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Split Thread The validity of classical physics (split from: DWFTTW)

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Now that you have cleared that up with yourself, perhaps you would like to explain the significance of the equation you posted.

Perhaps you have noticed that the general use of vectors in this thread is the scalar "speed" with "to the left" added.
It makes no difference in principle if we look at one vector or a vector field. It's just more vectors to transform to another reference frame.

Why? Please see above.
Got it. I took a little more time to read this time. The thing is, it depends on how precise you need your model to be to calculate what you want to know. If I want to know the kinetic energy of a volume of gas I will need to know not only its mass and speed, but also how it is rotating and deforming. If I want to know what happens when I split a spinning mass, I can't use point mass models.
But the difference between treadmill and road with wind is not such a difference. For inviscid flow they are identical, and for a sufficiently large treadmill, they are indistinguishable.

One dimensional pedantry.
Okay, why don't you start talking sense then? In stead of stating vague criticisms of mathematical modelling, please suggest an alternative model. What is missing? Be precise; don't start about "the effect of something slower" or "taking an aerial view". I want vectors fields now, humber, the assumptions, the equations. You can keep it simple; limit it to the comparison of a treadmill in still air and a road in a steady wind. 2D will do.

Thanks.
 
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Fascinating. So, how do airplanes work? How does their energy return to ground, since they aren't touching it? And what about airplanes that are taxiing, touching the ground, but still moved by their propellers?

By transferring energy, by transferring momentum to the wind. That wind finds it merry way to ground some time. The supplied energy is stored in the mass of the air and the plane itself, with the remainder going as heat through drag and engine losses, and sundry items such as sound.

In the last case, the engine develops a certain amount of thrust. That energy returns to the air (stored in its mass as KE) and some directly via the wheels.
Rather like a certain wind cart, but the energy comes from the wind to directly drive the cart, or via the wheels to the ground. ( certain liberties taken for brevity, jjcote.)
 
No, the notion of "two passing cars" having zero KE was your idea:



Tunny

I don't see your point, Tunny. If they pass when what the law regards as "in the same direction" there must be an instant when their relative velocities are zero. They need not be passing closey at that point, they could be quite far apart. Or just like many other vehicles on parallel roads, all linked by the invisible bond of zero KE?
Yes, just like each and every parked car, is related to another parked car.
 
This is the case with the car. The maximum speed is determined by the engine's power; it's capacity to do work against a load. Lower gears may give better acceleration at lower speeds, but that does not change that final result.
Actually, it does. The maximum speed of my car may be limited by the engine power in top gear, but certainly not in first gear.
 
I don't see your point, Tunny. If they pass when what the law regards as "in the same direction" there must be an instant when their relative velocities are zero. They need not be passing closey at that point, they could be quite far apart. Or just like many other vehicles on parallel roads, all linked by the invisible bond of zero KE?
Yes, just like each and every parked car, is related to another parked car.

Total nonsense. You're deeply confused about the meaning of the term "velocity", and at the moment you seem to be confusing it with "displacement". Don't worry - plenty of 5-year-olds are confused by that too.

Take two cars with constant velocity on parallel roads. If their velocities are different one will pass (or has passed) the other. Since the velocities are constant, so is the relative velocity. There is no instant when the relative velocity is zero.
 
So, geared carts or yo-yo's may gain in that respect, because they can exploitany power that is available and so accelerate faster, but the terminal speed is fixed by the same means as any other chute driven vehicle; by the available power.

I can sit on a bicycle and pedal it so that my feet are moving around 6 mph. And I can set the gears on my bike so I'm moving at 15 mph.

That's all the yoyo-parachute does. A 10 mph wind causes the chute to move at 6 mph. Because of the "gear ratio" or the block and tackle ratio, the yoyo moves at 15 mph.

the chute's force is linearly related to its velocity w.r.t. wind, and that falls as its gains velocity

Except that with the yoyo-chute design, at the point where the cart is moving at the speed of the wind (10 mph) the chute is still getting reeled in by the axle of the yoyo, pulling it backward (at whatever speed you want depending on the diameter of the axle). So, even though the yoyo is moving as fast as the wind, and even though the yoyo doesn't feel any wind, the yoyo is still turning, reeling in the chute, meaning the chute feels wind, which pushes the chute, which accelerates the yoyo faster than teh wind.

