HansMustermann
Penultimate Amazing
- Joined
- Mar 2, 2009
- Messages
- 23,741
IIRC, I mentioned right at the event horizon one something like "whether it can withstand the tidal forces at that distance is another question".
Well, you probably know most of this if you even ask the question, but I'm going to take it slow and long winded anyway.
The short answer is that it depends on your size and the size of the black hole. Since what counts for tidal forces in the gradient of the gravity field, and the distance over which you "feel" that gradient.
Essentially the difference between your closest and farthest point is (1/r12 - 1/r22)MG. For objects that are very small compared to the size of the black hole, or for really approximate back-of-the-napkin calculations, we can pretend it's just the gradient times the size of that object.
Well, the gradient is the derivative in respect to r, of r-2, which is an elementary one. It's -2r-3. So the gradient is inversely proportional to the CUBE of the distance from the centre.
So as you've figured out by now, a small black hole would indeed rip you apart, a supermassive one, probably not so much.
Well, let's do some maths. Sagittarius A*, the biggest black hole in the Milky Way, and the one at the centre of it all, is about 12 million km in radius and has a mass of 4.1 million solar masses.
Well, much as I love screwing up the maths myself, there are gravity calculators out there. I'll use a random one, namely this one: https://www.ajdesigner.com/phpgravity/newtons_law_gravity_equation_force.php#ajscroll
at 12,000,000 kilometres, one killo will weigh: 3778966.7737303 N
at 12,000,001 kilometres, one killo will weigh: 3778966.1439025 N
Of course, in free fall what matters is the difference, which is just a little over half a newton over a whole 1000m distance. Or for you imperials, every pound at the far end of our 1km long ship, would effectively pull back on our hull with a force of about an ounce.
But that's actually not respecting action and reaction, from the point of view of our free falling ship. What it would feel is really a half an ounce pull in each direction. That's what each pound of mass at the very tip or end of our ship contributes.
You can integrate over the length and shape of the ship, but really it's not a whole lot. I mean, sure, it could cause some warping and stretching, but I have doubts that it would actually take apart a hull that's built to resist photon torpedoes.
Of course, most black holes you'll meet will probably be under 10 solar masses or so, which would really rip you apart at the event horizon. Other points in between, well, your mileage may vary.
Well, you probably know most of this if you even ask the question, but I'm going to take it slow and long winded anyway.
The short answer is that it depends on your size and the size of the black hole. Since what counts for tidal forces in the gradient of the gravity field, and the distance over which you "feel" that gradient.
Essentially the difference between your closest and farthest point is (1/r12 - 1/r22)MG. For objects that are very small compared to the size of the black hole, or for really approximate back-of-the-napkin calculations, we can pretend it's just the gradient times the size of that object.
Well, the gradient is the derivative in respect to r, of r-2, which is an elementary one. It's -2r-3. So the gradient is inversely proportional to the CUBE of the distance from the centre.
So as you've figured out by now, a small black hole would indeed rip you apart, a supermassive one, probably not so much.
Well, let's do some maths. Sagittarius A*, the biggest black hole in the Milky Way, and the one at the centre of it all, is about 12 million km in radius and has a mass of 4.1 million solar masses.
Well, much as I love screwing up the maths myself, there are gravity calculators out there. I'll use a random one, namely this one: https://www.ajdesigner.com/phpgravity/newtons_law_gravity_equation_force.php#ajscroll
at 12,000,000 kilometres, one killo will weigh: 3778966.7737303 N
at 12,000,001 kilometres, one killo will weigh: 3778966.1439025 N
Of course, in free fall what matters is the difference, which is just a little over half a newton over a whole 1000m distance. Or for you imperials, every pound at the far end of our 1km long ship, would effectively pull back on our hull with a force of about an ounce.
But that's actually not respecting action and reaction, from the point of view of our free falling ship. What it would feel is really a half an ounce pull in each direction. That's what each pound of mass at the very tip or end of our ship contributes.
You can integrate over the length and shape of the ship, but really it's not a whole lot. I mean, sure, it could cause some warping and stretching, but I have doubts that it would actually take apart a hull that's built to resist photon torpedoes.
Of course, most black holes you'll meet will probably be under 10 solar masses or so, which would really rip you apart at the event horizon. Other points in between, well, your mileage may vary.
Last edited: