Sorry chief, but you sound confused.
The static load is being decelerated at 1g while it is being supported. Gravity is at work there trying to accelerate it and the structure below is decelerating it.
To actually break the structure below with the static load mass it which was designed to handle several times over, there needs to be a deceleration of that mass sufficiently greater than 1g to generate the force amplification necessary.
I don't know what planet you are on but that is how it works here.
And this is where your mistaken 1g "static acceleration" gives you a squirrelly answer.
Once the collapse begins, then an unsupported upper floors will begin to fall at 1g.
Any force applied to the upper block by the lower supporting structure will reduce the resulting acceleration to a number that is less than 1g. The measured acceleration (a) form a resisting force (Fr), that is
constantly applied from the instant that collapse begins, will be given by:
a = (mg - Fr)/m = g - (Fr/m)
(where a positive "a" indicates increasing downward velocity)
The resisting force (Fr) doed NOT have to be greater than mg. And the resultant acceleration does not have to be greater than 1g.
A couple of things to note:
1. If Fr/m < g, then the upper block will be accelerating (its downward velocity will be increasing)
2. If Fr/m = g, then the upper blocks downward velocity will be CONSTANT. Not zero. That means that, if the upper block had fallen for 1 second, gaining a downward velocity of 32 ft/sec, and THEN the lower structure applied a resisting force equal to the static load (Fr = mg), then the building would STILL collapse to the street, with the downward acceleration = 0, and the downward velocity equal to 32 ft/sec.
3. The reality seems to have been that the average downward acceleration was approximately 0.6g - 0.7g. Which means that, during the collapse, the massively damaged building was able to still generate a resisting force of about 0.4mg - 0.3mg.
This resisting force is made up of many components, each acting over various time intervals: the force it takes to destroy connections, the force it takes to fling parts around, the force it takes to accelerate previously stationary (or slowly falling) mass, the force it takes to crush things, etc. The only thing that you can say is that the sum of all these forces averaged out over time to be equal to approximately 0.3mg - 0.4mg.
The fact that you don't know the time sequence, time profile or direction of all these forces is why it is easier to use scalar energy calculations rather than force calculations.
NOTE WELL, Tony, that this total resisting force is, contrary to your assertion, less than mg. And the DECREASE IN ACCELERATION that results from these forces, is approximately 0.3g to 0.4g. Which is significantly less than your claimed minimum of 1g.
The force amplification is, to a large degree, a figment of your erroneous "1g static acceleration". Plus your conflating force with acceleration, and your failure to construct correct force diagrams.
There was no need for the resisting force to be greater than mg. Nor any need for the decrease in downward acceleration to be greater than 1g.
Tom