The parts of the upper section may not be destroyed, but will be destroyed and that is the beginning of the collapse arrest.if the lower floors of the upper section causes damage to the floors below, guess what is going to happen when the rest of the upper section plows through.
Only temporarily. As the strcutures below fail they can no longer provide any resistance to the mass of the upper section. And there is still the potential energy due to gravity.The destruction of the upper section will, i.a. cause deceleration.
That is stupid. If the structures have failed they can no longer provide resistance to the upper section. If they have failed to the point where they are free to move gravity will pull them into the lower floors causing yet more damage.Sure, the mass is still there but it has been slowed down and is in pieces rubbing against each other and friction and further local failures take care of the rest.
Friction of the parts of the upper mass rubbing against each other does not subtract from the kentic energy of the mass moving down. That is like saying two choppsticks that are falling towards the floor will slow down if they are rubbing up against each other. Is that what you are impling or have I missinterpreted something?
You still don't understand why your matchbox experiment is silly and does not relate to reality. It has everything to do with the structural integrity and arrangement of components of the buildings and the forces involved as the masses are moving into each other.All energy available is used up So nothing will continue to impact anything. Physically impossible even if Bazant and NIST suggest the opposite. Sorry that the Match Box experiment didn't teach you that. You have completely misunderstood what gravity does. It terrorizes me!
What frightens me is your apparent lack of simple physics and yet you are employed as a engineer.
There's some temporary deformation, sure. Absolutely.
But it's temporary, because the matchboxes have the strength and elasticity to recover. Correct?
Now, what would happen if the matchboxes weren't as strong?
Heiwa, I am waiting to hear about your findings on the news. When is it going to happen?
Don't you understand that the matchboxes are capable of sustaining the forces involved?Not at all. You cannot refute reality. In the original Match Box Experiment you drop one Box on a tower of ten Boxes! Very real and easy to do.
By careful observation you notice the deformations of the two objects at contact and observe that the dropped box is deformed X mm and that the 10 boxes are also deformed X mm. The deformation is then reduced as the single Box bounces up. The energy transmitted at contact causing the deformations is transformed into other types of energy. The dropped box motion is arrested.
Again, the match boxs are structuraly capable of sustaining the forces involved. The forces you are using in your matchbox experiments are on many magnatudes less than what the WTC had to sustain in relation to scale. There is no comparison between the matchboxes and the WTC towers. If you cannot see that you are truly hopeless.In the revised Experiment you drop an assembly of ten Boxes on one Box. Also easy to do.
Now the energy involved is 10 times bigger. By careful observation you notice the deformations of the two objects at contact and observe that the dropped ten boxes are deformed 10X mm and that the single box also deforms 10X mm. The deformation is then reduced as the 10 boxes being dropped bounce up. Energy is transformed from one state to another as explained before.
That is an oversimplification. You are forgeting about structural integrity, Load capacities, structural design, avenues for progressive collpase, etc.Thus, whatever you drop on anything is affected at contact and the bigger object is always less affected than the smaller object. Just keep your eyes open and observe carefully.
Wow, now you are just making things up.Bazant and Nist close their eyes and assume (conveniently, lazy?) the opposite and suggest that whatever you drop becomes SUPERSTRONG, rigid, and affects (read destroys) anything below it, while it itself is not affected at all by the contact. Global collapse thus ensues ... whenever you drop a object on anything. In any scale!
I fear for your clients. Especially considering you Pizza box and matchbox experiments.Such stupidity really terrorizes me. On whose side are they? OBL's?
But it is not gravity that does it - it is the inclined plane. Or more correct, not shown, the force that the inclined plane applies to the object perpendicular to the inclined plane.
Re water flowing downhill, it is only due to the force that downhill applies to the water. If no downhill, the water would drop ... like rain assuming gravity is strong enough!
That is stupid. If the structures have failed they can no longer provide resistance to the upper section.
