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Suddenly, A Flat Earther Appears!

:boggled: So.... "If you fired a gun horizontally, how far would the shell drop in 80 seconds?"

So you're saying (LOL, btw) that if I fired a...

9mm: Muzzle Velocity ~ 400 meters/second AND a...

.223: Muzzle Velocity ~ 1000 meters/second...

They would drop EQUALLY over a given distance ?? :boggled:

And then...you call this "Classic", eh?


Take the next 3 days off...then quit :thumbsup:


oy vey

Do you see the two highlighted words above? Do you see your mistake? Is a second a measure of distance, or something else?

This is why you fail at physics.
 
Show us your maths then.
Even my kids could do this one.

Come on.


Show you the maths, eh? I showed the simple "maths" for fairytale gravity and people fumbled, bumbled, and stumbled with that.

This is "Conceptual" professor, we're not that much interested in the EXACT cm of drop over a given distance for each weapon, just the Overall IDEA :rolleyes:

Go punch up your 'maths' for the Rail Gun :thumbsup: Have your kids do that one.


regards
 
Show you the maths, eh? I showed the simple "maths" for fairytale gravity and people fumbled, bumbled, and stumbled with that.

Funny you should mention that - it's exactly what I had in mind when I accused you of mathematical incompetence. Shall we take another look at it?
 
This is ludicrous. There is no such place in Shangri-La where " Vacuum " Pressure is = to the Atmospheric Pressure. :rolleyes: It's Orders of Magnitude away from equilibrium @ BEST (SEE: previous post where I listed the "Torrs" with respect to elevation.)

I see you skipped over the posts where It was explained a bit better. All your yammering about pressure misled me a bit. It is not really about pressure, it is a lack of matter that ultimately determines the "edge". The 2nd LoT doesn't apply.

There is no mistake and no assumption...just the 2nd Law of Thermodynamics :thumbsup: which you are in Direct Contradiction of, and...

“If your theory is found to be against the second law of thermodynamics, I can give you no hope; there is nothing for [your theory] but to collapse in the deepest humiliation.”
Arthur S. Eddington, The Nature of the Physical World (1930), p. 74.

How's it feel ?

regards

I feel sad for you.
 
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I was in RECON. Back in those days, it was a Combat Support Company: Recon, Snipers, TOW, and 4.2 "4 Deuce" Mortars.


Now, can you please tell me how you can have a Vacuum attached to a Non-Vacuum and still retain the properties of each in the same system, simultaneously?

If you can't (and btw, you never will) then say goodbye to your World-View, Phlogiston is more tenable.


regards

Define "attached."
 
oh brother. Do you have some semblance of a coherent substantive argument by chance?

regards

Yes, thanks. Take it for granted everyone else got it, but just for you here we go in baby steps again;

I asked how far the projectile would drop in a particular time. You responded by pointing out that projectiles moving at different velocities have different drops over a particular distance.

Your failure to grasp that they exibit the same drop over the samer time means your objection was irrelevant.

Regards
 
Yep, those are not the same statements.


What Statements are not the same...?

You are talking about them dropping equally over the same distance.


Ahhh no, I would never proffer such ludicrousness.


Jack is talking about them dropping equally over the same time (80 seconds).


Professor what are the units of measure for Muzzle Velocity...?

Is it "METERS/SECOND", by chance?

Please post the Muzzle Velocity for any weapon in just Meters....? :boggled:

Please post the Muzzle Velocity for any weapon in just Seconds...? :boggled:

Do Ya kinda see the point yet? :rolleyes:


regards
 
Do Ya kinda see the point yet?
You keep confusing distance in two different axis. That's a problem. Muzzle velocity is in the horizontal, so effects distance in the horizontal. Drop is in the vertical, so is unrelated to muzzle velocity. Do you see that point yet?

They don't really interact, at least not on a practical scale until you get to values that need to account for the earth's curve. Which is why I think the railgun example earlier might have been a poor one. Especially if you define horizontally as "tangential to the horizon."

Though it does sort of illustrate the folly of flat earth. As a tangent to the horizon would be much further out.
 
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Professor what are the units of measure for Muzzle Velocity...?

Is it "METERS/SECOND", by chance?

Please post the Muzzle Velocity for any weapon in just Meters....? :boggled:

Please post the Muzzle Velocity for any weapon in just Seconds...? :boggled:

Do Ya kinda see the point yet? :rolleyes:


regards

No, no, I don't see the point yet, but I am absolutely agog to know what you think the point is. Please do go on. Please explain to us all how the distance a projectile drops below its aiming point in a particular number of seconds depends on its muzzle velocity.

Feel free to check with your old sniper buddies if you want.
 
Ahhh no, I would never proffer such ludicrousness.

Yes you did, a number of us have quoted you writing just such a thing.

Professor what are the units of measure for Muzzle Velocity...?

Is it "METERS/SECOND", by chance?