If teh chute were simple a tether on the yoyo, hanging on the end of a rope with the other end connected to a flagpole or something stationary to the frame of the cart/yoyo, then yeah, as the cart sped up, teh wind on the chute would decrease until it was going the speed of the wind, and the chute would stop feeling any force from the wind.

But the chute isn't tethered. It's being reeled in by the string wrapped aroudn the axle. As teh axle turns, it reels in the chute. The faster the axle turns, the faster it reels in the chute. When the yoyo is moving at the speed of teh wind, a tether would hang limp, but the axle is still turning, reeling in the chute, and so teh chute pulls the yoyo forward.
 
Actually, it does. The maximum speed of my car may be limited by the engine power in top gear, but certainly not in first gear.

That is the point jjcote. In first gear you can accelerate, but not get to top speed. The gearbox matches the engine's power to the load. Acceleration is additional to the demands of drag.
For the n'th time see MAXIMUM POWER THEOREM
 
Total nonsense. You're deeply confused about the meaning of the term "velocity", and at the moment you seem to be confusing it with "displacement". Don't worry - plenty of 5-year-olds are confused by that too.
Drivel. Please do tell how linear acceleration, (as applied to motion!) occurs without displacement.

Take two cars with constant velocity on parallel roads.
Constant, meaning dv/dt = 0.

If their velocities are different
Meaning constant but not equal. V1 - V2 = k

one will pass (or has passed) the other.
How?

Since the velocities are constant, so is the relative velocity. There is no instant when the relative velocity is zero.
V1 = V2 + K
Applies to zero too.
So you agree, two vehicles traveling at same speed, have zero relative KE, just like two stationary vehicles.
 
Drivel. Please do tell how linear acceleration, (as applied to motion!) occurs without displacement.

So in humberland if one thing requires another, the two are identical?

Constant, meaning dv/dt = 0.

Right.

Meaning constant but not equal. V1 - V2 = k

Right....


What do you mean, how? They're moving at different velocities, let's say in the same direction. If the faster one is a distance d behind the slower one, it will overtake and pass it in a time d/k. If it's in front, it passed the slower one d/k time earlier.

So you agree, two vehicles traveling at same speed, have zero relative KE, just like two stationary vehicles.

Yes of course - and in that case one doesn't pass the other.

I retract my comment about 5 year olds. This level is obvious to 2 year olds and chimpanzees.
 
It makes no difference in principle if we look at one vector or a vector field. It's just more vectors to transform to another reference frame.
In practice, things are not lined up in a row. I doubt that you can make all vectors zero, H'ethetheth.

Got it. I took a little more time to read this time. The thing is, it depends on how precise you need your model to be to calculate what you want to know. If I want to know the kinetic energy of a volume of gas I will need to know not only its mass and speed, but also how it is rotating and deforming. If I want to know what happens when I split a spinning mass, I can't use point mass models.
But the difference between treadmill and road with wind is not such a difference. For inviscid flow they are identical, and for a sufficiently large treadmill, they are indistinguishable.
None of that does anything to support zero KE as the basis of a model H'ethetheth, but to suggest that is impossible, and produces an inert result.

Okay, why don't you start talking sense then? In stead of stating vague criticisms of mathematical modelling, please suggest an alternative model. What is missing? Be precise; don't start about "the effect of something slower" or "taking an aerial view". I want vectors fields now, humber, the assumptions, the equations. You can keep it simple; limit it to the comparison of a treadmill in still air and a road in a steady wind. 2D will do.
It is quite straight forward, and you are changing the playing field. None of these matters have been addressed, and whatever the outcome or interpretation, I have not seen anything other than the over-simplification represented by the equations you posted to me a few posts ago.
I am quite sure an ad-hoc structure can be built, why not, just add more transformations, but that will say nothing about the validity of the model. Mathematics will simply be an obfuscation.

