StevenLeonCooper
Thinker
- Joined
- Jan 6, 2014
- Messages
- 133
The easiest way of explaining the monty hall problem to people who have trouble understanding is to use a million doors instead of 3. I find that people grasp it better when you can say "If you picked the right door at the beginning, you win if you stay with the door you chose. When you chose a door, you had a 1 in a million chance of being right..."
Something about it seems to make it click in people's heads
edit: Fener has already mentioned this.
That's the part about this that goes over my head and gave me troubles trying to explain it to other people.
Let's say you didn't pick ANY door from the million and he opened all but 2, then you got to choose. That would be 50/50 since you're only choosing between 2 doors. If the premise of the riddle is that he always opens "Goat" doors until you are left with only 2 doors, doesn't it seem inconsequential as to whether or not you had a 1/1,000,000 chance to get it right the first time? By the rules of the riddle you will always have a 50/50 chance because he will always get rid of every wrong option except for one and ... oh crap I think I get it now.
He will always get rid of every wrong option except for one and that means that staying with your door means that you happened to get that 1/1,000,000 chance at the very beginning and he opened all the wrong doors except one and your selected door. It's far more likely that you chose a wrong door and he opened all of the wrong doors except for your wrongly-chosen door and the correct door ... wow that analogy really does help.
So the crux of the riddle is the fact that the host will always open all wrong doors except one, meaning you are always left with a wrong and right door and it's more likely that you chose incorrectly to begin with and he was merely forced make your chosen door the single unopened wrong door.