Vixen
Penultimate Amazing
This post is intended as an investigation of what can be learned about the window breakage using elementary Newtonian physics. The specific goal is to estimate a minimum velocity the rock would need to break the window and produce a distribution of shards within the room.
The first task of a rock thrower seeking to break a window, or a baseball pitcher aiming to strike out a batter, is to get the thrown rock or baseball to the target area, which is some distance away. For the baseball pitcher, this means getting the ball within the strike zone over home plate - a distance of 60.6 feet (about 18.4 meters) from the pitcher's plate on the pitching mound. For the rock thrower, this means throwing a rock of mass 4 kg from his position on the rampart facing Filomena Romelli's window to the window 3 meters (about 10 feet) away, with enough velocity for the rock to break the window.
One important principle of physics many of us learn from experience is that if one is throwing an object to reach a target some distance away, the object must be thrown hard enough – that is, for it to go fast enough – to cover the distance. Otherwise, the object will fall to the ground (or floor, if one is indoors) before reaching the target, because of earth's gravity.
Elementary Newtonian physics gives a method to calculate what the minimum velocity the thrown object must have to reach the target. The method is based on the observations that the time required for a thrown object (with a non-zero velocity relative to the earth's surface) to fall is the same as the time required for that object (with no velocity relative to the earth's surface) to fall, when air resistance (drag) and lift are negligible, or may be ignored. The situation of the object falling only under the force of gravity is called free-fall and the method is summarized online in:
http://www.physicsclassroom.com/class/1DKin/Lesson-6/Kinematic-Equations-and-Free-Fall
Assumptions
1. The rock thrower is, of course, tall enough and with a good enough throwing arm to accomplish the task. The rock is thrown over-hand, with the arm extended above the head, and gripped somewhat like an American football rather than a baseball, with the ground of the rampart a distance d = -2 m from the vertical position of the rock when it is launched.
2. The effects of air resistance (drag) and lift, if any, on the rock will not be considered for the first estimate.
3. The acceleration of gravity near the earth's surface, g, is the generally used value: g = -9.8 m/s^2; see: https://en.wikipedia.org/wiki/Gravity_of_Earth
4. The rock must travel a minimum horizontal distance L = 3.5m; this value of L includes a “safety factor” of 0.5m intended to assure that the rock has enough horizontal velocity to penetrate the window glass at 3.0m from the thrower. The value of 3m is from the testimony of Marshal Francesco Pasquali.
Calculation of the free-fall time, t
t = square_root(2d/g)
t = square_root(2*(-2m)/(-9.8m/s^2))
t = 0.639s
Calculation of the average horizontal velocity, v_r-h-avg of the rock
v_r-h-avg = L/t
v_r-h-avg = 3.5m/0.639s
v_r-h-avg = 5.5m/s
Thus, the minimum horizontal velocity of the rock at launch, assuming negligible air resistance on the rock in its short flight, is the modest value of
5.5m/s = 19.7km/h = 12.3miles/h.
While Marshal Pasquali apparently did not measure the rock's velocity in his 3 test trials performed from 3m away from the test window, the window was indeed broken on each trial, and the glass shard pattern produced in the room was qualitatively similar to the one in Romelli's room as photographed by the police. Marshal Pasquali's work by itself establishes that there was no objective support for the allegation of the police that the break-in had been staged with the rock thrown within the room.
Someone throwing over arm is not using horizontal velocity.
Interesting you refer to gravitational force as when I gave you the equation for this, you claimed to be baffled and had to resort to Shakespeare.