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Superconductivity at room temperature??

Comments on post #959 by Ziggurat

Because there is no field anymore. Obviously.
Please look at posts # 962 and 987; and put on your thinking cap. All the arguments you have raised on this post #959 have already been answered on this thread.
 
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I agree with Zig here, Johan. This is complete nonsense. You did not (not correctly, anyway) derive this from your microphysics.
I did, since my whole model is based on the fact that the applied electric field is cancelled at the position of each and every superconducting charge-carrier by polarization of the charge carriers. If this is not the case the charge-carriers will be accelerated like normal charge-carriers and superconduction will not be possible.
You did not derive it from any experiment, or even thought-experiment, with superconducting capacitors.
Have you read my book? How can you make such a statement without first checking your facts?
You appear to have done no math whatsoever to help you understand it.
So you judge on appearances; not on facts! And you call yourself a scientist?
You need this effect to avoid an energy-conservation catastrophe; that appears to be the beginning and the end of your critical thinking about it. Sorry, Johan, even if this effect were as you say it does not solve your energy conservation problem.
Read my posts above: There is no energy-conservation problem.
And the effect isn't what you say; your vague nonmathematical reasoning has gotten the energy budgets wrong.
Again it "appears" to you that this is the case without checking the actual facts:; Please read posts #964, 987 and 999 above: Put on your thinking cap if you have one.
 
Comments on post #962 by Ziggurat

Again I urge you to put on your thinking cap rather than to expect that I must write a long response on your arguments which are not applicable to the situation at all: For example:
Yes. And in the process, you will lower the electric field energy. The equilibrium condition can be determined by minimizing the combination of electric field energy and polarization energy.
Yes electric-field energy is transmuted into polarization energy. If you want to claim that the transmuted energy must be subtracted from the original amount of electric field-energy; then I agree. If you want to argue that the total energy (electric-field and polarization) must decrease, you are wrong. All the dipoles are surrounded by "free" charges that can conduct and thus re-arrange in an electric field. Crunch the numbers.

etc. etc. etc.
 
Yes electric-field energy is transmuted into polarization energy. If you want to claim that the transmuted energy must be subtracted from the original amount of electric field-energy; then I agree. If you want to argue that the total energy (electric-field and polarization) must decrease, you are wrong. All the dipoles are surrounded by "free" charges that can conduct and thus re-arrange in an electric field. Crunch the numbers.

Johan, you've agreed that if you take a charged capacitor and insert an ordinary dielectric between its plates, there's a force pulling the dielectric in. That's because the presence of a dielectric lowers the energy.

Very simple question: is there a force on a slab of superconductor as it is inserted between two plates of a charged capacitor?
 
Now you switch on a voltage using the separate source connected over the capacitor plates. Only now does a voltage VJ appear over the Josephson junction: This voltage is clearly caused by the second power supply: Not the power supply that is injecting charge-carriers into the SIS.

That's a very clear description of two batteries, both with the same voltage VJ, connected in parallel. (If they were not the same voltage, there would be a voltage drop across one or both of the superconducting leads.) The current through the junction is the sum of the currents out of the two batteries---this is Kirchoff's Law or charge conservation.

If "original" battery supplies some small charge Q1, and the "Prins" battery supplies some charge Q2, then the net work done by both is VJQ1 + VJQ2. The total charge through the junction is Q = Q1 + Q2, so as usual the net work is Q V.

Not 2QV. We've been through this before.
 
Comments on post #963 by Ben m

Again the same problem as with Ziggurat: Please do the experiments described in posts #964, 987 and 999, etc.; and only then post your irrelevant arguments if you still believe in them; like
And you're missing the important numbers as usual. Go ahead and build your "dielectric" out of springs---lots of them. One end is fastened down, the other end carries a charge. The spring length is L and the constant is K.
This is obviously an irrelevant and infantile argument and just wasting everybody's time on this thread. Why do you not put a Josephson SIS between two capacitor plates with a separate battery and measure what you get before believing that you can model what happens without doing the experiment? Sheesz! Even better, get a high school pupil to do this experiment for you and report the results objectively before you influence him/her to get what you want to get.
 
