GregoryUrich
Graduate Poster
- Joined
- May 16, 2007
- Messages
- 1,316
OK, I've now read the paper in question. I'm sorry, Gregory, you are completely wrong.
The main reason is that we have no idea how much energy fireproofing dislodgment actually dissipates. On Page 10 you state the following:
The problem is that you make the assumption, incorrectly, that the KE was distributed over this entire area all at once. It doesn't work like that. Think of the KE as being contained in a wavefront, but this KE is not necessarily consumed. The wave will disspiate due to three factors -- (a) dispersion into larger space, (b) damage to the structure, i.e. inelastic collisions, and (c) turbulence becoming heating. But since the fireproofing is so fragile, it dissipates virtually nothing. The wave can pass over the fireproofing, dislodging it, and continue with negligible dissipation.
This is the same mistake that Kevin Ryan and so many others have made. The fireproofing doesnt expend 10^5 J/m^2. That's the strength of the wave required to shake it loose. It's like saying I can stand in the ocean and stay on my feet if a wave no higher than 1m washes over me -- if I get knocked down, that doesn't mean I absorbed an entire 1m wave. The wave barely notices me whether I fall down or not.
The other problem, again, is in your assumptions regarding ricochets and lift. The flow inside the structure will be completely turbulent. Gravity will have virtually no effect, and "lift" -- actually drag -- can occur up or down with virtually no bias. Again, if you want to see this effect, estimate the Reynolds and Froude numbers of the flow and see what you get.
NIST's approach, again, was to use LS-DYNA. This predicts, to reasonable granularity, what the flow and momentum of individual particles of debris were throughout the structure. NIST also keeps track of dissipation due to heavy furnishings and transfer to the structure. NIST does not add additional dissipation caused by the fireproofing, but to first order, this is correct. Instead, NIST estimated a lower bound for energy per area (should really be impulse, shame on NIST) required to dislodge the fireproofing, and made a hard cutoff -- after the wave falls below this value, no more dislodgment.
It's coarse, but it is valid. NIST can be criticized for not really finding the lower bound, not attempting other types of dislodgment (e.g. hot jet without any debris, sand-blasting, shock, etc.), and so on, but their method is appropriate.
A rather categorical assessment considering that your "blast wave" only blew out a few windows. What energy level is required for that? A tiny over-pressure and a fast moving bolt, so I don't buy your "blast wave".
I think you are missing an important point. NIST didn't show that a certain impulse or pressure would remove SFRM. They showed that impact by hard objects at 60 degrees or less from perpendicular can remove fireproofing. Once the object hits, its energy is spent or the energy will go into continued motion or rebounding. However, the probability is extremely low that the motion will be in a direction which could cause more SFRM damage.
So if the flow was "completely turbulent" as you say, wouldn't the debris vectors be normally distributed in terms divergence from the original trajectory (ignoring collisions for the moment)? Unless completely turbulent means that gravity is somehow turned off, every single debris vector is subject to gravitation giving a general and significant tendency of displacement towards the floor over time. In case you missed it, I have ignored gravity.
I have taken account for that it is equally likely for drag or turbulence to cause divergence both upward and downward. Given the system as a whole, all of the mechanisms I decribe will affect some proportion of the debris in one direction or another.
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