Farsight often fails to read his proof texts.
Clinger: Yes he was, and no it wasn't. And you're defending him? Shame on you. My reference was to the Ray quote, and we were discussing the "uniform gravitational field" here with respect to the principle of equivalence. Not EGR v MGR. And certainly not cosmic strings.
In
the proof text you cited, Peter M Brown quoted Ray to illustrate the difference between EGR and MGR. Furthermore, Brown's third example (the one with a cone-shaped spacetime) was a cosmic string.
ben m said:
In the correct rubber-sheet analogy, you can make a sheet shaped like a cone (there is not "inverted" or "right side up" in the more accurate version of the analogy---your use of the word "inverted" is what clued me into the fact that you're thinking of the misleading kiddie version). In this cone, there is no gravitational force except at a singularity in the center. An object left at rest on the "cone" will not accelerate towards the center. There are no geodesics that orbit the center. You are correct that such a cone has no Riemann curvature, but you're incorrect to say that a cone has a "uniform gravitational field". A conical sheet has the same Newtonian gravitational fields as flat sheet does---none at all.
OK, so what sort of object has a gravitational field like this?
A... ummm... cosmic string.
ben m said:
Or perhaps you meant that the gravitational potential energy is a cone, with constant slope and therefore constant gravitational acceleration? Draw the GR version of that and you'll see that it DOES have Riemann curvature. Go ahead, try it.
If it's a cone, it doesn't. See above where even Clinger had to confess that I was right:
Farsight's wrong about that. Although Brown's cone-shaped spacetime (for the cosmic string) has no Riemann curvature, the spacetime
ben m described here does have Riemann curvature.
Riemann curvature is "the defining feature" of a gravitational field because without it your plot can't get off the flat and level.
Although this may be "the defining feature" of a gravitational field in MGR, this is most definitely not the defining feature of a gravitational field in EGR.
Huh? Vorpal, it's the crux of it. If there's no Riemann curvature you haven't got a gravitational field. Things don't fall down.
Einstein disagreed with
Farsight on this point.
In the proof text cited by
Farsight, Peter M Brown quoted JJ Stachel summarizing Einstein's disagreement with
Farsight:
Stachel said:
...what characterizes the existence of a gravitational field from the empirical standpoint is the non-vanishing of the [components of the affine connection], not the vanishing of the [components of the Riemann tensor].
Peter M Brown quoted Ray as an example of how the modern view (MGR) has made it difficult for some people to understand Einstein's view (EGR):
"It is very important to notice that in a freely falling frame we have not
transformed away the gravitational field since the Riemann tensor
(gravitation ←→ Riemann tensor) will not vanish and we will still measure
relative acceleration ….. The first thing to note about the 1911 version of
the principle of equivalence is that what in 1911 is called a uniform
gravitational field ends up in general relativity not to be a gravitational field
at all – The Riemann tensor is here identically zero. Real gravitational fields
are not uniform since they must fall off as once recedes from gravitating
matter".
And by the way, I take exception to you guys crawling out of the woodwork with smoke and mirrors to make things complicated and attempt to say "Farsight is wrong" when I'm not.
That hasn't happened, at least not recently. Almost everything you've written here has been wrong in some way or another.
In recent days, I found only one opportunity to say you're right about something. I took advantage of that opportunity. You then tried to use my endorsement against
ben m, but you were wrong to do so.
Sorry edd, but cosmic strings are a 40-year old hypothesis with no evidential support.
Why, then, have you been citing Brown's example of a cosmic string (with its cone-shaped spacetime) as your primary proof text?