Known Physics That Could Make Cold Fusion Possible?

Some of the sites recommended were not too depressing.

One of them triggered and old memory, about the kinetic ball toy, also called Newtons Cradle. The steel balls are at the apex of a triangular thread, which restricts their side to side motion. Their front to back motion is nearly frictionless.

Click Clack Click

Deuterium nuclei, all in a line. Their electron shells ringing like a bell.

Protons to Protons,
Protons to Neutrons ,
Neutrons to Protons,
Neutrons to Neutrons.

!0 E+2X Bells a ringing. Electron shells moving too an fro.

Kinetic reflections moving back and forth, can an atoms coulomb repulsion be made to have a wave like ringing function?

What if an atoms repulsion wave frequency is dependent on impacts from multiple sides. The wave waxes and wanes though the total amount of repulsion remains the same. A tide of force but incredibly sensitive to multiple impacts occurring at exactly the right time and from the right directions.

It isn't possible to test this in a plasma or a kinetic target since these are too random.

Is there a chord that will open natures secret garden?

The many Mathematical Probabilities tested in these dense Deuteron orchestras. It must be an orchestra.

A bell, the proton the bell, the neutron the clapper.

Just like ringing a bell.
 
One of them triggered and old memory, about the kinetic ball toy, also called Newtons Cradle. The steel balls are at the apex of a triangular thread, which restricts their side to side motion. Their front to back motion is nearly frictionless.

Kinetic reflections moving back and forth, can an atoms coulomb repulsion be made to have a wave like ringing function?

Nope. At the relevant velocities, atom-atom collisions are not frictionless in the slightest. Imagine a Newton's Cradle made not from steel but from baklava.
 
Some of the sites recommended were not too depressing.

One of them triggered and old memory, about the kinetic ball toy, also called Newtons Cradle. The steel balls are at the apex of a triangular thread, which restricts their side to side motion. Their front to back motion is nearly frictionless.

Click Clack Click

Deuterium nuclei, all in a line. Their electron shells ringing like a bell.

Protons to Protons,
Protons to Neutrons ,
Neutrons to Protons,
Neutrons to Neutrons.

!0 E+2X Bells a ringing. Electron shells moving too an fro.

Kinetic reflections moving back and forth, can an atoms coulomb repulsion be made to have a wave like ringing function?

What if an atoms repulsion wave frequency is dependent on impacts from multiple sides. The wave waxes and wanes though the total amount of repulsion remains the same. A tide of force but incredibly sensitive to multiple impacts occurring at exactly the right time and from the right directions.

It isn't possible to test this in a plasma or a kinetic target since these are too random.

Is there a chord that will open natures secret garden?

The many Mathematical Probabilities tested in these dense Deuteron orchestras. It must be an orchestra.

A bell, the proton the bell, the neutron the clapper.

Just like ringing a bell.
Is there supposed to be some meaning buried in this nonsensical gibberish?
 
Edited by Tricky: 
Edited for rule 12.
 
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Is there supposed to be some meaning buried in this nonsensical gibberish?

How about the gibberish you lice eating primates call Quantum Tunneling? (the term lice eating primates is not race prejudice, it is species prejudice:))

What happens to the screening electrons when an atom is hit from opposite sides simultaneously?

When you try to push two atoms together, the screening electrons decrease and repulsion increases.

What happens when a large atom (Say a Nickel atom held in a condensed matter vise) is pincered by TWO deuterons from opposite sides?

BOTH tunnel and a Helium nuclei is added to the Nickel.

This is S-process nucleosynthesis.

Hydrogen doesn't work because it doesn't have a neutron.

The neutron adds mass while NOT adding more charge, and is therefore more kinetic mass, without adding to the repulsion. A slower heavier bullet that can go through the same amount of repulsion.

Trying to add two hydrogen protons to a large atom isn't stable. Kinetically the proton mass is pure charge carrier, harder to get past the repulsion.

A deuteron atom is small and mobile and difficult to lock into a lattice vise.

So I see Deuteron-Deuteron fusion as unlikely.

A larger atom might go unstable, and kick out an Alpha particle, which might decay to tritium.
 
What happens when a large atom (Say a Nickel atom held in a condensed matter vise) is pincered by TWO deuterons from opposite sides?

The same thing that happens when it's hit from one side.

BOTH tunnel and a Helium nuclei is added to the Nickel.

No it doesn't.