What news? Fox? CNN? ABC, NBC? You must be joking. News?
No, he didn't say that. He says that air friction is negligible when a debris comes down, because a WTC debris is mooooooooooooooore heavier than a paper sheet.According Bazant friction does not exist in global collapses!
So, what you're admitting here, is that depending on the direction of the resistance to the force of gravity, there can be a horizontal component to the acceleration vector of a falling object.
Thanks.
I had to snip out a lot or rambling to get to the pith of it.
No, he didn't say that. He says that air friction is negligible when a debris comes down, because a WTC debris is mooooooooooooooore heavier than a paper sheet.
Minadin's schema is somewhat incomplete; here's a better one:
[qimg]http://pagesperso-orange.fr/laurent.buchard/CroquisLaurent/croquis4.gif[/qimg]
The three forces that are needed are represented. This is called "principle of inertia". It's a base of Newton's physics. And you aren't able to understand basic physics that students learn in high school. How shameful.
Air friction? Yes it is negligible. But we talk about friction between parts like columns, beams, floors rubbing against each other and that is considerable. And Bazant ignores it.
No, wrong.At contact there is deformation. Sure. Deformation is there, as long as there is contact. Everywhere.
Wrong.No, the deformation is not temporary.
Or none at all.It varies due to the energy applied during contact and is different in various locations; more deformation close to the contact point, less deformation far away from the contact point.
Or it can be elastic throughout the structure.It means that the deformation can become permanent in certain locations, even resulting in failures, close to the contact point and can be just elastic in other locations, far from the contact point.
Yes indeed.Same thing happens when the matchboxes are less strong.
You still have the force of gravity bearing down. Gravity never switches off.And when the energy applied has produced the relevant deformations and failures, the action stops.
That is what permanent means, yes.Permanent deformations and failures then remain.
Build a matchbox 1000 times as large in all dimensions, and it will instantly collapse under its own weight.Scale does not matter.
No, you can't be sure of that. Not only that, but a destroyed matchbox has the same weight as an undestroyed matchbox, and can be used to destroy other matchboxes.You can be sure that the single match box dropping on the 10 boxes will be destroyed before the 10 boxes.
What if they're not strong enough?Of course, in this experiment the boxes have same strength, so it is the single box dropping and the uppermost box of the 10 boxes that get destroyed first ... and that's it - if strength is not sufficient. The nine other boxes just deform elastically
Quite absurd, actually.In WTC1 the upper part is evidently weaker than anything below that carries it, so it is destroyed first at contact. Quite basic, actually.
You keep claiming that there is not enough energy available. NIST shows that you are wrong.To confuse the public, Bazant assumes that the upper part is stronger than anything below - he makes the top part rigid - and then, and only then, global collapse may take place without destroying the upper part first and if there is enough energy available. But there is not enough energy available.
No, and in any case, irrelevant.And if there were enough energy available, it would destroy the upper part first.
Yep. He's taken a statement that is true for certain structures under certain conditions, and asserted that it is true for all structures under all conditions, in defiance of mathematics, physics, engineering, and reality in general.You've oversimplified it beyond any reasonable measure...
Not too bad. But P + R = F can also be 0, i.e. the object does not move at any angle alfa. Solve it for alfa = 90°! Explain why object does not drop straight down!
Alpha = 90°, the slope does not apply any force R to the object, P equals practically F (plus some negligible air friction).
Go back to school.
You have all sorts of materials and failure modes going on, and even if the upper part is "destroyed", it weighs just as much as it did before and is applying just as much force as it did before.
No. Although there will be a non-negligible air friction, gravity applies a bigger force. A glued object interacts each other with the wall he's stuck to.But imagine now that the object still does not drop in spite of alfa = 90°. It is possible if the object is glued to the inclined plane = very big friction.
Because the glue interacts with the ceiling and the object...Do same with alfa = 180° (object glued to ceiling)! Why doesn't the object drop due to gravity?