If the speed is not high enough in a turn then the plane will desend, if it is too high the plane will rise through the turn. If the speed is less the g's will also decrease.
Well, to keep it in simple terms let's keep the speed a constant. When the aircraft banks to X degrees and commensurate G force for the bank angle is applied it will turn because the angle of attack increases and the vertical lift component is shifted in a lateral direction resulting in a turning moment. For 60 degrees of bank in ANY fixed wing aircraft the equivalent G for a level turn is 2. If more than 2 G's are applied the aircraft will climb
AND TURN at the same rate as level or greater. Thrust/Power must be increased in order to maintain a constant speed. Now, if less than 2 G's are applied at 60 degrees angle of bank, the aircraft will enter a descent,
BUT IT WILL NOT TURN at the same rate as when level, it will achieve a lesser rate of turn because the angle of attack has decreased and the vertical lift component shifts forward, not as much laterally as when level. Thrust/Power must be decreased to maintain a constant speed. In this descending turn at a constant speed as well as a a constant rate of descent is normally eventually achieved. At this point when speed, angle of bank, and rate of descent are constant; 2 G's must be applied to achieve the same rate of turn as when in level flight.
This is the expanded explanation based on my understanding of Beachnut's comments and the comments here. This is about as simple as I can make realizing it is not that simple for non aeronautical types.
All of these forces discussed are variable, but it would take pages and pages of explanation to examine all of the variables in combination with each other. This is what flying and the study of aeronautics involves.
Wing lift is traded off to turning the aircraft. CIT, and probably many on pft , probably think that the rudder is soley responsible for changeing the heading of the aircraft.
Yes, that's precisely why I included a brief aeronautics lesson regarding turns in the original article. All the rudder does is coordinate the yaw axis to the changing forces around the other axis of the aircraft.
If the plane was at the height of the VDOT tower as it passed by it and 70 agl as it went over the Citgo how much altitude would it lose? Now one has to ignore the 780 fps and determine the bank angle, speed and centrepetal 'g' force that will allow a desending turn such as that.
In the previous scenarios, a descent was not factored into the calculations in order to keep it simple. A descent would actually make the turn problem
MORE IMPOSSIBLE simply because time to turn (rate of turn) would be sacrificed by decreasing the angle of attack which would move the vertical lift component more forward rather than laterally as it would be in a level turn. I posted the best case scenario to make a turn possible in the original article.
If they want to decrease the speed because the FDR Data is fraudulent for the North of the Citgo path, then they also have to decrease the speed equivalently in the DME video for the accepted Southerly approach. At this point it all becomes speculation, doesn't it?
Hehehe, what will happen if we reach the point where the FDR data is rejected and then what will CIT and pffft do? They no longer have a reason to exist? No viable theories and no facts, but that's what they are all about anyway, isn't it?