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why Nuclear Physics cannot be entirelly correct

pedrone said:
Is this sum of the intrinsic magnetons produced by their spin ?
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Spin and charge, yes.

Is a spin of the proton such orbital angular moment of the quarks ?
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No, the spin is the sum of the intrinsic AND orbital angular momenta of the quarks and gluons. The gluons contribute to the angular momentum but not to the magnetic moment.
 
Ziggurat said:
Um... you do know that people can check that, don't you?



Oops.
Click to expand...
Ok, a mistake of mine.

Then let's correct it:

1- The interaction proton-neutron occurs through the strong nuclear force, which is 100 times stronger than the electromagnetic interaction.

2- The spin-interaction of nucleons is electromagnetic, and so a spin-interaction is 100 times weaker than a strong force interaction.


A type-written error of mine cannot save Nuclear Physics
 
Originally Posted by pedrone View Post
Is this sum of the intrinsic magnetons produced by their spin ?


ben m said:
Spin and charge, yes.
Click to expand...

Therefore, as the sum of the intrinsic magnetons are produced by their spin, this means that the magnetic moment of the proton is produced by spin

Is it correct ?
 
pedrone said:
Is this sum of the intrinsic magnetons produced by their spin ?
Click to expand...

A magneton (which, BTW, is rather meaningless without further specification) is not a thing. It's a unit. Nothing more.

Angular momentum is the fundamental property of spin, NOT magnetic moment. That is why the units of quantization for angular moment are the same for all particles. But the units for quantization of magnetic moment are NOT the same for all particles. They're different. That's why we have Bohr magnetons and nuclear magnetons, for example. These are just units, and they're not even the same units, because magnetic moment is not fundamental. It is a secondary characteristic.

Look up gyromagnetic ratio if you want to learn more.
 
pedrone said:
Therefore, as the sum of the intrinsic magnetons are produced by their spin, this means that the magnetic moment of the proton is produced by spin

Is it correct ?
Click to expand...

No. The magnetic moment of the proton is generated by to both the intrinsic spins of the quarks, and the orbital angular momenta of the quarks.
 
ben m said:
No. The magnetic moment of the proton is generated by to both the intrinsic spins of the quarks, and the orbital angular momenta of the quarks.
Click to expand...

and therefore the intrinsic spins of the quarks and the orbital angular momenta HAVE THE SAME MAGNITUDE for the production of the magnetic moment.

Is it correct ?
 
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pedrone said:
:D:D
Oh my god
:D:D

We are not interested in Pauli Principle

The question here is: what is the magnitude of the spin-interaction???

Dont you understand it yet ?
:p:p:p
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I'm interested in how fast cars can drive, but I'm not interested in car engines.

There's a glaring flaw in your post. Can you spot it? Hint: I just gave you a hint.
 
Ziggurat said:
I'm interested in how fast cars can drive, but I'm not interested in car engines.

There's a glaring flaw in your post. Can you spot it? Hint: I just gave you a hint.
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Zig,
Pauli Principle is OTHER consequence of the spin, which does not matter here.

Pauli Principle does not depend on the magnitude of the spin-interaction.
No matter what is the magnitude of the spin-interaction, Pauli Principle holds

However, a spin-interaction with the magnitude of the magnetism cannot influence a strong-interaction, which is 100 times stronger than magenetism
 
pedrone said:
Oh my God !!!
A nuclear physicist that knows nothing about basic nuclear physics
:D:D:D:D:D:D
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Oh my God !!!
A random poster that imagines he can read my mind, (and is deluded into thinking that I am a nuclear physicist!) and that knows nothing about basic nuclear physics
:D:D:D:D:D:D

