You missed the point entirely.
Except that in E=mc2, E and m do not have the same units. The fact that c is not unitless is required for equality. If you multiply a volume by c2, what you end up with will not be a volume, just as if you multiply m by c2 you don't get a mass. And if you use units other than SI, c2 won't even be 9x1016 m2/s2. All you're doing is demonstrating that you really don't understand units. You could try to prove me wrong by doing the calculations with units, but I know you won't. You will avoid doing any math at all.
No I'm afraid you are the one with a definition problem here. SR ;provides absolutely NO physical basis for it's mathematical relationships. i.e. - HOW does space-time interchange - that would be a physical theory. Not merely HOW mathematically as a relationship.
AND no I do not and have not disregarded the number of times Dr Licoln and I disagree. But I also note just as here Dr Lincoln often asserted I didn't understand or that I misunderstood something which I actually did or do know.
But I disagree with emphatically and in some cases what you claim SR says isn't what SR actually is. So the confusion here is not my lack of knowledge about what is claimed but your lack of understanding the objection.
That may well me as much my fault in presentation but also in part due to your (not you personally) inability to think outside the formal mathematical confines of relativity.
You haven't been explicit enough for him, Zig. You know what Dorothy Parker said about horticulture.
MacM:
In classical physics, there's only 3 dimensions we actually measure. There's length, and mass, and time.
Some concepts are useful enough that we chunk them together and give them a name. Speed, for example. Speed, whether it's in miles per hour or meters per second, is always in the same dimensions of length divided by time.
We can express energy in different ways; we speak of Joules, and kilowatt-hours, and horsepower-hours, and so on.
But all of these different terms actually have the same dimensions.
The dimensions of energy are mass * length * length/(time * time)
A Joule, then, is 1 kg (m^2)/(s^2).
A kilowatt-hour is 3 600 000 (kg (m^2)) / (s^2)
A horsepower-hour is a little more non-obvious and irritating to work out, because of the awkwardness of the implied acceleration in using lbs-force in the definition.
A horsepower is defined as 33000 ft-lbsforce/minute.
So a horsepower-hour is that times an hour.
(33000 lbs mass x 1 ft (for the foot-pounds) x 32ft/sec^2 (to find the force exerted by 1 lb mass)/ 1 minute) x 60 minutes in the hour.
And when you look at the dimensions of the answer, it's in lbs mass x ft ^2 x sec^2.
Dividing by minutes in the horsepower definition is canceled by multiplying the 60 minutes in the hour of the horsepower-hour definition.
So we're left with lbs mass, a foot from the foot-pounds, a foot from the implied acceleration of pounds force, and the 1/sec^2 of that same implied acceleration.
The dimensions are (mass x len x len)/(time x time)
So look at the
dimensions of the right hand side of E = mC^2.
m is mass. C has dimensions of length/time. So the dimensions are:
mass x length/time x length/time, which rearranged, is mass x length^2/time^2
If Einstein had multiplied those quantities together and tried to claim they were anything but energy, we would never have heard of him.