Split Thread The validity of classical physics (split from: DWFTTW)

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I think humber's obsession with the power having to be behind the axle is due to his constant running out of gas (cars don't need gas if they can hover) as a result he is always getting out of his vehicle and pushing it from behind.

I imagine that if you did not have a treadmill with you so you could stand on it to get home, that when you ran out of gas, you would;
(a) Push the car from the front
(b) Take the wheels off the car, move them, then drag the car to them, and so forth.

I am quite sure that a car's engine pushes the wheels from behind the axle.
You are just guessing that is no so.
 
It sometimes gets to where everything humber says is wrong.

"A wheel with the contact point with the ground,directly below the axle, cannot travel. It will slide." says humber.

"When power is applied to the axle, stress develops between the contact point and the axle, causing the axle to move forward against a trailing contact patch." says humber.

As you can see, there is a problem, because that would require an increase in wheel diameter for that contact point to be sustained. It's "further away" from the axle, than a contact point directly below the axle. says humber.

"Of course, the wheel cannot stretch, but the wheel ( an or road) can compress to accommodate that." says humber

"This causes a difference in relative velocities of the wheel's material at the contact point and elsewhere. This is one view of 'slip'. For tyres, it is quite complex." says humber


That's everything so I couldn't have missed any.

Where "not missed" means posting everything, then when provoked, attempt to support it, but get rebuked and so stop.

ETA:
"... The engine torque is magnified by the gear ratio and the differential ratio and provides the drive torque on the rear wheels. The angular velocity of the wheel is high enough that it causes slip between the tyre surface and the road, which can be expressed as a positive slip ratio. This results in a reactive friction force, known as the traction force, which is what pushed the car forward. The traction force also results in a traction torque on the rear wheels which opposes the drive torque. In this case the net torque is still positive and will result in an acceleration of the rear wheel rotation rate. This will increase the rpm and increase the slip ratio."

"In a typical situation where the car is cruising at constant speed, the rear wheels will be rotating slighty faster than the front wheels .
(My edit: smaller effective diameter)
The front wheels are rolling and therefore have zero slip. You can calculate their angular velocity by just dividing the car speed by 2 pi times the wheel radius. The rear wheels however are rotating faster and that means the surface of the tyre is slipping with regard to the road surface. This slip causes a friction force in the direction opposing the slip. The friction force will therefore be pointing to the front of the car. In fact, this friction force, this reaction to the wheel slipping, is what pushes the car forwards. This friction force is known as traction or as the longtitudinal force. The traction depends on the amount of slip. The standardised way of expressing the amount of slip is as the so-called slip ratio:".......

A powered wheel will no move without slip. When it does, it slides.
 
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Okay, so that's how it works in the Humberverse. Fascinating delusion.

In our universe, when the cart is held on the belt, the friction (about the only thing that's somewhat similar to the Humberverse) from the belt spins the wheels. The wheels, through the axle, angle gear drive, and shaft (in Sporks cart; Goodman's just uses a belt with a 90 degree twist) , drives the propeller. The propeller, spinning in the air, generates thrust in the opposite direction of the treadmill belt.

Once the prop has been spun up, the cart can be released, as the propeller generates more that enough thrust to maintain the cart's position on the belt.
Wrong. The cart cannot produce more power than it gets from the belt.

Note: Only in the humberverse are rotating objects with axes at a 90 degree angle considered to be "counter-rotating". Also, in the real world, even if they were counter rotating, it would not reduce power consumption.

This means:
It's not true, but I will make an excuse any way, because it just works; so there.

Two shaft connected as in the cart, rotate in opposite directions. Their torques oppose. They counter-rotate.
 
I imagine that if you did not have a treadmill with you so you could stand on it to get home, that when you ran out of gas, you would;
(a) Push the car from the front
(b) Take the wheels off the car, move them, then drag the car to them, and so forth.

