The question assumes the calculation. There is no independent data that can falsify that conclusion. As you suggest, a simple arithmetic exercise.I just want to be clear on this, humber. You are saying that there isn't enough information for you to answer my first question? I'm only asking a question to see if you can do some math like you say you can. Providing a proof of the amount of force available is futile if you can't follow along.
Well maybe, Mender, but not like this.My technique is better expressed as attempt an explanation only for you either to ignore it because you don't understand it, or flatly and without any logical (to people in the real world) reason, deny that it has any relevance because it doesn't talk about KE.
I understand enough to anticipate the answer from the first line, Mender.
Easy: look up Newton's first law.
Har-har, "assume no air drag". The BMW team is testing the movement of air over their cars. When they want to include the effects of the tires turning, they start the treadmill. Obviously they know a lot more about what they are doing and what they are testing than you do.
That will not be useful. The real load on the tires is much higher than that.
Rolling and load resistance are complicated, and variable.
They use 2 or 3 sets in an F1 race.
Mender... really. I can run rings around your math skills.Here's the question again. If you can;t get an answer using the information provided, you won't be able to follow my proof, as it requires a working knowledge of numbers and such.
I oppose its general use, because it is so often a bluff, and it leaves out those without the necessary skills. In this forum 100% bluff, and entirely cookbook examples.
The proof is important, Mender, because even a calculator can add up.
There are countless internet applets to do any calculation, but the reasoning, is not wikkiable.
"I will ask you to consider the following scenario that makes use of normal physics. Remember that the ground is considered to be flat and smooth.
A fishing reel with lots of line is attached by a scale to the ground. The other end of the fishing line is attached to a sail cart. The sail cart with a fishing line attached to it is released in a 10 mph wind. It reaches 9 mph, losing 1 mph because of rolling resistance.
The simplest but entirely incorrect assumption, is to make that 1mph/"unit of drag"?
You apply the brake on the fishing reel to slow the cart down to 8 mph and read the amount of pull (force) on the scale. Let's say it reads 100 grams. Based on these numbers, what is the rolling resistance of the cart when it is traveling at 9 mph in a 10 mph wind?
The entirely wrong the answer you seek may be:
So drum roll.......one unit of drag = 100grms.?
Is that what you mean?
Terrible, Mender.
(1)You are trying to plot a velocity/force profile, based on two data points, and on the assumption that you already know it. Not logical.
You still no not know the correct answer, because you do not know that load line.
(2) When under braking load, the "rolling resistance" becomes a loaded resistance.
Now you slow the cart to 6 mph. What is the reading on the scale now?"
Just for the record, and before I post the answers and without anyone else posting answers, does anyone else feel that there isn't enough information to answer the questions?
No, it is not 300gram .