Sol & CurtC, you are correct (but you already knew that

). I've just drawn out the tree diagram and convinced myself my previous intuition was wrong.
The difference is the probability Monty opens a particular door in the original problem is conditional in one case on the door the contestant chooses, whereas in the "dumb" Monty version, he (typically) chooses the door to open with equal probability.
Where it gets interesting is if you now say although Monty is ignorant to which door has the car behind, he still alters the probability of opening a particular door based on the door the contestant chooses.
Mmmm, yes.
If you've got to the point in the game where you have chosen a door and Monty has then opened another to reveal a goat, the answer to the question "will switching to the other unopened door improve your chances of getting the car" depends
entirely on Monty's motive in choosing which door to open.
A. "Classic" scenario, where Monty knows where the car is and has deliberately opened a goat door, switching doubles your odds of winning (from 1/3 to 2/3).
B. Alternative possibility, not excluded by the way the puzzle is usually worded, where Monty does not know where the car is (or if he knows, is capable of entirely disregarding this information) and has opened one of the two unchosen doors at random. Switching does not change the probability of getting the car. (Originally 1/3 chance you chose correctely the first time, 1/3 chance the remaining door has the car, and 1/3 chance that Monty might have revealed the car - we are now at the stage where that last possibility has been excluded, and you're left with two equal-probability coices.)
C. "Monty-is-a-bastard" scenario, where he knows you have already chosen the correct door and is only offering you the switch to entice you away from the winning choice. Switching would lose you the car 100% of the time. However, as this is not a strategy (if employed consistently) that would produce a viable game show, it is arguable that it may be discounted.
The inclusion of the last scenario is mainly of importance when considering the possibility that Monty may be running a different scenario every time (which is probably what actually happened in the real show). While scenario C is non-viable if used consistently, it could form part of the mix in this situation.
Scenario C can only be excluded if we know or assume that Monty
always offers a choice. If we can't assume that Monty will always do that, then we can't exclude the possibility that scenario C may be invoked. In that case, the question is unanswerable, because you don't know if you'll improve your chances (scenario A), leave them unchanged (scenario B) or destroy them completely (scenario C).
If, however, we can assume, deduce or stipulate that Monty will always offer a choice, then scenario C can be excluded. In that case, even if we don't know whether scenario A or scenario B is in operation, then the answer is clear. Since switching cannot
reduce your chances of winning, and
may improve them (if A is the game in town), then switch anyway.
Rolfe.