The neutron adds mass while NOT adding more charge, and is therefore more kinetic mass, without adding to the repulsion. A slower heavier bullet that can go through the same amount of repulsion.

You can penetrate the nickel Coulomb barrier with a 2MeV deuteron (2amu moving at 0.045c) or a 2MeV proton (1amu moving at 0.063c). Doesn't matter, neither of these energies are obtained in room-temperature materials.

A larger atom might go unstable, and kick out an Alpha particle, which might decay to tritium.

:dl:
 
The same thing that happens when it's hit from one side.



No it doesn't.



You can penetrate the nickel Coulomb barrier with a 2MeV deuteron (2amu moving at 0.045c) or a 2MeV proton (1amu moving at 0.063c). Doesn't matter, neither of these energies are obtained in room-temperature materials.



:dl:
Why is the order of fusion with increasing energy Tritium-Deuterium, Deuterium Hydrogen, Hydrogen-Hydrogen, as if your opinion shapes the universe?
 
More gibberish.
I assume he's referring to the activation energy or energy barrier required to be overcome to allow nuclei to fuse. D-T fusion is the easiest to initiate, then D-D et cetera. The reasons are discussed in undergraduate physics, IIRC we covered it in second year.
DeathDart's post is just silly, he ignores 3He and 11B options and doesn't seem to be familiar with concepts such as the Lawson criterion or even understand electrostatic repulsion and nuclear binding energy which would answer his question quite easily.
 
I assume he's referring to the activation energy or energy barrier required to be overcome to allow nuclei to fuse. D-T fusion is the easiest to initiate, then D-D et cetera. The reasons are discussed in undergraduate physics, IIRC we covered it in second year.
DeathDart's post is just silly, he ignores 3He and 11B options and doesn't seem to be familiar with concepts such as the Lawson criterion or even understand electrostatic repulsion and nuclear binding energy which would answer his question quite easily.

It's obvious even to a layman like me that he has no clue about this subject. I'm learning from this thread though,keep it up.
 
I assume he's referring to the activation energy or energy barrier required to be overcome to allow nuclei to fuse. D-T fusion is the easiest to initiate, then D-D et cetera. The reasons are discussed in undergraduate physics, IIRC we covered it in second year.
DeathDart's post is just silly, he ignores 3He and 11B options and doesn't seem to be familiar with concepts such as the Lawson criterion or even understand electrostatic repulsion and nuclear binding energy which would answer his question quite easily.

Ok, let see for one, you are assuming that repulsion would be the same on opposite sides of an atom.

As a single Deuteron Nuclei approaches the target atom, the screening electrons might reorient to the opposite side. If the opposite side also has a Deuteron Nuclei approaching then the screening electrons might be forced to take intermediate positions or orbits that partially provide screening.

You make an assumption and I don't have to take your word on it.

Then an electron might hit the proton and you are trying to push 2 neutrons through.
 
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The force of Coulomb repulsion is mainly on the charged proton and not the neutral neutron. The force to be applied, is just get close enough for the nuclear forces to take hold, can be expressed as a velocity and a probability. The probability has to do with the probabilities for an exact in-line collision of the nuclei.

MV^2/2

Mass and velocity generate the force that will overcome the repulsion.

A single proton has less mass, but encounters the full amount of the repulsion, so it has to be moving faster to overcome the coulomb repulsion than would a Deuteron Nuclei with a proton and a neutron.

The neutron adds mass to the force that is applied without adding the full amount of repulsion that a another proton would add.
 
Then an electron might hit the proton and you are trying to push 2 neutrons through.

Scratch that, the electron is a De Broglie Wave not a Bohr Model. Isotopes can decay by electron capture, but not single protons.
 
Scratch the S process comment that is a high energy beta particle being absorbed by nuclei, not two separate Deuteron Nuclei entering a Nuclei from different directions.
 
Ok, let see for one, you are assuming that repulsion would be the same on opposite sides of an atom.

As a single Deuteron Nuclei approaches the target atom, the screening electrons might reorient to the opposite side. If the opposite side also has a Deuteron Nuclei approaching then the screening electrons might be forced to take intermediate positions or orbits that partially provide screening.

You make an assumption and I don't have to take your word on it.

Then an electron might hit the proton and you are trying to push 2 neutrons through.

[/lurk]
Oh my, so electrons have no fields and no quantum indeterminancy?

Are you sure the protons aren't involved somehow?
[lurk]
 

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