Comments on post 971 by Sati1984

What are they scared of exactly?
What do you think the "old" "experts" on superconduction will do if they are confronted by the possibility that they will have to announce that their models and publications based on these models have been incorrect for over 50 years?
I've seen that mentality before, no need to elaborate on that. Just look at the story of the phonograph and Edison's demonstration in Paris...
Yes it has always been there from the time of Galileo: It has now reached a worse scenario since after the second world war physicists increased and number and are vying for funds. It is bad for your future to acknowledge that you have made a mistake; and even worse when the majority in the field has to do so. How the public will laugh when the physicists acknowledge that they are not the "clever gods" portrayed by the BBC on their Horizon programs. At least Stephen Hawking was prepared to state after 30 years that he was wrong: This in my my mind makes him the most important physicist alive today!
Don't these companies have R&D departments? I suggest trying to setup an experiment and show it to them. You could try IBM too for example. If they (any of these companies) are willing to see it, and verify it, maybe you could do a demonstration...
I have offered this countless time, but never received an answer from anybody.
 
For example: Yes electric-field energy is transmuted into polarization energy.

Only in the case of a non-zero spring constant. But a nonzero spring constant cannot cancel the electric field.

If you want to claim that the transmuted energy must be subtracted from the original amount of electric field-energy; then I agree. If you want to argue that the total energy (electric-field and polarization) must decrease, you are wrong.

No, johan. If there is no change in total energy, then there's no reason for the system to polarize at all. The system is driven to polarize precisely because it lowers the total energy.

All the dipoles are surrounded by "free" charges that can conduct and thus re-arrange in an electric field.

What field? There is no field inside the superconductor in the situation we're discussing.

Crunch the numbers.

I have. You clearly have not.
 
Obvious? So a perfect conductor will also give V=0 and R=0 but without the Meissner effect? So, according to you, it is a superconductor without the Meissner effect? So why use the Meissner effect to define superconduction?

No, johan. It is NOT a superconductor without the Miessner effect. Zero resistance without the Meissner effect is perfect conduction. Zero resistance WITH the Meissner effect is superconduction. Superconduction is not the same as perfect conduction. What on earth ever made you think it was, when I explicitly explained that it was not?

Exactly my argument! And the reason why you cannot define superconduction in terms of Ohm's law until you can identify why an equilibrium current can flow through such a material.

Sure I can. Anyone can. There's no problem. Let V go to zero, and you're in equilibrium. And there are MANY ways to achieve that. For example, use a battery, a resistor, and a superconductor all in series. Your circuit is now a standard LR circuit, and equilibrium current is approached exponentially. No problem at all. You have imagined a problem where none exists.

I am not "appealing" to non equilibrium conditions in certain cases but pointing out that according to your model you will not be able to get an equilibrium current as is experimentally found. I only refuse to look at non-equilibrium conditions since we are only discussing equilibrium super currents on this thread.

Indeed: you'll look at non-equilibrium conditions when you think they'll disprove my position, but refuse to look at them when they threaten your position.

When you switch on a current over a resistor you also at first have "non-equilibrium" conditions. Ohm's law only applies when the current reaches a terminal speed owing to the "friction" that Ohm defined as resistance. Thus Ohm's law can only be applied after equilibrium has been reached.

So what? 1) That's not a problem, and 2) we can extend this to non-equilibrium conditions quite easily by using the more general impedence formulation of Ohm's law, where the inductance of the superconductor (remember that? I've mentioned it quite a few times) is not zero, and it handles zero resistance just fine.

It is a mathematical accident that this is so

No, johan, it is not a mathematical accident.

Since we know that in all other materials Ohm's law only applies after the charge-carriers reaches a constant terminal speed when there is a high enough resistance, one must explain how the charge-carriers within a superconductor can reach a constant terminal speed without any friction.

That's easy to explain: the field vanishes. No more field, no acceleration along the direction of motion, and presto! Constant speed. There is no problem here. You're trying (desperately) to invent a problem, but it just doesn't exist.

What you are claiming is that a parachute will work just as well on the moon as it does on earth.

Nope. I'm claiming that a ball will roll at constant velocity in the absence of any friction if the surface is flat.

We are not talking about transient conditions but steady-state equilibrium conditions; for which you claim that the charge-carriers are being accelerated between two points within the material while there is no voltage difference between these points.