I am quite sure that a car's engine pushes the wheels from behind the axle.
You are just guessing that is no so.

The last time I ran out of gas, I hooked a tow rope to a another car and had it towed. From the front.
 
Wrong. The cart cannot produce more power than it gets from the belt.



This means:
It's not true, but I will make an excuse any way, because it just works; so there.

Two shaft connected as in the cart, rotate in opposite directions. Their torques oppose. They counter-rotate.

The axle shaft for the wheels is at a 90 degree angle to the propeller shaft. That is not counter-rotation anywhere but the Humberverse, where 2 + 2 = 22.
 
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The axle shaft for the wheels is at a 90 degree angle to the propeller shaft. That is not counter-rotation anywhere but the Humberverse, where 2 + 2 = 22.

There disposition does not matter. The shafts rotate in opposite directions.
They counter-rotate. That is a fact.
 
There disposition does not matter. The shafts rotate in opposite directions.
They counter-rotate. That is a fact.


Translation- I don't understand what "Counter-rotate" means, so I'll make an incorrect statement and put "That is a Fact" on the end.
 
Two shaft connected as in the cart, rotate in opposite directions. Their torques oppose. They counter-rotate.

One of your best McHumber. where do you draw the line here? If a shaft is connected by a universal joint and bent 45 degrees, is that still counter-rotating? How about 15 degrees, zero degrees? By your definition, a single shaft transmitting torque is counter-rotating since it is stressed by opposing torque. You are brilliant, you have offered a direct mechanical analogue for your own logic, a singular counter-rotating shaft!
Question Cucumber, is it still counter-rotating if it is not rotating?
 
A wheel with the contact point with the ground,directly below the axle, cannot travel. It will slide.

idiocy

This is one view of 'slip'. For tyres, it is quite complex.

I think we established that for you a bag of hammers is "quite complex".


Humber, if you had asserted that the sky is yellow with mauve polka dots, and somebody posted links to 5000 photographs with a blue sky, you would claim that the photographs support your claim that the sky is yellow with mauve polka dots.

That's how delusional thinking works.

You're only half right. The real truth is that humber will use your above logic to claim he's right. He's delusional-squared.

You are the smaller group. The treadmill has no standing in science, or academic support. It is ridiculous.

We must notify all publishers of physics texts that the Earth's surface is the "proper" reference frame. This business of inertial frames and velocity being relative is so two-hours-ago! (and non-humberian).

You misunderstand 'slip' because you see no other possible meaning than the one you already have. Look it up.

In order to "look it up" we'd need a dictionary from the humberverse. And I can only assume the text on the pages changes even as we read it. In our universe we establish and agree on consistent definitions - particularly in the field of science. We've done this even for "slip". You should learn a little about the "rolling constraint". You can "look it up" in one of our texts. You'll love them. The words just sit there on the page as you read. They don't even change from day to day!

The propeller is geared to the wheel and has no choice but to spin at a rate determined by the belt...

...and the speed of the cart.


The only possible option, is that the wheels may spin slower than the maximum implied by the belt, but for this to happen the wheels must break traction in the manner of a car on ice. That is the only way that can happen.

idiocy

The cart cannot climb the belt, by any means, but remains at the artificially induced state of windspeed by the mechanisms I have described.

idiocy and completely contrary to observed fact.

Again, all those ideas are actually beyond you.

idiocy mixed with arrogance.

If you are interested in negative drag, look it up.

delusional idiocy.

You must be a great instructor with that attitude.

ironic idiocy

Yes, I designed and developed it.

ludicrously optimistic delusional idiocy

They are a 3 axis device. They are specialised and expensive. However, the yield is low, and there are a lot of rejects that work but fail say the temprature test. These had a scrap value of 600 pounds(UK) four years ago. I can contact them if you like.

intricate and delusional idiocy

I withdraw that offer.

Very bold to withdraw an offer that was never made, and could only be based on your delusions if it were.

