Originally posted by Suggestologist
Are you familiar with Cantor's notation or not?
I assume you are using the same notation as
MathWorld's web page on ordinal numbers? That page says, for example,<blockquote>In order of increasing size, the ordinal numbers are 0, 1, 2, ..., omega, omega + 1, omega + 2, ..., omega + omega, omega + omega + 1, .... .</blockquote>And the table on that page defines "omega + 1" as the set {0, 1, 2, ..., omega}. Is this basically what you are talking about?
Notice that there is no mention of numbers like omega - 1 or omega - 2, etc.
1,2,3,...,1,2,3 represents a set of omega+3 elements. Do you see the dots in the middle? Is Cantor being silly?
The notation is not silly. However, it is somewhat unclear, and I believe you are misinterpreting it. The dots are not in the middle, exactly. They are attached to the "1, 2, 3" at the beginning, but not to the "1, 2, 3" at the end. Think of<blockquote>1, 2, 3, ..., 1, 2, 3</blockquote>as meaning<blockquote>(1, 2, 3, ...)(1, 2, 3),</blockquote> instead of meaning<blockquote>(1, 2, 3, ...)(..., 1, 2, 3).</blockquote>In other words,<blockquote>1, 2, 3, ..., 1, 2, 3</blockquote>might be the same as<blockquote>1, 2, 3, 4, ..., 1, 2, 3,</blockquote>depending on what the dots stand for, but it definitely is not the same as<blockquote>1, 2, 3, ..., 0, 1, 2, 3.</blockquote>In "1, 2, 3, ..., 1, 2, 3", infinitely many numbers precede the second 1, but no number directly precedes it; while in "1, 2, 3, ..., 0, 1, 2, 3", there is a number that directly precedes it, namely, 0.
In "1, 2, 3, ..., 1, 2, 3", there are infinitely many numbers (namely, the initial 1, 2, 3, ...) that are each a finite distance from the beginning, but only three numbers (namely, the final 1, 2, 3) that are a finite distance from the end; this is also true for "1, 2, 3, 4, ..., 1, 2, 3" because that's just another way to write the same thing. But in "1, 2, 3, ..., 0, 1, 2, 3", there are four numbers (namely, the final 0, 1, 2, 3) that are a finite distance from the end.
If you prefer, we can use a modified version which corresponds to my proposition, as such:
6,7,8,9,10,...,1,2,3,4,5 : In which up to and including the elipses, we have a set of omega MINUS 5 elements, and then we add another 5.
(Here, as above when talking about "a set of omega+3 elements", you seem to be confusing ordinals and cardinals, trying to describe the size of a set using an ordinal instead of a cardinal. The natural numbers, considered as a set, has cardinality aleph<sub>0</sub>; the natural numbers, considered as a well-ordered set, has order type omega. But cardinals and ordinals are not the same sort of thing: the order type of {0, 1, 2, ..., omega} is omega + 1, yet its cardinality is still aleph<sub>0</sub>.)
In any case, there is no cardinal number named "aleph<sub>0</sub> - 5"; removing 5 elements from a set of cardinality aleph<sub>0</sub> results in another set of cardinality aleph<sub>0</sub>. There is, likewise, no ordinal number named "omega - 5"; removing 5 elements from a well-ordered set of order type omega results in another well-ordered set of order type omega.
I still say you are thinking about transfinite ordinals as if they were finite, when the two are in fact rather different.