Acceleration perpendicular to the direction of motion is not a problem, it doesn't change the speed of the charge carriers, and it doesn't violate equilibrium conditions. I have never claimed that there is ANY acceleration along the direction of motion for a current in equilibrium in a superconductor.

Can you not see that you are talking BS?

I can see that once again you have completely misunderstood what I've been saying. Perhaps you're having trouble with your memory.

Where did I claim that non-equilibrium conditions are not possible?

When you have stated, multiple times, that charge carriers in a superconductor cannot accelerate.

If we have to include them on this thread, this thread will be even longer than you have caused it to become with your endless infantile arguments.
__________________

I tire of your insults, johan. But since you persist in playing that game, I will let you have it your way. This thread is long because you have grown senile. Whatever physics you once may have known, you have since forgotten. You are a dottering old fool, and it is long since past time that you realize that you are no longer capable of doing science. You are not ignored by the scientific community because of some vast conspiracy, or because of universal blindness on the part of active and productive researchers: you are ignored because you're just another internet crank, and insane internet cranks are a dime a dozen.

Does this style of argument really suit you better, johan?
 
comments on post #973 by sol invictus

The idea that scientists are scared of disproving a theory because it's established isn't just wrong, it's exactly the opposite of the truth.
You are obviously living in cloud cuckoo land: If you have published ever anything at all (which I doubt) you must have very carefully toed the line not to upset the "cardinals" in charge of main stream dogma. I am sure that if Einstein today tried to publish his theory of relativity for the first time, he would have remained a second grade patent clerk.
Any scientist that overturns a well-established theory becomes very famous. Researchers both young and old dream of an opportunity like that.
I can assure you that when such a dream comes true it immediately turns in the worst nightmare possible. This one can see from the few examples that did succeed notwithstanding the bigotry of the main stream cardinals (better to call them criminals): Take Tectonic Plate Theory, Mandelbrot's mathematics, etc. etc. etc.

I shudder to think of the cases which did not succeed; or where people committed suicide like poor old Boltzmann.
The trouble is, a well-established theory is nearly always correct - because if not, one of the myriad of scientists attempting to overturn it would have already succeeded.
If you believe this BS you should not be doing science at all. To judge new science in this manner is to throw out the baby with the bathwater. The latter has become the rule over the past 100 years. This is why I claimed above that Einstein would have had no chance to publish his theory of relativity at present: It is because of people like you that think it is a virtue to defend established theory, instead of evaluating new theory on merit. If only we could clean physics from this curse! Please, in the interest of mankind, become a street sweeper: You are more fit to do the latter. Did you not bid me goodbye in an earlier post? You cannot even keep a promise.
In the case at hand, the problem is that Johan's evidence doesn't show what he claims it does, and Johan's "theory" of superconductivity is gibberish.
And when I challenge other people to do simple experiments to prove that it is "gibberish" or not "gibberish" they refuse. And when I point out that Cooper Pairs cannot have charge, I am ignored even though the model itself is totally commensurate with this being the case. An when I point out that charge-carriers which can be accelerated cannot convey a supercurrent since the voltage over such a material will never drop to zero, I am insulted and denigrated.
 
Comments on post #974 by TjW

Well, I couldn't comment about "too scared", but since energy conservation is so fundamental, and your explanation appears to violate that, I could understand why a researcher might not be interested.
It does not violate energy conservation and I proposed simple experiments in posts #964, 987, and 999, to easily prove that energy is not violated
It may be that it doesn't violate energy conservation. But if it doesn't, and you would like other researchers to look at it, you need to come up with a presentation using standard definitions of terms that shows why it's not violating energy conservation.
Standard definitions based on normal conduction? Then I will be just as incompetent as Sol, Ben and Ziggurat. We are not dealing with normal conduction here and thus need to settle the issues by experiment: And I have proposed these experiments.
Or if it does violate energy conservation, go ahead and admit it,
I can assure you that in contrast to Sol, Ben and Ziggurat I will admit it when I am wrong; as I did in the beginning of this thread when I realized that my initial explanation was wrong.
If you can come up with a method of presenting your findings that, for example, Sol would accept as not violating energy conservation,
Sol is incapable to understand anything that does not fit in with the dogma he wants to believe. He is not able, and never will be able, to see the mountains on the moon.
then you would have a much better chance of getting other researchers to replicate your findings. Not because the phenomena has changed, but because the presentation will be understandable to them.
If they are incapable of understanding a presentation based on new experimental evidence it is up to them to do the necessary experiments. If you only repeat experiments because you understand what a person told you, you are not worth to be called a physicist.
 
