tusenfem
Illuminator
- Joined
- May 27, 2008
- Messages
- 3,306
tusenfem;
You did a calculation before about the rate of water production based on solar wind particle density. Which, if I recall correctly was 6 orders of magnitude lower than detected values (for the comet parameters you used). The response was that your interaction region considered was just too small. Sorry but not wanting to go back and look for it myself and figuring you would still have the numbers handy. What does that work out to for the required size of an interaction region (basically just six orders of magnitude greater than the region you used)?
Hey, just because the electrical comet proponents don't want to quantify things doesn't mean that we can't.
Hi the Man
Yes, I did that calculation in post 2250.
A few of the complaints are:
- The electrochemical process also takes place in the coma, which is much larger than the nucleus
- There is a "storage" of protons around the comet, which can be accelerated by the cometary electric field (double layer)
During the passage of 1996 the coma was at it largest 2 arcminutes in diameter at a distance of about 1 AU, which trigonometry would tell us gives an approximate size of D = r sinθ ≈ r θ ≈ 1 AU * 6 10-4 = 90000 km, which seems okay from a gut feeling.
Naturally, the coma is not homogeneous, but is known to be basically exponentially dropping in density away from the nucleus with exponent {-ν r/ ve} where ν is the ionization rate (10-6) of the gas coming from the comet and ve is the escape velocity (~1 km/s) and r is the distance. So one e-folding length would be on the order of the size actually. So you have density N at the comet and density N/e at the edge of the coma.
So 4 or 90000 km diameter makes a huge difference and in principle you would get your 106 factor, BUT, we cannot use the mainstream outgassing, because mainstream thinks there is ice below the surface which sublimates, whereas EC says there is electric discharge machining of the surface, or there is proton electrochemical production of negative oxygen. No matter what, the surface of the comet must deliver the oxygen either in negative ion or in hydroxyl state. We do not know the rate for the EDM production, but the proton influx onto the comet still holds as in my calculation, as far as I can see.
Then again, we know that around the comet, in the draped magnetic field, the velocity of the shocked solar wind plasma is still rather high and down the tail. So there is no way of having a "reservoir" of protons hanging around.
Naturally, then they will invoke the "neutral hydrogen cloud" around the comet, of which through ionization protons can be formed. They would have to be accelerated towards the nucleus of the comet by the supposed cometary electric field (double layer?), with up until now has not been measured.
That is the answer I can give you at the moment. More details could be taken into account, but it is a rather pointless excersize, unless haig or David Talbott or Sol88 would like to take the challenge of improving/correcting on the quick analysis above and show us how it is done.