To answer the modeling question, I may as well reply to your earlier post, H'ethetheth.

it implies motion of the car yes if we look at it from the belt. Just like from every other reference frame that is not stationary with respect to the car.
And if there is no belt? That idea seems magical to me. As yet, nobody has managed to explain how the car can be said to be in motion, or how the KE necessary to meet even the minimum requirements of dynamic modeling is acquired or stored, or how that may be assigned to the belt or anywhere else. (Measurement seems to be impossible without actually supplying it it from test device itself)
The car and belt (or the observer) are not isolated from ground, but share it in common, and are within a common gravitational field. That is for certain, or there would be no power for the motor, to name but one reason. ( Power stations eventually return all current to the ground). It becomes difficult to believe that any KE produced from that source is not relative to ground.

Yes. In the same way the the fish in the fish wheel can be said to be travelling, and in the same way that you can be said to be travelling at any given time.
I presume you mean motion other than relative to the ground? That motion at any given time is in the 'background', a common-mode effect. Your fish tank model, and all of our scientific tools are selective, and serve to isolate the desired outcome from that background, or as in your specific case, from water currents too.
I am not traveling in any real sense when not in motion w.r.t the ground, or it could be said that our cemeteries are full of travelers.
The fish may do work against a flow, and yet not move relative to the ground, and so gain no KE w.r.t the ground. This is nor true of the treadmill, as generally, little work is required to stay in one spot, when there is no load.

But if it's a horizontal array it does necessaily imply vertical jets.
I admit that this is theoretically possible, however, it is practically orders of magnitude more complicated than current computers can handle, due to the nature of turbulence. It is practically the only way, and there will never probably never be a necessity to solve this differently. By the time people can generate arbitrary turbulent velocity fields at will, the can use that same computing power to just solve their problem by CFD.
I did not elaborate on the jets, though I did not have simple vertical jets in mind. Yes, I know it is possible and I could use it, or perhaps something else, may be high-power ultrasonics. Orders of magnitude? I doubt that, and I can still call upon natural phenomenon to do some of the 'calculation', as indeed BMW seem to be doing. I expect that the CFD programme is 'seeded' with real data.
My point H'ethetheth, is that I do not need a belt. Therefore, I can see no reason why the belt could be said to imply motion of any sort.

No, considering only the treadmill for a moment. on the DDWFTTW cart all components are active, and interact in the same ways as on the road. The air moves across the propeller blades the same way, the wheels move the same way relative to the surface, the air moves the same way relative to the surface.
But the treadmill does not remove the wind! It preserves the interaction of air and surface, and the interaction of the air and the cart!
The belt drags the cart backwards through the wind to be self-limiting, and so stay on the spot. That is not equivalent.
Some emulation of the road/wheel interface and propeller, yes. That is where the similarity ends.

(1)The real wind's power is independent. Whereas on the treadmill, the power available to the cart is limited by the friction to the belt and the reaction of the cart to that. Moreover, the force to the belt is of course, dependent upon gravity. That is not equivalent.

(2) The belt may be capable of providing the necessary power, but as stated, that is limited by the force to the belt. When that limit is reached, the cart's wheels may turn, but it will stay motionless w.r.t the ground ( because of the relative motion of wheel and belt) while the force will be more or less constant from the point. This casts doubt on the claim that the cart is capable of climbing the belt to windspeed.

(3) The treadmill can be modeled by fixing a strip of belt to the top of a long flatbed trolley. The wind-cart is placed on the belt as normal, and the trolley pulled through still air, so as to drag the cart backwards (air against the rear of the propeller). That is the same as the cart moving back with the belt. If the model is at all valid, the cart should make progress along the belt. That would not happen for many reasons;
(3a) The rear of the cart's prop will be met by the air mass, and simply roll on the spot with no motion w.r.t ground, hence no KE.
(3b) Should the propellor turn in that condition, that will serve to drive the cart forward. However, this will self-regulate because the cart is now moving in the forward direction, and so away from the driving force, with the added vexation that the belt and wheels are still in opposite motion. This means that the force is essentially constant, and at a minimum, with little or no motion w.r.t ground. That is the general operation of the treadmill, and the windspeed state.

