Slowvehicle
Membership Drive , Co-Ordinator,, Russell's Antin
Same MO as in the Holy Tablecloth I, and II threads...
And it has been pointed out to him over and over.
And it has been pointed out to him over and over.
- You're right. I'll have to get back to that...I don't see anything there about using the number of people who hold the belief as the basis for assigning the probability.
- You're right. I'll have to get back to that...
- You're right. I'll have to get back to that...
How about skipping that for now, and instead explaining why a low probability outcome occurring casts doubt on a hypothesis that predicts low probability outcomes?
I'd suggest making a list.
Humots,That's what you claim.
What is your reason, your basis, your justification, your support for that claim?
How is "the likelihood that I would currently exist would be close to zero" a logical consequence of "each potential “self” has only one finite life to live (at most)"?
Humots,
-- Now, imagine a die with 1080! faces, and "me" is one of the faces. What is the likelihood that the top face of the die, when rolled, would be "me"?
Humots,
- Assuming that I understand your question...
- If I have have a 6-sided, and "fair," die and roll it, the likelihood that the top face would be 3 is 1/6.
- Now, imagine a die with 1080! faces, and "me" is one of the faces. What is the likelihood that the top face of the die, when rolled, would be "me"?
- Sure.How about skipping that for now, and instead explaining why a low probability outcome occurring casts doubt on a hypothesis that predicts low probability outcomes?
- Sure. That’s exactly what I wanted to do. See below.How about skipping that for now, and instead explaining why a low probability outcome occurring casts doubt on a hypothesis that predicts low probability outcomes?
Put a different way, here’s what I think. Maybe this way will communicate. I’ve made a few changes.
1. The proper formula to use in determining the post-probability of “A,” given “me” is
P(A|me) = P(me|A)*P(A)/(P(me|A)*P(A)+P(me|~A)*P(~A)).
1.1. “A”: the hypothesis that any potential “self” has only one, finite, life to live` -- at most.
1.2. “me”: the current existence of my, specific, self.
1.3. “~A”: the hypothesis that “A” is not true.
2. My basic claim is that my own current existence makes the post-probability of “A” teensy-weensy.
3. To reach that conclusion, I claim that the likelihood of my, specific, current existence -- given “A” – P(me|A) -- is, at most, 1/1080!.
4. The only real issue here is whether or not I can correctly use that figure as the P(me|A) in this formula … even if I’m right about that figure. 5. In a way, the answer to that question is, “Why, the Hell not?!” Isn’t that the very definition of P(me|A)? 6. Unfortunately (for my side), the answer is, “No -- the word ‘specific,’ in 1.2., may not belong.” 7. We need to show that it does belong. If we can’t, the “plug-in” should be 1.00…
8. If you guys can agree with my analysis so far, I’ll try to show why 1/1080! does belong.
Humots,
- Assuming that I understand your question...
- If I have have a 6-sided, and "fair," die and roll it, the likelihood that the top face would be 3 is 1/6.
- Now, imagine a die with 1080! faces, and "me" is one of the faces. What is the likelihood that the top face of the die, when rolled, would be "me"?
- Sure. That’s exactly what I wanted to do. See below.Put a different way, here’s what I think. Maybe this way will communicate. I’ve made a few changes.
1. The proper formula to use in determining the post-probability of “A,” given “me” is
P(A|me) = P(me|A)*P(A)/(P(me|A)*P(A)+P(me|~A)*P(~A)).
1.1. “A”: the hypothesis that any potential “self” has only one, finite, life to live` -- at most.
1.2. “me”: the current existence of my, specific, self.
1.3. “~A”: the hypothesis that “A” is not true.
2. My basic claim is that my own current existence makes the post-probability of “A” teensy-weensy.
3. To reach that conclusion, I claim that the likelihood of my, specific, current existence -- given “A” – P(me|A) -- is, at most, 1/1080!.
4. The only real issue here is whether or not I can correctly use that figure as the P(me|A) in this formula … even if I’m right about that figure. 5. In a way, the answer to that question is, “Why, the Hell not?!” Isn’t that the very definition of P(me|A)? 6. Unfortunately (for my side), the answer is, “No -- the word ‘specific,’ in 1.2., may not belong.” 7. We need to show that it does belong. If we can’t, the “plug-in” should be 1.00…
8. If you guys can agree with my analysis so far, I’ll try to show why 1/1080! does belong.
- Sure. That’s exactly what I wanted to do. See below.
Humots,
- Assuming that I understand your question...
- If I have have a 6-sided, and "fair," die and roll it, the likelihood that the top face would be 3 is 1/6.
- Now, imagine a die with 1080! faces, and "me" is one of the faces. What is the likelihood that the top face of the die, when rolled, would be "me"?
Humots,
- Assuming that I understand your question...
- If I have have a 6-sided, and "fair," die and roll it, the likelihood that the top face would be 3 is 1/6.
- Now, imagine a die with 1080! faces, and "me" is one of the faces. What is the likelihood that the top face of the die, when rolled, would be "me"?