Please post the Muzzle Velocity for any weapon in just Meters....? :boggled:

Please post the Muzzle Velocity for any weapon in just Seconds...? :boggled:

Do Ya kinda see the point yet? :rolleyes:


regards

And what is the vertical velocity of those bullets when they leave the barrel?
 
Yes, thanks. Take it for granted everyone else got it, but just for you here we go in baby steps again;

I asked how far the projectile would drop in a particular time. You responded by pointing out that projectiles moving at different velocities have different drops over a particular distance.

Your failure to grasp that they exibit the same drop over the samer time means your objection was irrelevant.

Regards


The really scary part is that you actually posted this.

everyone else got it


Those 'everyone else' also adhere to:

1. Air is attached to the Earth and spins with it. :rolleyes:
2. Can't discern basic High Pressure to Low Pressure (Entropy) :rolleyes:
3. Can't reconcile Coriolis Effect (Merry-Go-Round, a friend, a ball, playing Catch) :rolleyes:

Among numerous other ground-squirrel reasoning atrocities. I would be careful hitching my wagon to that train for justification.


regards
 
So Daniel, let's just recap a second.

Do you now accept that if you were to fire a gun horizontally on a perfectly flat plain and at precisely the same time drop a bullet from the same height as the muzzle, that both of the bullets would hit the ground at exactly the same time?

That's a simple yes/ no question.
 
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No, no, I don't see the point yet


That's quite obvious.


Please do go on. Please explain to us all how the distance a projectile drops below its aiming point in a particular number of seconds depends on its muzzle velocity.


Sure and next we'll discuss 'step by step' how to make peanut-butter and jelly sandwiches.

You'll forgive me, but I have better things to do with my time.

Unless you can post some semblance of a coherent refutation of:

1. Entropy
2. Coriolis Effect
3. Naval Rail Gun

OR

Proffer any EMPIRICAL Evidence for your Fairytale "Spinning Ball" then this is goodbye.

Have a Nice Day


regards
 
That's quite obvious.





Sure and next we'll discuss 'step by step' how to make peanut-butter and jelly sandwiches.

You'll forgive me, but I have better things to do with my time.

Unless you can post some semblance of a coherent refutation of:

1. Entropy
2. Coriolis Effect
3. Naval Rail Gun

OR

Proffer any EMPIRICAL Evidence for your Fairytale "Spinning Ball" then this is goodbye.

Have a Nice Day


regards

Running away? Again?
 
Giving up then? Maybe it's for the best. You either can't grasp or won't grasp that we have been dealing with your garbled physics claims.

On the rail gun - it rather obviously can shoot over the curvature of the earth, as surely as one of your mortars could shoot over a hill. Your own blank incomprehension of high school physics makes a more detailed explanantion likely futile.

On entropy we have tried to lead you by the hand through the idea that gravity is responsilbe for air pressure diminishing with altitude just as water pressure drops as you ascend from the ocean bed. You do, I think, accept that these pressure drops are real phenomena, yet you seem to cling to the idea that if the pressure gets too low at some altitude all of our air would just be sucked into space. Your lack of grasp of basic physics reassures me this is unlikely to happen.
 
Well I left so as to not support the troll - but continue to read for the 'Daniel's un-intented comedy'

..and thanks for that you certainly provided that indeed!

You'll forgive me, but I have better things to do with my time.

What's better than making a public fool of yourself - repeatedly?

Given Troll 101 says that stamping your feet and saying you're leaving only to come back later is a standard tactic. I suspect he'll be back soon with more DEEP THINKING!!!!

Let the comedy continue to roll
 
:boggled: So.... "If you fired a gun horizontally, how far would the shell drop in 80 seconds?"

So you're saying (LOL, btw) that if I fired a...

9mm: Muzzle Velocity ~ 400 meters/second AND a...

.223: Muzzle Velocity ~ 1000 meters/second...

They would drop EQUALLY over a given distance ?? :boggled:

And then...you call this "Classic", eh?


Take the next 3 days off...then quit :thumbsup:


oy vey

Ahhh no, I would never proffer such ludicrousness.
,,, and yet you did exactly that.





Professor what are the units of measure for Muzzle Velocity...?

Is it "METERS/SECOND", by chance?

Please post the Muzzle Velocity for any weapon in just Meters....? :boggled:

Please post the Muzzle Velocity for any weapon in just Seconds...? :boggled:

Do Ya kinda see the point yet? :rolleyes:


regards
Since there is no force in the horizontal after it leaves the muzzle, with an intial velocity, the horizontal distance is calc'd by d=vt
Since there is a zero starting velocity in the vertical and a force due to gravity giving an acceleration of 9.8 m/s/s the vertical distance is calc'd by
d=0.5at2In 80 seconds both the bullet travelling horizontally at 400 m/s and the bullet travelling horizontally at 1000 m/s will fall vertically 31360 meters. They will have traveled horizontally 32000 and 80000 meters respectively.

Given the dimensions of the Earth, and the fact of fluid drag, perhaps you'd be better at using 0.8 seconds rather than 80.
 
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