An intresting question. When there is no current flowing through trhe superconductor, there will be no image charge since the superconductor will react to the external charge like a dielectric
First: you must realize that dielectrics can have (bound) unbalanced charge density. In a dielectric with non-constant polarization density P, there is an effective
charge density rho = divergence(P), sometimes called bound charge. If you treat my "plate" as a dielectric, the polarization indeed has a divergence (at the top and bottom surfaces) which indeed gives you nonuniform charge density. The formation of that charge density has exactly all of the properties of---guess what?---an electric current. (d/dt rho = div J is exactly as true for bound charge as it is for free charge.)
Second: no, it does *not* behave like a dielectric. You can see this very clearly if (as I suggested) the plate is plugged into a ground connection. Start with a grounded plate, and no external charge. Now bring the external charge in from far away. In order to remain at ground potential, the plate needs to pull in an
image charge; it does this by drawing ordinary, free current through its grounding cable. The resulting charge arranges itself on the plate top surface in a nonuniform way.
This is basic, basic E&M, Johan. This problem (induced charge on a plate with a point charge above it) is section 3.2.2 in Griffiths "Introduction to Electrodynamics"; a complete derivation of the induced charge density as a function of position, uses Coulomb's Law plus literally four lines of algebra.
There is nowhere in the problem where you care about presence of a DC current, nor about the nature of the conductor (metal, semimetal, plasma, superconductor, salt water, etc.), nor any of the other details you toss in as "objections" without actually thinking about.
If you disagree, this is the world's easiest test of your theory. Take a superconducting plate (you can but a cheap YCBO pucks from Edmund Scientific for about $30) Plug it into ground via a nanoammeter (old Keithleys are $100 on EBay) Wave a static-charged rod (glass rubbed with silk) up and down above it. Does the ammeter show the plate drawing current? If so, it's getting a nonuniform image charge as normal physics says. If not, the plate is behaving like a dielectric, any moving charge is of the bound/polarization variety, and you win the Nobel.