Mojo
Mostly harmless
This might be a good time to consider actually reading the many responses you've had in this thread. Including the ones that point out that "thing" and "process" are not the same.
Including the ones you just quoted, Jabba.
This might be a good time to consider actually reading the many responses you've had in this thread. Including the ones that point out that "thing" and "process" are not the same.
230
232 236 239
291
Dave,
- In other words, there is a "thing," or process, that is exhibited in you that would not be exhibited in a perfect copy of you (see 232-239, above).
- In most humans, this process "cares, and it "senses, or imagines, a continuation that it would like to continue. You seem to be saying that such care is just an illusion and nothing to be concerned about -- i.e., it needn't be considered in our ethics.
In other words...
...there is a "thing," or process...
that is exhibited in you...
that would not be exhibited in a perfect copy of you (see 232-239, above). I've been calling that your particular self-awareness.
Do you have a name for it?
In most humans, this process "cares, and it "senses, or imagines, a continuation that it would like to continue. You seem to be saying that such care is just an illusion and nothing to be concerned about -- i.e., it needn't be considered in our ethics.
I agree. I'd challenge anyone who sticks to this Texas Sharpshooter Fallacy explanation to explain what is wrong with the following argument (or any other such argument) where I condition on my own existence in the second statement:
If my parents hadn't met then I wouldn't exist.
I exist.
Therefor, my parents have met.
Consider this cartoon drawing of the joint hypothesis–sample space, where E is the event "I, Jabba, exist," and H and ~H are two hypotheses about how Jabba came to exist. If I could draw the cartoon to scale, the oval representing E would be invisibly small, at least on the side of the cartoon representing the so-called scientific, or random, hypothesis.
[imgw=300]http://www.internationalskeptics.com/forums/imagehosting/5305557c62d342a7d0.png[/imgw]
But if Jabba is conditioning on his own existence, then his joint space is reduced to the oval:
[imgw=300]http://www.internationalskeptics.com/forums/imagehosting/5305557c62d344927e.png[/imgw]
Conditioned on his own existence, the probability of his existence is 1 under either hypothesis. Hence, the observation that he exists is not evidence for either hypothesis over the other.
These cartoons also illustrate the connection between conditioning on E and the Texas sharpshooter fallacy. All the events outside of the oval—the target—are ignored.
Only because H|E = ~H|E in your diagram. Please do it again but this time draw it such that H|E >> ~H|E and you will see the error with your reasoning (the highlighted "hence") here. Yes, the observation that he exists is not evidence for either hypothesis over the other but it is not because conditioned on his own existence the probability of his existence is 1.
I should have been clearer. I am not saying that P(H|E) = P(~H|E).
What I'm saying is that P(E|H,E) = P(E|~H,E) = 1.
Hence, the evidence does not discriminate between H and ~H
and therefore the posterior probabilities of the hypotheses equal their prior probabilities.
Then your argument is certainly incorrect. Let's refer back to my parents having met:
Let H be "my parents have met"
Let ~H be "my parents have not met"
Let E be "I exist"
Let P(H|E) = 0.9999[*]
Let P(~H|E) = 0.0001[*]
Let's go through your statements one by one:
P(E|H,E) = P(E|~H,E) = 1. Or in words, the probability that I exist given that my parents have met and that I exist equals the probability that I exist given that my parents have not met and that I exist, both of which equal 1. This is true - trivially so in fact, the probability of an event conditioned on itself is always 1 irrespective of the event being "I exist" or anything else.
Hence, the evidence that I exist does not discriminate between my parents having met and my parents not having met. Clearly this argument is starting to go wrong here.
And therefor the posterior probabilities of the hypotheses, about my parents having met or not, equal their prior probabilities. Nope, this is not a correct conclusion.
Are you seeing the error you are making?
* I'd rather put 1 and 0 but then we'd get a division by zero error in P(E|~H,E), so let the small discrepancy stand for the possibility of artificial insemination from an anonymous sperm bank or something.
Exactly. The mere fact that you exist does not discriminate between different hypotheses with non-zero probabilities about how you came to exist.
- In other words, there is a "thing," or process, that is exhibited in you that would not be exhibited in a perfect copy of you
There should be a "speechless" emoticon on this forum.
There are two persons, person1 and person2. Let H be "person1 and person2 have met". Can you give an estimate of the prior P(H)? And remember that you can not use the information that I exist as the child of person1 and person2 in constructing your estimate, that information will only come later.
- In other words, there is a "thing," or process, that is exhibited in you that would not be exhibited in a perfect copy of you (see 232-239, above).
i.e., it needn't be considered in our ethics.
Describe the joint sample–hypothesis space of the experiment you have in mind.
H = "my parents have met"
E = "I exist"
Here's a visual diagram (approximately to scale):
[qimg]http://www.internationalskeptics.com/forums/picture.php?albumid=1305&pictureid=11185[/qimg]
Jesus, it took me a whole afternoon to do my graphics, and I still couldn't get the line off center. I'm about to have dinner. I'll get back to this.
H = "my parents have met"
E = "I exist"
Here's a visual diagram (approximately to scale):
[qimg]http://www.internationalskeptics.com/forums/picture.php?albumid=1305&pictureid=11185[/qimg]
I just used Paint (on windows), draw a rectangle and draw an ellipse, takes less than a minute in total. Anyway, enjoy the dinner.
Actually, I can comment on this now. If that's your sample space, then you're not committing the fallacy of conditioning on the observation.
Only because H|E = ~H|E in your diagram.
It's the same sample space as yours above but with E moved a bit to the side to account for my earlier objection:
- Am I wrong about that?Dave,
- In other words, there is a "thing," or process, that is exhibited in you that would not be exhibited in a perfect copy of you (see 232-239, above)...