Comment on post #975 by Ben m

I agree that it's a silly circuit. Ordinary E&M tells you that the switch is unimportant. However, your theory ("polarized superconductors have totally different energetics than polarized conductors") predicts that the switch is important.
Only in the mind of a demented person!
 
Comments on post 977 by Ben m

That's the opposite of what you said in post 106.
You seemed to be saying that your area is tiny and that it doesn't superconduct in the x-y plane.
I was discussing my initial experiment which does not have conduction in the xy-direction. It is not a traditional superconducting phase. That was ten years ago. Since then I discovered the mechanism responsible for traditional superconduction.
If your superconducting phase superconducts in such a way that you can fabricate circuits within it, you could induce a persistent ring current in it. But when I suggested this before I got a volley of insults.
. This is not possible for the phase that I extracted from an n-type diamond; and is still not possible for such a phase. My present materials are under development and proprietary. Nonetheless I can think of applications for my first phase in the micro-electronics industry.
 
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I can assure you that in contrast to Sol, Ben and Ziggurat I will admit it when I am wrong; as I did in the beginning of this thread when I realized that my initial explanation was wrong.

You will indeed admit being wrong when you realize you are wrong. The problem is that you don't realize you're wrong, even when you're wrong on the most basic, fundamental issues.

And I have admitted I was wrong when I made a mistake early in the thread, which makes this accusation against me a lie.

Sol is incapable to understand anything that does not fit in with the dogma he wants to believe.

No, johan. He just happens to be right, and you happen to be wrong.
 
Comments on post #979 by Ben m

Um. If there are moving charge carriers that are not scattering, there is no work being done on them, and they are doing no work.
If they are being accelerated as you claim they are, then work is done on them since potential energy is converted into kinetic energy.
By the definition of voltage, dV = dW/q, if the work is zero then the voltage change is zero.
This does not give a physics-reason why no work is being done solely because there is an absence of scattering. According to your reasoning here, it means that Newton's second law only applies when there is scattering!
If you're talking about the initial acceleration---"the charge carrier has to accelerate to get out of the non-ideal contact and into the ideal conductor"---this can take one of several forms that we can discuss later.
Why later? This is the crux of the matter! You are in effect claiming that there is a "cannon" below the injection contact within the superconductor; which then "fires off" the charge-carriers so that they can afterwards move with a constant speed to the next contact. So you are claiming that only within this limited region below the injection contact of the superconductor you have a voltage which then disappears as if by magic over the rest of the material. Even if this magic were physically possible, you will still measure this voltage over the contacts to the superconductor. Furthermore, the resultant kinetic energy will still dissipate when the charge-carriers enter the end-contact, so that conduction without entropy generation does not occur at all.

But yes, the arbitrary length of wire between the contacts? With zero scattering of charge carriers in the wire? Yes, there is nothing the carriers can do work on, and nothing that can do work on the carriers,
If there is nothing that can do work on the charge-carriers, how do they attain a drift speed that is orders of magnitude larger than in the rest of the circuit?
carriers move at a constant speed (not velocity)
In which direction is this non-constant velocity when the charge-carriers move between two contacts?
the whole time, so the voltage drop along that wire is zero.
Again if there is no voltage anywhere between the contacts by what mechanism does the charge-carriers achieve their constant drift speed? This cannot be explained by the BCS model.
 
