Jabba
Philosopher
- Joined
- Feb 23, 2012
- Messages
- 5,613
Dave,
- But P(H|E) = P(E|H)P(H)/(P(E|H)P(H)+ P(E|~H)P(~H)), and in our case, H is OOFLam. And P(E|H) is the likelihood (probability?) of your current existence -- given OOFLam.
- Explain?This suggests that you are misusing Bayesian statistics.