I am quite sure that a car's engine pushes the wheels from behind the axle.

And the entire scientific community (in our universe) is quite sure this is nonsense.

There disposition does not matter. The shafts rotate in opposite directions. They counter-rotate. That is a fact.

idiocy. Look up "fact".


So there we have it. Nearly 100 pages of humberian idiocy. What a ride!
 
There disposition does not matter. The shafts rotate in opposite directions.
They counter-rotate. That is a fact.
I see another interesting humberverse principle here. Depending on which side of the propshaft gear the axle gear is on, the propshaft could rotate either CW or CCW, given the same rotational direction of the axle. But either way would apparently be called "counter-rotating" in the humberverse.
 
This will be easy, it's from Simperton

I was right. No, it maintains a fixed position, as a result of that mass.

It stands to reason Distemper, that the losses will end up as heat.
That is all the work the treadmill motor does. No work is done on the cart, because it remains in place. It takes little work to stay in place, as I am sure you know.

No Humber, you were not right. You were wrong, and you fail to specify which mass you mean by "that mass" you also fail to recognize the actions, reactions and points of application of forces.
It can take any amount of work to stay in place, or none at all.
Did you eat your rabbit? She was your last hope.

Do not change a user's name so as to insult.
Replying to this modbox in thread will be off topic  Posted By: Gaspode
 
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Humber, are you now claiming that you are an accountant from the Netherlands?
 
At point of contact of wheel and belt, both the belt and wheel circumference are moving in the same direction. Therefore, the cart should go with the belt.
An external force will prevent this, allowing the wheel axle to remain stationary, and so inhibit the motion. This force is low, being total friction to the belt, so a light touch of the finger, or drag from a propeller, will easily hold it in place. The prop does not move the cart relative to the belt, but simply prevents is from moving back with the belt.
Completely backwards again. Ignoring for a moment the mass of the wheels, a cart, just on wheels without any extra gubbinses, would not "go with the belt", except for an external force to overcome inertia. It would stay still, as Newton's First Law dictates, allowing its wheels to rotate under it. THE FRICTIONAL FORCES are what would cause it to go with the belt, clearly demonstrated by making them infinite. The fact that in the real world a cart with just wheels does not have zero friction means that if it was left on a very long treadmill, it would be accelerated down-belt until it reached terminal velocity due to drag from the wind, probably just actual belt-speed depending on its aerodynamic features and amount of friction, rolling resistance, etc.. Once you get that bit right, you see that the mechanism of the cart with its prop has to not just go a little bit forward (even so, pretty darn miraculous), but has to overcome the constant forces pushing it backwards. In other words, it has to reach windspeed before it can just outpace it a bit. Ynot's videos are useful for two things in particular: you can start the cart from "standstill in still air" and increase the windspeed to where it is sufficient to make the cart outpace the wind; and you can see by how much it outpaces it, continually, steady state. This should dispel any remaining doubts about where the cart achieves its natural speed relative to the wind, for those who understand relative motion, frames of reference, etc.

The wheel and so the propellor can not move at any other velocity than directly determined by the belt, unless the wheels can rotate slower than the belt. Faster is not possible, as no matter what the grearing, the propellor cannot drive the wheel faster than the wheel that drives it.
Wrong. Not only demonstrated as wrong, but physically naive. If we replaced all elements in the system with toothed gears - belt-wheel-prop-air-belt - then you'd have a point, but the prop-air and the air-belt interfaces are flexible.

It is not possible for a cart to move at say 2m/s slower than a 4m/s belt, while 'traveling up the belt', because then the wheels must spin at half the velocity of the belt.
Well, a plane can taxi along an aircraft carrier in the direction of the stern making its velocity w.r.t. sea half that of the ship. What the cart demonstrates is that not only do you not need a separate engine to do that in air that is stationary w.r.t. the sea, but the cart will go directly down ship faster than the ship, reversing its direction w.r.t. the sea from that of the ship it is on. Somebody really ought to do that, film it, and post in on youtube, by the way. ETA: Unfortunately, ships of sufficient length to demonstrate DDWFTTW from a standing start might not be capable of sufficient speed, nor is it easy to demonstrate that the air movement is solely due to the passage of the ship (i.e. that it's a completely still day). Thank goodness for treadmills and equivalent frames!

