the balance, upon this one simple question/issue.

Case in point. I can't parse the above.

If I strip off the meaningless, self-congratulatory crowing, all I am left with is the semantically dubious "Of course these two images were in reality taken from the same vantage point."

In which reality, Patrick? The one you've constructed? Or the one the Apollo Program claims? And what is meant by "the same" within this context?

In any case, this is not the claim I responded to. Have you forgotten your own words, Patrick?

"NOT TWO IMAGES, BUT RATHER ARE BOTH ITERATIONS/COPIES OF THE EXACT SAME IMAGE. "

A copy of an image is not the same thing as a duplication of a scene. In the latter, two cameras are aimed at the same scene. In the former, one camera is used, and one photograph taken.

Patrick, you strongly appeared to state that the Apollo 11 image was a direct physical copy of the LRO image.

Either withdraw that claim, or disavow it.

(Bolding because otherwise you'd ignore my request. Again.)


If NASA/Apollo says the vantages are different, WE ALL THEN WOULD AGREE THAT THEY, THE WRIERS OF THE APOLLO STORY, WRITE FICTION AND AS SUCH ARE LYING, FOR WE ALL NOW AGREE THE VANTAGE IS COMMON, ONE AND THE SAME FOR THE TWO SHOTS AS -37-5447HR AND LUNAR ORBITER ll 2085.

Lunar Orbiter ll was at an altitude of 51.37 kilometers, latitude 0.80 degrees north and longitude 23.71 degrees east when Lunar Orbiter ll 2085 was snapped in November of 1966. The Eagle best estimate trajectory from Mission Report 5-lll shows the imaginary bird tracking at 1.037 north and image AS-37-5447HR shows the simulated Eagle was roughly at the height of the command module, could not have been under it to get the shot of the CM over the moon. So the Eagle is 60 miles up give or take. In the vicinity of 100 kilometers above the lunar surface. Check the Mission Report table 5-lll for your self nomuse.

The angles aren't the same, as you would know if you had taken more than a cursory look at the pair. Any further confusion is entirely due to your inability to read maps.

I have nothing further to say to you until you retract or disavow your claim that:

AS11-47-5447 and 2085 (LRO sequence) are identical save for scaling and rotation, and;

LAM2-CMP-flown and ALS-2-vertical are also identical to the extent that they must have shared a single original.
 
The best way to think of Apollo in this regard Captain_Swoop...

That's easy, the Robot mission can land un aided, and deploy sophisticated Military hardware butthey forgot to include a camera. Doh!

The best way to think of Apollo in this regard Captain_Swoop...

Landing the Eagle without Neil would have been and was more or less just like landing Surveyor VII. The bird is bigger, but it is not a big deal, no big difference, piece of cake really landing the Surveyor probes and the unmanned Eagle. Piece of space cake COMPARED with landing a dude, mostly because if you crash, who really cares.....?......You haven't killed the dude........

Photos that have the dudes are fake, at the very least shopped. Photos without the dudes may well be real, even real in real-time some of the time.........

Landing dudes on the moon was more likely than not too dangerous and so impossible given 60s technology. That is, you might have pulled it off, but the odds would be so way way way insanely over the tippy top against you. The dudes would more likely than not have died. Would you rather have a live Neil trotting around here giving his bad acting performances Captain_Swoop, or a dead Neil who go suckered into doing something insanely stupid? Armstrong is not dumb. He opted for the acting job, too bad they did not give him lessons.

Anyhoo, even today, 2011, I imagine more likely than not they could not do it, could not pull off a manned lunar landing. WAY TOO DANGEROUS. NASA is incompetent, just read what Feynman has to say about those chumps....
 
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