abaddon
Penultimate Amazing
- Wouldn't you agree with what I said about the first section was correct?
Will you please stop with this trivial tactic of trying to insert your words into the mouths of others.
- Wouldn't you agree with what I said about the first section was correct?
jt,
- Can't we do the same thing with something that just occurs, that we didn't plan an experiment for?
Jabba, your questions are not permanent to the fallacy I discussed.
jt,
- Can't we do the same thing with something that just occurs, that we didn't plan an experiment for?
jt,Jabba, your questions are not permanent to the fallacy I discussed.
- So far, I'm claiming that once we have a reasonably possible alternative hypothesis that favors my current existence (an hypothesis that would provide a better likelihood of my current existence)...
Jabba, your existence cannot be more likely under a hypothesis under which it requires A plus B than it is under a hypothesis under which it only requires one of them.
jt,
- That would seem to imply that the answer to my question is "yes."
ORLY?- It seems to me that there are only 5 issues here.
No.1. Does the formula I provide actually apply to the situation I'm trying to apply it to?
No.2., 3., 4., & 5. Are my estimates for the 4 variables reasonable/appropriate?
No.- So far, the only issue that I find worrisome is #2 -- Is my estimate for P(E|H) appropriate?
Wow. You admit that you are making all of it up.- The claim that worries me is actually two-fold:
But you cannot demonstrate that.2.1. In order for the estimate I provide to be appropriate, I need to be a special case, and
2.2. I'm not a special case.
unevidenced claim.- My claim so far is that I don't need to be a special case, but I am.
Which claim proves that you do not exist at all.- So far, I'm claiming that once we have a reasonably possible alternative hypothesis that favors my current existence (an hypothesis that would provide a better likelihood of my current existence), the likelihood of my current existence is an appropriate entry for P(E|H) -- as is the current existence of each of us who do currently exist...
Oh good. From my perspective, you do not exist. Therefore what?- The idea is that each of us who currently exist are more likely to currently exist if P(E|~H) is true, than if P(E|H) is true. And as ToonTown concludes, it's a matter of perspective.
My claim so far is that I don't need to be a special case, but I am.
- So far, I'm claiming that once we have a reasonably possible alternative hypothesis that favors my current existence (an hypothesis that would provide a better likelihood of my current existence), the likelihood of my current existence is an appropriate entry for P(E|H) -- as is the current existence of each of us who do currently exist...
...
- The idea is that each of us who currently exist are more likely to currently exist if P(E|~H) is true, than if P(E|H) is true.
Jabba,
You are keeping in mind that your ~H is not simply an alternate hypothesis, right? It is infinitely many. You don't get to pick which one you like for your probability calculation and ignore all the others.
- It seems to me that there are only 5 issues here.
1. Does the formula I provide actually apply to the situation I'm trying to apply it to?
2., 3., 4., & 5. Are my estimates for the 4 variables reasonable/appropriate?
- So far, the only issue that I find worrisome is #2 -- Is my estimate for P(E|H) appropriate?
- The claim that worries me is actually two-fold:
2.1. In order for the estimate I provide to be appropriate, I need to be a special case, and
2.2. I'm not a special case.
- My claim so far is that I don't need to be a special case, but I am.
- So far, I'm claiming that once we have a reasonably possible alternative hypothesis that favors my current existence (an hypothesis that would provide a better likelihood of my current existence), the likelihood of my current existence is an appropriate entry for P(E|H) -- as is the current existence of each of us who do currently exist...
- The idea is that each of us who currently exist are more likely to currently exist if P(E|~H) is true, than if P(E|H) is true. And as ToonTown concludes, it's a matter of perspective.
Mojo,Jabba, your existence cannot be more likely under a hypothesis under which it requires A plus B than it is under a hypothesis under which it only requires one of them.
Mojo,
- I don't understand your objection.
- I'm at a family reunion, and 'slower' than ever...
- What are A and B?
abaddon,Do not insert yet again, your crap into your interlocuters statements.