P.S. I am actually an (ex) solid state physicist who knows how to read. I suggest you learn (see below) :D

pedrone said:
That's why I dont want to waste my time with lay man
Such spin-orbit interaction is regarding the ATOM, which has nothing with the NUCLEUS
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There is the atomic spin-orbit interaction.
There is the nuclkear spin orbit interation.
They are both interatctions of spins with orbits.
One is regarding the ATOM.
One is regarding the NUCLEUS.
Try reading what is quoted: spin-orbit interaction
In quantum physics, the spin-orbit interaction (also called spin-orbit effect or spin-orbit coupling) is any interaction of a particle's spin with its motion. The first and best known example of this is that spin-orbit interaction causes shifts in an electron's atomic energy levels due to electromagnetic interaction between the electron's spin and the nucleus's magnetic field. This is detectable as a splitting of spectral lines. A similar effect, due to the relationship between angular momentum and the strong nuclear force, occurs for protons and neutrons moving inside the nucleus, leading to a shift in their energy levels in the nucleus shell model
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pedrone said:
and therefore the intrinsic spins of the quarks and the orbital angular momenta HAVE THE SAME MAGNITUDE for the production of the magnetic moment.

Is it correct ?
Click to expand...

Nope. If I were feeling generous, I could interpret the above as a sensible statement which is wrong only by a famous factor of 2. (well, a factor of almost-but-not precisely 2.) But I'm not feeling generous. Stop trolling and get to the point.
 
pedrone said:
The question here is: what is the magnitude of the spin-interaction???

Dont you understand it yet ?
:p:p:p
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The answer everywhere is: there is no such thing as the spin-interaction!!!

There is the spin-orbit interaction. It is idiotic to ask about the magnitude of this because it depends on the spin and the orbit.

Dont you understand it yet ?
:p:p:p
 
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pedrone said:
Zig,
Pauli Principle is OTHER consequence of the spin, which does not matter here.

Pauli Principle does not depend on the magnitude of the spin-interaction.
Click to expand...

Indeed. In many cases it determines the magnitude of the "spin interaction" (which is not the right term anyways). And it acts through any and all forces. So you can (and do) get a nuclear "spin interaction" because of Pauli exclusion.

In other words, you really don't know what you're talking about, and are repeatedly missing every opportunity to actually learn something because you're trying to prove a point about a subject you're completely ignorant of. Not exactly the smartest move there.
 
Reality Check said:
There is the nuclkear spin orbit interation.
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Mayer-Jensen awarded the Nobel Prize with a theory that explains the magic numbers, and they used the spin orbit interaction.

Such spin orbit interaction has the magnetude of the magnetism.
That's why I asked it to Ben M, but he refused to respond it.

The spin orbit interaction cannot have the magnitude of the strong force, because the strong force actuates in the range less than 2fm.
While the spin orbit interaction actuate in the range of 20fm, which is the diamenter of the nucleus
 
pedrone said:
Mayer-Jensen awarded the Nobel Prize with a theory that explains the magic numbers, and they used the spin orbit interaction.

Such spin orbit interaction has the magnetude of the magnetism.
Click to expand...
Citation?
The spin-orbit interaction. is usally expressed as the differenc in energy that it producses.
It does not have units of "the magnetism". It is not the magnitude of an unspecified "the magnetism (Earth? Sun? electron? proton?).

pedrone said:
The spin orbit interaction cannot have the magnitude of the strong force, because the strong force actuates in the range less than 2fm.
While the spin orbit interaction actuate in the range of 20fm, which is the diamenter of the nucleus
Click to expand...
Citation?
 
pedrone said:
Such spin orbit interaction has the magnetude of the magnetism.
Click to expand...

Wrong. It doesn't care about the magnetism, it cares about the spin.

That's why I asked it to Ben M, but he refused to respond it.
Click to expand...

I'll respond on my own schedule, thanks.

The spin orbit interaction cannot have the magnitude of the strong force, because the strong force actuates in the range less than 2fm.
Click to expand...

It doesn't have anything to do with either the strong force or the electromagnetic force. It's an exchange interaction.
 
ben m said:
Nope. If I were feeling generous, I could interpret the above as a sensible statement which is wrong only by a famous factor of 2. (well, a factor of almost-but-not precisely 2.) But I'm not feeling generous. Stop trolling and get to the point.
Click to expand...

Ben M,
a factor 2 cannot save you.

You need a factor 100, in order to explain why the spin-interaction can influence the strong-interaction.

So, the question is:
can the spin produce interactions with the magnitude of the strong force ?
 
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