The cart can never be in motion w.r.t the belt. For the cart to do that, the wheel's axle must move w.r.t the belt, but the opposite motions of belt and wheel prevent that. If force were to be available from the prop, then that would drive the axle forward, away from the driving force. The fact that is does not, shows that there is no net thrust from the propeller.

In fact, the above is a particular example of the general case; a simple wheeled vehicle powered only by the belt, cannot make progress w.r.t that belt.

(3c) That raises questions about distance on the belt. If the perceived travel is said to be velocity above windspeed, that would seem to be valid. The belt represents a velocity plane ( the speed of the belt sets the windspeed) but the distance along the belt itself, as a real belt, has a real dimension, so what does that represent to the treadmill side observer?
The models is strained, but it would appear to be simple displacement w.r.t the ground, for both the real and modeled cases. This also suggests that the cart is not in motion, save for that small displacement.

The fish tank is different, very true, but like the treadmill, it keeps the object of study in one place, while keeping all interactions with the environment as close to identical as possible.
It is also true that it is not at all comparable. Yes, the fish does stay in one place, that is my point. The fish can gain no KE unless it swims at a velocity w.r.t the ground. The cart does not move relative to the ground at any appreciable velocity, and so can have no KE. In this way, they are similar.

The fish swims in still water with respect to itself? That's not swimming.
Badly expressed, perhaps. The fish and water could both be at the same velocity w.r.t. the ground, but zero w.r.t reach other. There is no motion relative to the water when not swimming, is what I mean to say.

It could be that you actually intended to say the right thing though, so I'll give you the answer.
The fish wheel is intended to model still water. It does this by creating a uniform flow field as well as it can. My version is intended to enable measurement of the vortices in the wake of small fish, so any vortices typical of flowing water would severely influence the measurement. These vorrtices are absent in still water, but following a fish through a tank with a camera is not easy, so you want to create moving still water for the fish to swim through while stationary remaining with respect to the camera.
Yes, that is option(3)of the my earlier post. The others I thought may be closer to the treadmill, which is why I said that (1) was most likely to be comparable.
Yes, the fish is motionless w.r.t the camera, and flowing water would cloud your data, but the fish does swim. The tank rotates to keep the swimming fish fixed relative to the camera. As the tank rotates, there must be some viscous coupling to the water, so a small flow will be generated. I imagine this to be necessary to the experiment, because it stimulates the fish to swim against it. This is nothing like the treadmill.

True, but not important if the interactions of all parts reamin the same.
The fish is self-powered and not from the flow of the water. That is very different from a wind cart. Few would doubt that a battery R/C car would not climb the belt.

It does not imply motion. It moves.
That also sounds like magic. Like the fish, the cart it has no KE because it is not in motion w.r.t the ground. The KE is said to exist "relative to the belt" but it seems that a belt is not necessary to the model, so what then? The belt simulates the effect upon the boundary layer of the cart/car passing over the road, but not the motion itself.

Let's forget about that, shall we. It confuses matters, and it won't be feasible until holodeck technology is hum-drum.
In detail, yes. It is hypothetical, but means that it is feasible, and I could eliminate the belt. In any event, I need not model the boundary layer to test other aspects, so how can it be said that the car is in motion if there is no motion at all?

For a large enough treadmill, the interactions between wheels, air, chassis, and surface will become indistinguishable from a car on a road.
An error margin can be set accordingly. The reproduced boundary layer may perhaps be indistinguishable from the real thing, but definitely not the car's behaviour. The dynamics of motion at speed are no reproduced at all. It is not possible to do this to any significant degree, as the BMW/F1 car is mechanically restrained by attachment to the ceiling. The cart is similarity stabilized, by the method I described and some details specific to the cart's mechanism, but it is quite clearly only just stable. Not the dynamics of a vehicle driven to wind at such speeds,

On the road, there is no wind coming from under the car. The only thing that can happen is that the wheels and airfoils create vertical velocities, but they will never induce vertical velocities at the surface.
There is certainly wind passing under the real car. The real wind blows over the road creating a boundary layer, independently of the car. That passes under the car, to be modified by the motion of the car as it travels over the road. There are two components to the boundary at a given velocity; the wind under the car, and the motion of the car over the road. The belt largely provides the pattern of that interaction, but the wind that passes under the car is needed for accurate reproduction. The error in the treadmill belt flow, is a demonstration ( in part) that wind is necessary to that model.