The cart is brought to speed by operator influence, so that it may balance in place.
No, it is brought to speed by operator influence because the treadmill is only a few feet long.

The treadmill has nothing to do with a cart in wind.
You're like a creationist taken to see a cliff face full of fossils.

The belt and wheel do not go at different speeds. The only other option is for the wheel to completely slip on the belt, and so go slower then the belt, but that means motion down the belt.
You've changed the sense, now. Going slower than the belt was going up-belt a couple of paragraphs ago. Not only that, but "slipping" was what you suggested made the cart go up-belt in the videos.

You were saying?:...
You contradict yourself, and do not notice that in your case, both the axle and tyre move relative to the road.
I've never denied it. I've assumed it was fairly obvious. Parts of the tyre move at different velocities relative to the road.

There are other errors. The wheels on the front and rear of a car are often at different angular velocities.
Mostly untrue or negligible difference, but irrelevant anyway.

The average diameter of the driven wheel is actually smaller than an undriven wheel. That is how thrust develops. On a tire, this causes the tread to 'slip' to make up the difference.
NOMINATED (not that almost everything above also shouldn't be, but that really is the dog's nadgers).

ETA: That'll be why dragsters don't develop any thrust I suppose. They should have the small wheels at the back!...or are they front-wheel drive?

Actually, someone ought to take humber's version of how wheels work and email Dunlop or some vehicle dynamics labs. We could post the replies here. Perhaps have a conversation with NASA on gravity, freefall, etc. and do the same.:D
 
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One of your best McHumber. where do you draw the line here? If a shaft is connected by a universal joint and bent 45 degrees, is that still counter-rotating? How about 15 degrees, zero degrees? By your definition, a single shaft transmitting torque is counter-rotating since it is stressed by opposing torque. You are brilliant, you have offered a direct mechanical analogue for your own logic, a singular counter-rotating shaft!
Question Cucumber, is it still counter-rotating if it is not rotating?

At least as bizarre as the contention that shafts at an angle of 90 degrees to each other are "counter-rotating" is the notion that this somehow reduces the power consumption. Apparently in the humberverse, two wheels connected by gears, so they rotate in opposite directions, use less power than the same two wheels connected by a chain drive, so they rotate in the same direction.
 
Humber, are you now claiming that you are an accountant from the Netherlands?

If true, it's somewhat comforting, as his bizarre misunderstanding of physics won't really matter in his profession. If he were an engineer (or even an auto mechanic) it would be downright dangerous. I still wouldn't hire him to do my taxes
 
Tranlation:- You have totally destroyed my argument, so I'll mock you.

Well, if you thin towing is like pushing, that explains why pilot error is now responsible for the majority of crashes. It has fallen from 50%, but that is because of increased automation.



Translation- I don't understand what "Counter-rotate" means, so I'll make an incorrect statement and put "That is a Fact" on the end.

The two shafts cunterotate Captain. When one moves one way, the other moves in the opposite direction. That is quite comprehensible, as it always happens when two wheels are engaged, for example.
 
One of your best McHumber. where do you draw the line here? If a shaft is connected by a universal joint and bent 45 degrees, is that still counter-rotating? How about 15 degrees, zero degrees? By your definition, a single shaft transmitting torque is counter-rotating since it is stressed by opposing torque. You are brilliant, you have offered a direct mechanical analogue for your own logic, a singular counter-rotating shaft!
Question Cucumber, is it still counter-rotating if it is not rotating?

A universal joint, is not a gear set. Two engaged gears, counter-rotate.
That is a fact.
 
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