Comments on post #980 by W. D. Clinger

Since I would like us primarily stick to the issue of modelling superconduction, I at first decided to ignore this post: A full discussion of these issues will require a new thread. However, after reading it I decided to post a few short remarks.
If you've been following this thread, you already know that Dr Prins rejects a great deal of the accepted physical theory that is taught to undergraduates.
I do not reject physical theory but the Copenhagen interpretation and what follows from it. In this I am not being controversial since Einstein, Schroedinger, and eventually de Broglie questioned this interpretation right up to their deaths. David Bohm also proposed an alternative interpretation.
In particular, Dr Prins rejects a key principle of quantum mechanics: the Born rule, ......
Dr Prins's rejection of the Born rule has been seen in several previous posts, but it's fairly explicit in the post quoted below. For more on Dr Prins's interpretation of quantum mechanics, see
Johan F Prins. Causality and relativity in quantum physics. Unpublished, 24 July 2006. http://arxiv.org/abs/physics/0607209
​
Quite correct: I reject the interpretation that the intensity of a photon-wave (or an electron-wave) is an inbuilt probability in Nature which on its own describes the probable outcomes that can become a reality when making a measurement. I do not reject the fact that there are probabilities involved, but these probabilities are "normal" just like the probability that a diffusing atom can jump from one position to another within a crystal. To explain my reasoning, let us consider what really happens when one measures the positions of an ensemble of identical photon-waves that impinges into a measuring apparatus.

Assume that the apparatus is a single atom. We know from numerous experiments that the photon will only be detected by the atom when there is resonance between the incoming photon and the atom. If there is no resonance the photon will not be detected. This means that even if one first allow the atom to de-excite before sending in the next photon, the next photon might not be detected. But every photon that is detected is only detected at the same position: i.e. that of the atom. What the outcome is when the wave collapses is thus not a probability distribution that is solely determined by the intensity of the wave; but by whether resonance is achieved or not.

Next consider a screen which contains zillions of atoms. When a photon wave now impinges it has very little chance not to resonate with one of these atoms. It will thus collapse to be absorbed at the position of the first atom it resonates with. There is now no need to only collapse at a single point so that consecutive photon waves will collapse all over the screen. One can visualize the atoms as radio receivers each having a little boy fiddling with the tuning knob. As soon as the incoming wave resonates with one of these receivers it collapses at that point on the screen. We all know that the radio will respond better where the intensity of a wave is highest. Thus the probability for collapse will be higher where the intensity of the incoming photon wave is higher. Thus after many identical photons have been measured, the spots will form a picture of the intensity of the incoming wavefronts. NOT because the wave's intensity is inherently a probability distribution in Nature; but because of the same reason that you have different probabilities for outcomes when gambling in a casino.
I'm partial to this simple photon polarization experiment, described at Professor (Emeritus) Frank Rioux's web site:
http://www.users.csbsju.edu/~frioux/polarize/POLAR-sup.pdf
The result is straightforward when you assume that a photon is a light wave rather than a "particle" which it is not.
If you're looking for an early, influential experiment, I'd suggest the Stern-Gerlach experiment. Our resident physicists can suggest many others.
It is possible to give a causal model for the alignment of an electron's spin. A free electron has energy (1/2)*(hbar)*(omega): i.e the energy of a harmonic oscillator with one degree of freedom. When solving for such an oscillator in the presence of a magnetic field, its energy beciomes a function of the angle (theta) to the axis of the magnetic field. When (theta) is 90o the energy is at its maximum. When (theta) is zero or 180o the energy is the same minimum value. So once again, the probability of an electron to flip spin-up or spin-down has nothing to to with an inbuilt probability in Nature.
Did you look at Wikipedia's example, as ben m suggested?
Why should I. I know the derivation well and has taught it for many many years to my students.
It's both. The "measuring apparatus" determines the observable, which is a special kind of linear operator on a Hilbert space. That operator's eigenvalues are the possible outcomes of the measurement. Independent The probabilities are determined by expressing the wave function in that operator's eigenvector basis.
So this is totally determined by John von Neumann's mathematics and not by the physics; like, for example, the properties of the measuring apparatus. I know that you are spouting the standard dogma: But it is obviously physics-nonsense.
As ziggurat said above, the Born rule is a key piece of standard quantum mechanics.

That's a fact. Stating that fact is not arrogance.
All experiments that I have come across which supposedly proves the Born rule can be explained in terms of the well known properties of waves when they interact causally. They change shape and size when the boundary conditions change; and if the boundary conditions are such that they can resonate at different points, an ensemble of waves will statistically collapse at the different points, just like you get different outcomes in a casino: Not because of the Born rule.
l=http://en.wikipedia.org/wiki/Dirac_equation]Dirac equation[/url] is a relativistic generalization of the Schrödinger equation.
That is what they say but I do not believe that it is so.
The Schrödinger equation works fine in non-relativistic situations,
Because the rest mass is used as input which should not be done under relativistic conditions.
but Dr Prins appears to be rejecting Schrödinger's equation even within its domain of applicability.
A blatant lie!
If so, that's another example of Dr Prins rejecting a key piece of standard quantum mechanics.
The Schroedinger equation is an excellent approximation when calculating bound energy states for electrons that end up having energies not far below the rest mass energy of the electron. I suspect that it can be made compatible with relativistic conditions by not using the rest mass as input. Dirac's equation has nothing to do with a single electron; and should thus be ignored as irrelevant If you solve an equation for a single electron and find that you have to invoke an infinite sea of electrons to make sense of your solution, you are definitely not doing physics but abstract mathematics.
 
