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DIY experiment proving graviton is a particle

theprestige said:
My dude you could take these measurements tomorrow morning at Mount Royal or Savane no problem.

But maybe it's better if you wait till summer. That way you don't have to wake up so early, on the day you change the world.
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Yeah ok thanks. Tomorrow is Saturday so it's all good with me.

Actually during the winter is better because the Sun rises later...
 
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theprestige said:
Even the most ignorant astrophysicist can figure out where the sun is, when it's below the horizon.

You can't even do basic astronomy, and you're claiming you're going to discover gravitons first thing tomorrow morning?
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I live on the 3rd floor of a condo complex. There is gravitational interference below me.

The ground noise is about 0.00001 g.
 
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philippeb8 said:
I live on the 3rd floor of a condo complex. There is gravitational interference below me.
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So? Go downstairs. Step out onto the street. Point your phone at the sun. Do the same tomorrow during the day. Change the world. Why are you typing at me instead of taking measurements?

Hell, why do you not already have these measurements?
 
philippeb8 said:
I live on the 3rd floor of a condo complex. There is gravitational interference below me.

The ground noise is about 0.00001 g.
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According to my earlier estimates then the Sun's g on the surface of the Earth is:

- Sun's g: G*1.9885e30/(1496e8^2)/9.8 = 6e-4

So it should be greater by 1 order of magnitude. Pretty tight but possible.
 
philippeb8 said:
Because I want to do it correctly and I need some stability and irrefutable first round experimentation, just like the GEM experiment.
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So if I see a shift then I will be grateful and give back to you theprestige and Captain_Swoop for your constructive comments after or meanwhile my 3 experiments all put the nail in the General Relativity coffin.
 
112 posts and no one has bothered to google the idea. If they had they would have found this https://en.wikipedia.org/wiki/Graviton
In theories of quantum gravity, the graviton is the hypothetical quantum of gravity, an elementary particle that mediates the force of gravitational interaction. There is no complete quantum field theory of gravitons due to an outstanding mathematical problem with renormalization in general relativity. In string theory, believed to be a consistent theory of quantum gravity, the graviton is a massless state of a fundamental string.
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Or maybe this
https://www.quantamagazine.org/gravitons-revealed-in-the-noise-of-gravitational-waves-20200723/
Many physicists assume that gravitons exist, but few think that we will ever see them. These hypothetical elementary particles are a cornerstone of theories of quantum gravity, which seek to unify Albert Einstein’s general theory of relativity with quantum mechanics. But they are notoriously hard — perhaps impossible — to observe in nature.
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WhatRoughBeast said:
On the other hand, objecting to his experiment because you can't directly measure gravitational acceleration of a body in free-fall is clearly wrong. What is being measured is the attraction of the earth minus the attraction of the sun (when the sun is visible) vs the attraction of the earth minus a diminished attraction of the sun (due to absorption of gravitons during an eclipse).
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No - you can't measure the total attraction of the Sun on the Earth's surface by any sort of strain gauge accelerometer or absolute gravimeter because the Earth is in free-fall. You can measure the acceleration due to the Earth's gravity at the Earth's surface. The same thing goes for the Moon.

What you can measure at the Earth's surface is the tidal force of the Sun's or Moon's gravity (the difference in the gravitational force depending on the position of the Sun or Moon - whether it is overhead or directly below your feet for example). The magnitude of the respective tidal gravity is much less than the absolute gravity of the Sun or Moon.
 
philippeb8 said:
According to my earlier estimates then the Sun's g on the surface of the Earth is:

- Sun's g: G*1.9885e30/(1496e8^2)/9.8 = 6e-4

So it should be greater by 1 order of magnitude. Pretty tight but possible.
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No - you cannot measure the Sun's g at the Earth - only the Sun's tidal force which is 5.15e-8 g.
 
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