.
 
So in humberland if one thing requires another, the two are identical?

What do you mean, how? They're moving at different velocities, let's say in the same direction. If the faster one is a distance d behind the slower one, it will overtake and pass it in a time d/k. If it's in front, it passed the slower one d/k time earlier.

So there is a diminishing closing gap? That is ds/dt? Going through zero as it "passes" the car? So zero KE?

Yes of course - and in that case one doesn't pass the other.
Depends how you define the start of the process, perhaps?

I retract my comment about 5 year olds. This level is obvious to 2 year olds and chimpanzees.

That's wise, but now the chimps are livid over the comparison.
 
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For those wanting to try something at home, buy a small toy car from a toy shop (make sure it has free wheels that do not stick). Place it on sheet of paper, and pull the paper. See what you have to do to keep it in place w.r.t the ground. Figuratively, the prop stabilizes the cart in that position, by "hooking" to the air.

ETA: Just thought of something. I expect a sail on the car would do much the same as the prop.
If an elastic band were to be fitted between sail and mast, and if the friction to the paper were adequate, might not the elastic be stretched and relaxed, so driving the car forward?
 
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So there is a diminishing closing gap? That is ds/dt? Going through zero as it "passes" the car? So zero KE?

So all this time I've been avoiding other cars when I passed them on the road when I didn't have to! Zero KE as I pass - so a collision wouldn't transfer any KE between the vehicles and thus no damage! Wow!

ETA: nuts, almost forgot, I don't drive a humber.
 
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For those wanting to try something at home, buy a small toy car from a toy shop (make sure it has free wheels that do not stick). Place it on sheet of paper, and pull the paper. See what you have to do to keep it in place w.r.t the ground. Figuratively, the prop stabilizes the cart in that position, by "hooking" to the air.

But make sure it is a really long piece of paper and have someone pull it at a steady speed. Hold the car over the paper so the wheels just touch, let the wheels get up to speed, then set the car on the paper. See how long the car "balances" for.

In real life, the propeller cart not only would stay in place when the paper is pulled at a high enough speed, it would start moving the other way. The propeller not only "hooks" into the air, its wheels "hook" to the ground and the gearing system allows the cart to move forward between those two "hooked" substances.
 
To a first approximation, the chute's force is linearly related to its velocity w.r.t. wind, and that falls as its gains velocity, (so reducing its velocity w.r.t the wind) whereas the drag, the demandedforce, is the square of that velocity and so increases as you gain velocity, but at a faster rate. You will lose the battle well before windspeed.

Another humber gem: the drag of the chute against the air only increases at the same rate as the difference in the speed between the air and the chute, but the drag of the cart is the square of the difference in speed.

Does anyone see something wrong with this? Or are we all supposed to consider this inverted view to be another normal occurance in the humberverse?
 
Just wondering Humber, are you going to respond to John Freestone's post or have you finally run out of wriggle room?
After reading the recent transaction with sol, it hardly seems fair to set such complex and difficult puzzles as that. I've removed the frames of reference, number calculation, measurements, etc., and just left the observation of bits of tissue paper wafted through the air attached to a surface. Too much, apparently.

Maybe I should simplify again. The thing is I really just want to know what he thinks, clearly and simply. I'd leave it then. I don't care if it agrees with my version of events that much. I just can't make out from his answers so far what he means about the boundary layer going the wrong way.

It makes sense to me that if I hammer a nail in a wide plank and wave it through the air, the surface of the plank drags the air a bit, so while the end of the nail gets the full speed "waving-generated" wind on its leading side, the bottom gets something less than full speed "waving-generated" wind on its leading side. No part of it gets wind on the trailing side, except perhaps due to eddies. Eddies have not been mentioned, only that the 'flow' (boundary layer) - the whole of it, not eddies - goes the opposite way to when the plank is left out on a windy day. His maths is supposed to support that. You know it's wrong. I know it's wrong (even though I can't make head or tail of it most of the time anyway).