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Comments on post #981 by Ziggurat

As usual a long rambling post by Ziggurat based mainly on the words "nope" and "you're wrong". I again refer him to the experiments that I have proposed in posts #964, 987 and 999. PLEASE base your arguments on experimental results! I will thus ignore most of the nonsense arguments:
Originally Posted by johanfprins
Why and how is it cancelled?
By the motion of charges, which are pushed by the field towards a configuration which cancels it. That's basic electromagnetism. Why do I even need to explain that?
Not possible while free charge-carriers constitute a current through the material; as is the case for BCS.
"The intensity of a wave at a point is its energy at that point"

No it isn't.
So the intensity of an electromagnetic wave is not determined by its electric-and magnetic energy?
It's proportional to the energy density at that point,
You are just fooling around with the fact that the solution of any wave equation requires "normalization" ; but guess what after normalization the intensity of an EM wave at a point must be its energy at that point: Nothing else makes sense!
but guess what? The probability density is ALSO linearly proportional to the energy density.
No it is not: The probability density must be unity for all the electron-waves after integrating over their intensities, while different electron waves can have different energies.
"The solution for a free electron unbound state is a time-independent wave that fills an infinite 3D space".

That is a solution. And an un-normalized solution at that. Normalized solutions are not time-independent
So the wave-solution for an electron within its own inertial reference frame is not time independent? What does Ehrenfest say about it? No potential gradient but the wave is not a stationary wave? Wow!
(because they aren't energy eigenstates) and they do not need to fill all of space.
Why are they not energy eigenstates when the potential energy does not change with time or position?
Quote:
What the hell are you talking about? If you're trying to work out diffraction using Ehrenfest's theorem, you're taking the wrong approach. I suspect that you aren't, that you're just blindly applying the word in the hopes that it'll somehow dispel my argument, but it won't.
If you have an electron passing you with a momentum how do you calculate this momentum from Schroedinger's equation?
And yes, wavelength is reference-frame dependent. But guess what: so is the velocity of your apparatus, and the motion of a two-slit interferometer (for example) affects the diffraction as well.
If you knew a bit of relativity theory you would know that it is dangerous not to use relative velocities and therefore there is only a single relative momentum involved when an electron diffracts from a diffraction apparatus relative to which it is moving.
So what's your point? Are you still trying to argue that Ehrenfest's theorem is wrong?
I have never argued this anywhere at any time.
"Mass of what?"

Of the oscillator, obviously.
The mass you use as input to calculate the energy of the oscillator or the energy which is less than this rest mass? I am not asking about the input mass; and would not be surprised if you were not so dumb as you pretend to be on this issue
 
Comments on post #989 by sol invictus

Originally Posted by johanfprins
"OK I will bet you that a single battery on its own cannot maintain a superconducting current through a Josephson junction and a voltgae VJ over the junction."

That's not what you said before. Before, you said:

Originally Posted by johanfprins
"A battery on its own cannot even generate a voltage V over a Josephson junction. When applying only a battery, the voltage over a Josephson junction is ZERO."
It is exactly the same since we have all along discussed voltages during superconduction through a Josephson junction NOT when superconduction is not occurring. You see, this is the problem with especially you and Ziggurat; you play at semantics in order to make cheap shots.
But in any case, you're still wrong. The battery will generate both a voltage and a current.
This is another cheap shot by you. Obviously any battery supplies a voltage and a current and that is not what the argument is about. The argument is whether a single battery in series with a resistor and an SIS will cause a voltage over the Josephson junction while superconduction occurs through the SIS. So this is the issue and I expect that you should first admit that your sentence: "The battery will generate a voltage and a current" is deliberately misleading.
 

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