Yet there is this disturbing condition he seems to think arises, where the main body of air impinges on the leading side of the object (whatever it is) at some remove from the moving surface, but the reversed boundary layer lower down - he even said occasionally something about winds going in two directions. Hence the first diagram with the question marks. Where does the wind flip from left to right? Who knows, he didn't answer.

I just asked him to say what all the relevant speeds were compared to the 'real wind' situation; still no answer. Finally I am getting to the point of just asking "Humber, if you wave a stick with bits of string attached at 1 inch intervals, do they all stream backwards or forwards with respect to one of your fingers?", but maybe that's too difficult. Or maybe I've offended him too much with my sarcasm, although he welcomed it.

See, if I could find that out, I could then ask why it's different for that stick with bits of string if instead of just his hand, it's sticking out of a large board. Does a boundary layer arise then? Do some of the bits of string start streaming forward near the board?

Or I could repeat the other question: does the air move forwards over an aeroplane's wing (and fuselage, or anything moving through the air) when it's flying, but backwards over it when it's in a windtunnel?

I may never find the answers to any of these things. He is obviously deep in contemplation of more serious physics:-

Drivel. Please do tell how linear acceleration, (as applied to motion!) occurs without displacement.
It doesn't. As sol said, that doesn't mean they're the same thing. Velocity is rate of change of displacement, distance over time. Acceleration is rate of change of velocity, distance over time squared. And then there's the sloppy maths:
Constant, meaning dv/dt = 0.


Meaning constant but not equal. V1 - V2 = k
That's a poor way to express two things not being equal. You have not stated the most important idea, that k does not equal zero. You could have written V1 <> V2, or just stated that k does not equal zero as a note.....am I just being pedantic?......

How?


V1 = V2 + K
Applies to zero too.
No. Now you take the one value that k cannot be for two velocities to be different, and, because you've translated sol's English into humbermath, you can now state a falsehood and continue...
So you agree, two vehicles traveling at same speed, have zero relative KE, just like two stationary vehicles.
I don't know the latin phrase for "which was not to be demonstrated". [ETA: Your favourite response is fitting here: true but trivial. That was not the point at all. Besides, NOW you're introducing something called "relative KE". I thought things just had KE, belonging to them, which they picked up from Earth's gravity or somewhere throughout their history. Or is that another of those invisible 180s you've managed to pull off? - well, more like 95s]

It's just a completely different universe, isn't it? There really isn't much in the way of logical structure to get a grip of. He puts statements together, sometimes correct ones, sometimes wrong, mostly meaningless, but they hardly bear any relation to each other. Science might as well be punk rock lyrics. If the line doesn't scan, just gob a bit and say the opposite.
 
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So there is a diminishing closing gap? That is ds/dt? Going through zero as it "passes" the car? So zero KE?
What's "s"? Two cars are going at constant velocities........... ...... ...... ..... .... ......... .. . . . . . .etc.

They pass, at constant velocities. The closing gap (a displacement!) narrows to zero then expands again (negatively if we feel inclined to notate it as such). Who cares? They don't change their velocities.

They are different velocities. Constant, each one, but different from each other. Hence the gap closing. Hence there is a non-zero relative velocity V1-V2, which remains constant also. Still with us?

Since KE = mv2/2, and the masses are constant and non-zero, and the relative velocity is constant and non-zero, Na-ah! Not zero KE. Not at any time, zero KE. Do you see? [ETA: To be fair, it's easy to forget the obvious. I've just added "and non-zero" in bold italic there! But do you even understand the fundamental concepts of mechanics, or of mathematics?]

That's wise, but now the chimps are livid over the comparison.
They know to duck when the gap closes, when something heavy is coming towards them. I suppose that's due to their instinctive knowledge or experience concerning the non-zero KE. You've "worked out" that it gets to zero as it approaches. QED.
 
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